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Topic: Gas Laws. A gas particle spreads apart, filling all the space available. A gas does not have a definite shape of volume. When working with gases there is a relationship between the gas’s: * volume * temperature * pressure.
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A gas particle spreads apart, filling all the space available. A gas does not have a definite shape of volume.
When working with gases there is a relationship between the gas’s:* volume* temperature* pressure.
Pressure = is due to the collision of gas particles with one another and the walls of the container.
Calculating Pressure P = Force / AreaPressure (P) is measured in Pascals (Pa) or kilo- Pascals (kPa).Force (F) is measured in Newtons (N).Area (A) is measured in m2.P = Force / Area
Calculating Pressure PracticeA machine applies a force of 252 N on a piston having an area of 0.430 m2. Calculate the pressure.
A trash compactor exerts a force of 5,600 N over an area of 0.342 m2. Calculate the pressure in kPa. You will need to divide the pressure by 1000 to convert to kPa.
Boyle’s Law (Pressure)- When the pressure of a gas at constant temperature is increased, the volume of the gas decreases. When pressure is decreased the volume increases. Pressure = Volume
Charlie’s Law: (Temperature)- When the temperature of a gas is increased at constant pressure, its volume increases. Temperature = Volume- When the temperature of a gas decreases at constant pressure the volume decreases.Temperature = Volume
P1V1 = P2V2 T1 T2Temperature is measured in K°(Kelvin). 273° K = 0° C = 32° F
The pressure of a gas remains constant at 10 Pa and the temperature changes from 273°K to 283°K. The volume starts at 20 L. What is the volume after this temperature increase?
P1V1= P2V2 T1 T2 (10 Pa) (20 L) = (10 Pa) (? L) 273°K 283°K 0.732 = 0.0353 (?L) 0.732 /0.0353 = (?L) V2 = 20.7 L
The temperature of a gas remains constant at 300 °K and the pressure changes from 5 Pa to 10 Pa. The volume starts at 20 L. What is the volume after this pressure increase?
P1V1= P2V2 T1 T2 (5 Pa)(20 L) = (10 Pa)(? L) 300°K 300°K 0.333 = 0.0333 (?L) 0.333/0.0333 = 10 L