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Learn how to solve literal equations by taking an equation with multiple variables and solving for one variable in particular. This guide provides examples and step-by-step instructions for solving various literal equations.
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TRANSFORMING FORMULA • VARIABLES ON BOTH SIDES
LITERAL EQUATION "solving literal equations" is another way of saying, "taking an equation with lots of letters, and solving for one letter in particular."
Examples of LITERAL EQUATIONS d= rt d=distance r=rate t=time A= ½(bh) A=area of a triangle b=base h=height P= 2w + 2l P=perimeter w=width l=length
d= t r d= t r r t t t t =d r r =d t Solving Literal Equations Solve for r Solve for t d= rt d=distance r=rate t=time d= rt d= rt
2A = b b = 2A h h h h A= ½(bh) A=area of a triangle b=base h=height Solve for b A = ½ (bh) (2) A = ½ (bh) (2) 2A = (bh)
h = 2A b YOUR TURN! Solve for h A= ½(bh) A=area of a triangle b=base h=height
2 2 P -2w = l 2 Solve for l P= 2w + 2l P=perimeter w=width l=length P = 2w + 2l -2w -2w P -2w = 2l
4 t= 3m-e d=(b-6k) Solve the following literal equations and write each step made b = 6k + 4d Solve for d m = ⅓ (t + e) Solve for t
a= x - s 4 4 t= 3m-e s= x - 4a w=h - ⅓k k=3(h+w) d=(b-6k) Homework X = 4a + s Solve for a m = ⅓ (t + e) Solve for t X = 4a + s Solve for s b = 6k + 4d Solve for d h = ⅓k - w Solve for k h = ⅓k - w Solve for w