1 / 5

Today’s agenda: Magnetic Fields Due To A Moving Charged Particle.

Today’s agenda: Magnetic Fields Due To A Moving Charged Particle. You must be able to calculate the magnetic field due to a moving charged particle. Biot-Savart Law: Magnetic Field due to a Current Element.

rosemaries
Download Presentation

Today’s agenda: Magnetic Fields Due To A Moving Charged Particle.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Today’s agenda: Magnetic Fields Due To A Moving Charged Particle. You must be able to calculate the magnetic field due to a moving charged particle. Biot-Savart Law: Magnetic Field due to a Current Element. You must be able to use the Biot-Savart Law to calculate the magnetic field of a current-carrying conductor (for example: a long straight wire). Force Between Current-Carrying Conductors. You must be able to begin with starting equations and calculate forces between current-carrying conductors.

  2. Magnetic Field of a Current-Carrying Wire It is experimentally observed that parallel wires exert forces on each other when current flows. I1 I2 I1 I2 F12 F21 F12 F21     “Knowledge advances when Theory does battle with Real Data.”—Ian Redmount

  3. Example: use the expression for B due to a current-carrying wire to calculate the force between two current-carrying wires. d I1 I2 L F12  B2 y L1 L2 z x   The force per unit length of wire is Homework Hint: use this technique for any homework problems with long parallel wires!

  4. B d I1 I2 L F12 F21 B1  y L1 L2 z x   The force per unit length of wire is

  5. Be able to show that if the currents in the wires are in the opposite direction, the force is repulsive. d I1 I2 L F12 F21 L1 L2   The official definition of the Ampere: 1 A is the current that produces a force of 2x10-7 N per meter of length between two long parallel wires placed 1 meter apart in empty space.

More Related