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Rotation. The axis is not translating. We are not yet considering rolling motion. Not fluids,. Every point is constrained and fixed relative to all others. Every point of body moves in a circle. n FIXED. Rotation of a body about an axis. RIGID. Y.
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The axis is not translating. We are not yet considering rolling motion Not fluids,. Every point is constrained and fixed relative to all others Every point of body moves in a circle nFIXED Rotation of a body about an axis RIGID
Y reference line fixed in body q2 q1 X Rotation axis (Z) The orientation of the rigid body is defined by q. (For linear motion position is defined by displacementr.)
The unit of is radian (rad) There are 2 radian in a circle 2 radian = 3600 1 radian = 57.30
Example 1 The accuracy of the guidance system of the Hubble Space Telescope is such that if the telescope were sitting in New York, the guidance system could aim at a dime placed on top of the Washington Monument, at a distance of 320 km. The width of a dime is 1.8 cm. What angle does the dime subtend when seen from New York? = 3.2 x 10-6 degree
Y q2 q1 X Rotation axis (Z) Angular Velocity At time t2 At time t1 w is a vector
Frequency, , is the number of revolutions per second Period, T , is the time per revolution
= 2.50 rev = 15.7 radians/s The rotational frequency of machinery is often expressed in revolutions per minute, or rpm. A typical ceiling fan on medium rotates 150 rpm. What is the frequency of revolution? What is the angular velocity? What is the period of motion? = 0.400 s
Angular velocity w wis a vector wis rate of change of q units of w…rad s-1 wis the rotational analogue of v
Angular Acceleration Dw w1 w2 a a is a vector direction of change in w. Units of a-- rad s-2 ais the analogue of a
• = -1 – 0.6t + .25 t2 e.g at t = 0 = -1 rad = d/dt = - .6 + .5t e.g. at t=0 = -0.6 rad s-1
0= 33¹/³ RPM An example where is constant =3.49 rad s-2 = 8.7 s = -0.4 rad s-2 How long to come to rest? How many revolutions does it take? = 45.5 rad = 45.5/27.24 rev.
Relating Linear and Angular variables s q r q and s Need to relate the linear motion of a point in the rotating body with the angular variables s = qr
s w v r Relating Linear and Angular variables w and v s = qr Not quite true. V, r, and w are all vectors. Although magnitude of v = wr. The true relation isv = wx r
v = x r w r v
a r Since w = v/r this term = v2/r(or w2r) This term is the tangential acceleration atan. (or the rate of increase of v) Relating Linear and Angular variables a and a The centripetal acceleration of circular motion. Direction to center
Relating Linear and Angular variables a and a a Central acceleration r Tangential acceleration (how fast V is changing) Thus the magnitude of “a” a = ar - v2/r Total linear acceleration a
Rotational Kinetic Energy • An object rotating about z axis with an angular speed, ω, has rotational kinetic energy • Each particle has a kinetic energy of • Ki = ½ mivi2 • Since the tangential velocity depends on the distance, r, from the axis of rotation, we can substitute • vi = wri
The total rotational kinetic energy of the rigid object is the sum of the energies of all its particles • Where I is called the moment of inertia
There is an analogy between the kinetic energies associated with linear motion • (K = ½ mv 2) • and the kinetic energy associated with rotational motion • (KR= ½ Iw2) • Rotational kinetic energy is not a new type of energy, the form is different because it is applied to a rotating object • Units of rotational kinetic energy are Joules (J)
Moment of Inertia of Point Mass • For a single particle, the definition of moment of inertia is • m is the mass of the single particle • r is the rotational radius • SI units of moment of inertia are kg.m2 • Moment of inertia and mass of an object are different quantities • It depends on both the quantity of matter and its distribution (through the r2 term)
For a composite particle, the definition of moment of inertia is • mi is the mass of the ith single particle • ri is the rotational radius of ith particle • SI units of moment of inertia are kg.m2 • Consider an unusual baton made up of four sphere fastened to the ends of very light rods • Find I about an axis perpendicular to the page and passing through the point O where the rods cross
Moment of Inertia of Extended Objects • Divided the extended objects into many small volume elements, each of mass Dmi • We can rewrite the expression for Iin terms of Dm • With the small volume segment assumption, • If r is constant, the integral can be evaluated with known geometry, otherwise its variation with position must be known
Moment of Inertia of a Uniform Rigid Rod • The shaded area has a mass • dm = l dx • Then the moment of inertia is
Parallel-Axis Theorem • In the previous examples, the axis of rotation coincided with the axis of symmetry of the object • For an arbitrary axis, the parallel-axis theorem often simplifies calculations • The theorem states • I = ICM + MD 2 • I is about any axis parallel to the axis through the center of mass of the object • ICM is about the axis through the center of mass • D is the distance from the center of mass axis to the arbitrary axis