1 / 14

Unit 9: Combinations of Functions Review

Unit 9: Combinations of Functions Review. By. Amar Gill & Sagar Mody. P.4 Ms. Rishad. Agenda . 9.2 – Combining Two Functions: Sums and Differences 9.3 – Combining Two Functions: Products 9.4 - Exploring Quotients of Functions 9.5 - Composition Function.

ron
Download Presentation

Unit 9: Combinations of Functions Review

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Unit 9:Combinations of FunctionsReview By. Amar Gill & SagarMody P.4 Ms. Rishad

  2. Agenda 9.2– Combining Two Functions: Sums and Differences 9.3 – Combining Two Functions: Products 9.4 -Exploring Quotients of Functions 9.5 - Composition Function

  3. 9.2 Combining Two Functions: Sums and Differences Key Ideas • When two functions f(x) and g(x) are combined to form the function (f + g)(x), the new function is called the sum of f and g(f + g)(x) = f(x) + g(x) • Similarly, the difference of two functions, f – g, is (f – g)(x) = f(x) – g(x) • The domain of f + g or f – g is the intersection of the domainsof f and g

  4. 9.2 Combining Two Functions: Sums and Differences Example 1: Given f(x) = 3x² + 2 and g(x) = 1/x-4 find: • a) (f + g)(x)= 3x² + 2 + 1/x-4b) (f – g)(x)= 3x² + 2 – 1/x-4c)the domain of (f + g)(x)D=(xeR| x=/ 4)

  5. 9.2 Combining Two Functions: Sums and Differences • d) (f + g)(1) • = (f + g)(x) = 3x ² + 2 + 1/x-4= (f + g)(1) = 3(1)² + 2 + 1/1-4 • = 3+2 + 1/-3 = 5 – 1/3 • = 15 – 1 3= 14/3

  6. 9.3 – Combining Two Functions: Products Key Ideas • When two functions, f(x) and g(x) are combined to form the function, (f x g)(x), the new function is called the product function of f and g To determine the product function, (f x g)(x) • Multiply the values of f(x) by the corresponding y-values of g(x) • (f x g)(x) = f(x) x g(x) • The Domain of (f x g)(x) is the intersection of the domain of f(x) and g(x) • If f(x) = 0 or g(x) = 0, then (f x g)(x) = 0

  7. 9.3 – Combining Two Functions: Products

  8. 9.3 – Combining Two Functions: Products

  9. 9.3 – Combining Two Functions: Products Example 1: Given f(x) = √ x-3 and g(x) = 2x +1 • a) Find (f x g)(x)= f(x) x g(x)= √x-3 (2x +1) • b) Determine (f x g)(12)= √ 12-3 (2(12) + 1) • = 3(25) • =75

  10. 9.3 – Combining Two Functions: Products c) Graph  d) Domain and RangeD = (xeR|x > = 3)R = (yeR| y > = 0)

  11. 9.4 Exploring Quotients of Functions Key Ideas • When two functions, f(x) and g(x) are combined to form the function (f/g)(x) or f(x) / g(x), the new function is called the quotient of f and g. • Algebraically, (f/g)(x) = f(x) / g(x) • If f(x) = 0 when g(x) isn't 0, then (f/g)(x) = 0 • To graph (f/g)(x), use a TOV

  12. 9.4 Exploring Quotients of Functions Example 1: Write the equation of (f/g)(x), graph it, and state the domain F(x) = 5 g(x) = x • (f/g)(x) = 5/x • F(x) D= (xeR) • G(x) D =(xeR) • (f/g)(x) D=(xeR|x=/0) * Reminder* HA is y =a/cex:  f(x)= 4x 2x+1  HA = 2 VA = -1/2

  13. 9.5 Composition Function Composition Function • A function that is the composite of two other functions; the function f(g(t)) is called the composite of f with g; the function f(g(t)) is denoted by (f o g)(t) and is defined by using the output of the function g as the input for the function f. Key Ideas • Two functions, f and g, can be combined using a process called composition, which can be represented by f(g(t)) • The output for the inner function, g, is used as the input for the outer function • The function f(g(t)) can be denoted by (f o g)(x) • In most cases, (f o g)(x) does not equal (g o f)(x) because the order in which the functions are composed matters

  14. 9.5 Composition Function Example 1: If f(x) = 2x+3 and g(x) = x², find the following • A) (f o g)(3) = f(g(3)) = f(9) = 2(9)+3 = 21 b) (f o g)(x) = f(g(x)) = f(x ²) = 2x ²+3 b) (f o f)(x) = f(2x+3) =2(2x+3)+3 = 4x + 6 + 3 = 4x + 9

More Related