Photo Jigsaw 2 x 2

Jul 31, 2014

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Photo Jigsaw 2 x 2. Photo Jigsaw 3 x 3. Photo Jigsaw 4 x 3.

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Photo Jigsaw 2 x 2

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Photo Jigsaw2 x 2
Photo Jigsaw3 x 3
Photo Jigsaw4 x 3

Photo Editing #2

Photo Editing #2 . Colby Jenson. The Rule of Thirds. This is the before picture. Notice that, when gridlines are added, the picture is perfectly centered. Also, if you’re paying attention to the mirror, you can see me in it!. After.

236 views • 8 slides

Solve log 2 (2 x + 1) – log 2 x = 2

Log tips. When solving, you can often either: Get in the form log a b = c . Then rearrange as a c = b Get in the form log a b = log a c . Then b = c. Actual exam questions:. Solve log 2 (2 x + 1) – log 2 x = 2. log 2 ( x + 1) – log 2 x = log 2 7.

1.16k views • 28 slides

Photo Album 2

Photo Album 2. by Your Name.

153 views • 7 slides

f(x) = x 3 + 2x +3 g(x) = 2 x + x 2 + x + 4 h(x) = x 2 + 3x 3 + 2x + 1 t(x) = x -2 + x + 2

Do Now: Do we have a polynomial function? Is it in standard form? What is the degree? What is the leading coeficient ?. f(x) = x 3 + 2x +3 g(x) = 2 x + x 2 + x + 4 h(x) = x 2 + 3x 3 + 2x + 1 t(x) = x -2 + x + 2. Chapter 2.2/ 2. SWBAT Evaluate and Graph Polynomial Functions

328 views • 17 slides

Photo Album 2

Photo Album 2. by Friends of Berry Hill.

214 views • 14 slides

(X+Y) 2 =X 2 + Y 2 + 2 XY E (X+Y) 2 = E X 2 + E Y 2 + 2 E XY

Lecture 4 Rescaling, Sum and difference of random variables: simple algebra for mean and standard deviation. (X+Y) 2 =X 2 + Y 2 + 2 XY E (X+Y) 2 = E X 2 + E Y 2 + 2 E XY Var (X+Y) = Var (X) + Var (Y) if independence Demonstrate with Box model (computer simulation)

379 views • 10 slides

n S x 2 – ( S x ) 2

Note: All the K i values stored in K i database and used to calculate this graph are expressed in nM. Outliers are defined as any value that is more than 2 standard deviations greater than or less than the mean.

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4( x 2 – 2 x + ? ) + y 2 = 8 + 4( ? )

Note that A = 4, B = 0, and C = 1 , so the value of the discriminant is:. B 2 – 4 AC = 0 2 – 4(4)(1) = –16. Because B 2 – 4 AC < 0 and A = C, the conic is an ellipse. To graph the ellipse, first complete the square in x. EXAMPLE 6. Classify a conic.

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=x 2 +5 x +6 =x 2 -3 x -4 =x 2 -11 x + 30

活动与探索： ① ( x +2)( x +3) ②( x -4)( x +1) ③ ( x -5)( x -6) ( x + p )( x + q ). =x 2 +5 x +6 =x 2 -3 x -4 =x 2 -11 x + 30. =x 2 +( p + q ) x + pq. 利用你发现的规律口答： ① ( y +4 )( y -2 ) ②( y -5 )( y -3 ) ③( a -2 )( a +5 ) ④( a +9 )( a -9 ). 口答 : (1)(P+1) 2 ＝ (P+1)(P+1 )= . (2)(m+2) 2 = .

253 views • 13 slides

f(x) = x 2

f(x) = x 2. Let’s review the basic graph of f(x) = x 2. 10. 9. 8. 7. 6. 5. 4. 3. 2. 1. -6. -5. -4. -3. -2. -1. 1. 2. 3. 4. 5. 6. -5. -6. Standard Form. The graphs of quadratic functions are parabolas Standard form. If a > 0, the parabola opens upward

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2 x

# Q =. #U=20. Higher paper 2 Q2 C (ii): Sets. #(PnQ)= x. 2 x + x + 5 x + 4 = 20 8x+4=20 8 x = 16 x = 2 #( Q ) = 12. #(PQ)=2 x. #((PuQ)’)=4. U(20). (3 x ). (6 x). P. Q. 2 x. x. 5 x. 4.

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Warm Up Solve each equation. 1. 2 x + 3 = 2 x + 4 2. 2( x + 1) = 2 x + 2

Warm Up Solve each equation. 1. 2 x + 3 = 2 x + 4 2. 2( x + 1) = 2 x + 2 3. Solve 2 y – 6 x = 10 for y. no solution. infinitely many solutions. y = 3 x + 5. Solve by using any method. y = 3 x + 2. x – y = 8. 5. 4. (6, –2). (1, 5). 2 x + y = 7. x + y = 4.

181 views • 16 slides

x 2 + y 2

13. Locus and Equations of Circles. (a) How do we identify the equations of circles?. (i) The coefficients of x 2 and y 2 must be the same ; (ii) No xy -terms; (iii) The degree is 2. x 2 + y 2. x 2 + y 2. x 2 + y 2 + Dx+Ey+F = 0. General Form x 2 + y 2 + Dx+Ey+F = 0.

188 views • 13 slides

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