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Active Filters, EQs & Crossovers. Dennis Bohn Rane Corporation. It’s All About the Mathematics. Electronic filters are all about the mathematics. You cannot escape the math. We will study the math; … you will love the math. Simplified Laplace Transforms.
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Active Filters, EQs & Crossovers Dennis Bohn Rane Corporation Rane Corporation
It’s All About the Mathematics Electronic filters are all about the mathematics. You cannot escape the math. We will study the math; … you will love the math. Rane Corporation
Simplified Laplace Transforms • Represents complex (frequency dependent) impedance, i.e., magnitude & phase • Uses the Laplace Operator, s, where s = complex frequency variable = jω = j2πf • Resistor Impedance = R (freq. independent) • Capacitor Reactance = 1/sC • Inductor Reactance = sL • Allows writing a circuit’s transfer function by summing circuit currents using Kirchoff’s Law Rane Corporation
Transfer Functions (TF) • Transfer functions mathematically describe the frequency domain behavior of filters. • TF = ratio of Laplace Transforms of a circuit’s input and output voltages: T(s) = Vout(s) / Vin(s) Filter Vin(s) Vout(s) Rane Corporation
Filter Transfer Functions • General filter transfer function is the ratio of two polynomials: Rane Corporation
TF Poles & Zeros • “Zeros” = values that make numerator equal zero, i.e., the roots of the numerator. • Makes amplitude response rolloff 6 dB/oct. • Shifts phase +90°/zero (+45° @ fc) • “Poles” = values that make denominator equal zero, i.e., the roots of the denominator. • Makes amplitude response rise 6 dB/oct. • Shifts phase –90°/zero (–45° @ fc) Rane Corporation
Audio Filter Order • The order or degree (equivalent terms) is the highest power of s in the transfer function. • For analog circuits usually equals the number of capacitors (or inductors) in the circuit. • 2nd-order most common. • For common audio filters the order equals the rolloff rate divided by 6dB/oct, e.g. 24 dB/oct rolloff = 4th order (24 6 = 4) Rane Corporation
Audio Filter Order (cont.) Rule: 6 dB/oct & 90° per order Examples:1st-order = 6 dB/oct; θ = 90° ( 45° @ fc) 2nd-order = 12 dB/oct; θ = 180° ( 90° @ fc) 3rd-order = 18 dB/oct; θ = 270° (135° @ fc) 4th-order = 24 dB/oct; θ = 360° (180° @ fc) … etc. Rane Corporation
Why 6 dB/octave Slope? The impedance of a capacitor is half with twice the frequency, i.e., XC = 1/sC = 1/2fC The impedance of an inductor is twice when frequency doubles, i.e., XL = sL = 2fL Twice or Half Impedance = 6 dB change Twice or Half Frequency = One Octave change Rane Corporation
Why Phase Shift? • Phase shift is the flip side of time • It takes time to build up a charge on a capacitor -- that’s why you cannot change the voltage on a capacitor instantaneously. • It takes time to build up a magnetic field (flux) in an inductor -- that’s why you cannot change the current through an inductor instantaneously. • All this time = phase shift Rane Corporation
Why 2nd-Order? • Maximum phase shift is 180 degrees • Guarantees circuit is unconditionally stable • No oscillation problems under any conditions • Get higher order circuits by cascading 2nd-order sections … or • Design 4th-order section to mathematically emulate two cascaded 2nd-order (Rane’s L-R) Rane Corporation
Normalized Transfer Function Low-Pass (LP) =(2 poles) Amplitude 2 poles = -12 dB/oct Frequency Rane Corporation
Normalized Transfer Function • Bandpass (BP) =(1 zero, 2 poles) 1 pole = -6 dB/oct 1 pole = -6 dB/oct Amplitude 1 zero = +6 dB/oct Frequency Rane Corporation
Normalized Transfer Function High-Pass (HP) =(2 zeros, 2 poles) 2 poles = -12 dB/oct Amplitude 2 zeros = +12 dB/oct Frequency Rane Corporation
Coefficients Determine Performance • Butterworth: maximally flat passbands2 + 1.414s + 1 • Chebyshev: steeper rolloff w/magnitude rippless2 + 1.43s + 1.51 • Bessel: best step response, but gentle rolloffs2 + 3s + 3 LP = = Rane Corporation
