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Phylogenetic trees. Trees. Gorilla. Human. Chimp. Human. Chimp. Gorilla. =. Gorilla. Chimp. Human. =. =. Chimp. Human. Gorilla. Terminology. A branch = An edge. The root. Internal nodes. Chicken. Gorilla. Human. Chimp. External node - leaf. Ingroup / Outgroup:. Chicken.
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Trees Gorilla Human Chimp Human Chimp Gorilla = Gorilla Chimp Human = = Chimp Human Gorilla
Terminology A branch =An edge The root Internal nodes Chicken Gorilla Human Chimp External node - leaf
Ingroup / Outgroup: Chicken Gorilla Human Chimp OUTGROUP INGROUP
The maximum parsimony principle. (The shortest path) Modified from Inferring Phylogenies (Book), Author: Prof. Joe Felsenstein
Evaluate this tree… s2 s1 s4 s3 s5
s2 s1 s4 s3 s5 1
s2 s1 s4 s3 s5 1 0
s2 s1 s4 s3 s5 1 1 0
Gene number 1 s2 s1 s4 s3 s5 1 1 1 0 0
Gene number 1. The most parsimonious ancestral character states 1 0 1 s1 s4 s3 s2 s5 1 1 1 0 0
1 0 Gene number 1, Option number 1. 1 1 s1 s4 s3 s2 s5 1 1 1 0 0
0 1 0 1 1 1 1 0 0 Gene number 1, Option number 2. s1 s4 s3 s2 s5 Minimal number of changes for gene 1 (character 1) = 1
Gene number 2, s2 s1 s4 s3 s5 0 0
0 1 0 1 0 1 1 0 0 Gene number 2, Option number 1. s2 s1 s4 s3 s5
1 1 0 1 0 1 1 0 0 Gene number 2, Option number 2. Gene number 2, Option number 2. s2 s1 s4 s3 s5
0 0 0 0 0 1 1 0 0 Gene number 2, Option number 3. Number of changes for gene 2 (character 2) = 2 s2 s1 s4 s3 s5
Sum of changes = 9 Can we do better?
Sum of changes = 9 Sum of changes = 8 YES WE CAN! The MP (most parsimonious) tree:
The MP (most parsimonious) tree: s2 s1 s4 s3 s5 Sum of changes for this tree topology = 8
Intermediate Summary MP tree = one for which minimal number of changes are needed to explain the data We can now search for the best tree under the MP criterion
Challenges Evaluating big tree “by hand” can be problematic. We want the computer to do it. Going over all the trees? How many trees are there? Can we generalize to nucleotides? To amino acids? Is the parsimony criterion ideal?
s1AAGTAA s2CAAAAC s3CAGGAA s4AAATAC s5GCGCCA
Position number 1 s2 s1 s4 s3 s5 A A C C G
Position number 1 C C Number of changes for position 1 = 2 A C s2 s1 s4 s3 s5 A A C C G
Find the MP score of the tree for these sequences Exercise CAAG GAAA GCGA GACA GGGA Chicken Duck Gorilla Human Chimp
The Fitch algorithm (1971): {A,C} {A,C,G} {A,G} {A,C} C Chicken A Duck C Gorilla A Human Chimp G Postorder tree scan. In each node, if the intersection between the leaves is empty: we apply a union operator. Otherwise, an intersection.
{A,C} {A,C,G} {A,G} {A,C} C Chicken A Duck C Gorilla A Human Chimp G Total number of changes = number of union operators.
Rooting the tree From Wiki commons
H C G C H G G C H A A A A A A A A A Total number of changes = 0 For all 3 possible tree topologies
H C G C H G G C H A A C A A C C A A Total number of changes = 1 For all 3 possible tree topologies
H C G C H G G C H G T A T G A A T G Total number of changes = 2 For all 3 possible tree topologies
H C G C H G G C H Total number of changes is always the same for all 3 possible tree topologies
With 4 taxa Orangutan
O G C H O H C G H C O H O G C O G H C G O G C H O G C H C O H O H G O C G C H G O G C H O G C H C H G O H C G O H G O C
O O H C G H C G G H C O H O C G C G O H
O O H C G H C G 1 O 4 3 G 5 H 2 C H G O C G C O H C G O H
Conclusion The position of the root does not affect the MP score.
Rooting does not change MP score Orangutan G C Gorilla G G Chimp A G Human G G After “bending” the trees, the association of changes and branches does not change! G C A G G
Rooting does not change MP score Orangutan G C Gorilla G C Chimp C G Human C G After “bending” the trees, the association of changes and branches does not change! C C C G G
Using an outgroup Back to solving the relationships between human, chimp and gorilla…
No MP with 3 species 3 1 2 3 1 2
Using an outgroup Back to solving the relationships between human, chimp and gorilla…
Human Human Human Chicken Chimp Chimp Gorilla Chicken Gorilla Chimp Gorilla Chicken With 4 taxa, there are 3 difference unrooted trees.
Human Human Human Chicken Chimp Chimp Gorilla Chicken Gorilla Chimp Gorilla Chicken One tree gets a better score (less changes) than the other trees.