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Lecture 9 covers statics fundamentals, moments of force, rigid bodies vs. particles, and vector cross products. Learn to apply calculations in real-world engineering problems.
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Homework #4 • Chapter 3 problems: • 1, 4, 8, 11, 17, 25, 26, 28, 35 & 40 • To be solved using hand calculations • May check work using MathCAD, Matlab, etc. • Due Friday, September 26 Lecture 9
Chapter 3Rigid Bodies; Moments • Consider rigid bodies rather than particles • Necessary to properly model problems • Moment of a force • Problems Lecture 9
F F Rigid Bodies • The point of application of a force is very important in how the object responds • We must represent true geometry in a FBD and apply forces where they act. Lecture 9
B A Transmissibility • A force can be replaced by an equal magnitude force provided it has the same line of action and does not disturb equilibrium Lecture 9
M A O d F Moment • A force acting at a distance is a moment M d is the perpendicular distance from F’s line of action to O Defn. of moment: M = Fd • Transmissibility tells us the moment is the same about O or A Lecture 9
Vector Product; Moment of Force • Define vector cross product • trig definition • component definition • cross product of base vectors • Moment in terms of cross product • Example problems Lecture 9
A x B B q A B q A AxB ^ n = AxB Cross Product The cross product of two vectors results in a vector perpendicular to both. The right-hand rule decides the direction of the vector. A x B = - B x A B x A Lecture 9
- + Base Vector Cross Product Base vector cross products give us a means for evaluating the cross product in components. Here is how to remember all of this: Lecture 9
General Component Cross Product Consider the cross product of two vectors ˆ - AzBy i Or, matrix determinate gives a convenient calculation Lecture 9
+ - (AyBz-AzBy) i - (AxBz-AzBx) j = + (AxBy-AyBx)k Lecture 9
Problems A = 5i + 3j B = 3i + 6j Find • A·B • The angle between A and B • AxB • BxA Lecture 9