Response Comparison Rane Corporation
Q Effects Butterworth Q = 0.707 Bessel Q = 0.5 Rane Corporation
Group Delay Comparison Rane Corporation
Step Responses Butterworth Bessel Rane Corporation
Active or Passive? • There exists no sound quality attributable to active or passive circuits per se. • TF determines the overshoot, ringing and phase shift regardless of implementation. • A transfer function is a transfer function is a transfer function … no matter how it is implemented -- all produce the same fundamental results as long as the circuit stays linear: same magnitude response, same phase response, same time response; however there are secondary differences. Rane Corporation
Passive Less noise No power supply More reliable Less EMI susceptible Better at RF frequency No oscillations No on/off transients No hard clipping Handles large V & I Active Gain & adjustable No loading effects Parameters adjustable Smaller Cs No inductors Smaller, lighter & cheaper No magnetic coupling High Q circuits easy Active vs. Passive Rane Corporation
Creating An Equalizer Input Signal In Out 1 BP BP Filter fc Rane Corporation
Boost = Original + Bandpass Boost (Lift) 1 + BP Out In + BP 1 fc Rane Corporation
Cut = Reciprocal Out In + Cut (Dip) BP 1 1 1+BP fc Rane Corporation
Why 1/3-Octave Centers? • 1/3-Octave (21/3oct= x1.26) approximately represents the smallest region humans reliably detect change. • Relates to Critical Bands: a range of frequencies where interaction occurs; an auditory filter. • About 1/3-octave wide above 500Hz (latest info says more like ~1/6-oct); 100 Hz below 500 Hz Rane Corporation
Creating A Crossover:Use LP & HP To Split Signal HP1 High Out Input HP2 LP2 Mid Out LP1 Low Out Rane Corporation
1st-Order & Butterworth Crossovers 1st-order plus 2nd through 4th-order Butterworth vector diagrams Rane Corporation
Linkwitz-Riley Crossover • Two Cascaded Butterworth Filters • Outputs Down 6 dB at Crossover Frequency • Both Outputs Always in Phase • No Peaking or Lobing Error at Crossover Frequency Rane Corporation
Creating A LR CrossoverCascaded Butterworth BW-HP BW-HP High Out Input BW-LP BW-LP Low Out Rane Corporation
Linkwitz-Riley Crossovers LR-4 LR-2 LR-8 Rane Corporation
Ray Miller (Rane)Bessel Crossover Rane Corporation
Successfully Crossing-Over • Must know the exact amplitude and phase characteristics of the loudspeakers. • Driver response strongly interacts with active crossover response. • True response = loudspeaker + crossover • DSP multiprocessors à la Drag Net allow custom tailoring the total response. Rane Corporation
Accelerated-Slope Tone Controls Rane Corporation
Stop Kidding Yourself (Rick Chinn Request) Why low-cut and high-cut filters are a must for sound system bandwidth control; or, Why cutting the end sliders on your EQ doesn’t do diddly-squat. Rane Corporation
Digital Very complex filters Full adjustability Precision vs. cost Arbitrary magnitude Total linear phase EMI & magnetic noise immunity Stability (temp & time) Repeatability Analog Speed 10-100x faster Dynamic Range Amplitude: 140 dB e.g., 12 Vrms & 1 V noise Frequency: 8 decades e.g., 0.01 Hz to 1 MHz Cheap, small, low power Precision limited by noise & component tolerances Analog vs. Digital Filters Rane Corporation
Digital Filters and DSP Allow circuit designers to do new things. We can go back and solve old problems ... like the truth-in-slider-position bugaboo of graphic equalizers: • Proportional-Q was good • Constant-Q was better • Perfect-Q is best Rane Corporation
Truth in Slider PositionProportional-Q Rane Corporation
Truth in Slider PositionConstant-Q Rane Corporation
Truth in Slider PositionPerfect-Q Rane Corporation
PERFECT-Q™ & DEQ 60 Rick Jeffs Sr. Design Engineer Rane Corporation
DEQ 60 Graphic 1/3-Oct EQ Rane Corporation
DEQ 60 Features Rane Corporation
DEQ 60 Performance Rane Corporation