211 likes | 416 Views
Physics. Session. Rotational Mechanics -7. Session Objectives. Session Objective. Problems. Class Test.
E N D
Session Rotational Mechanics -7
Session Objective • Problems
A wheel of mass 2 kg having practically all the mass concentrated along the circumference of a circle of radius 20 cm is rotating on its axis with an angular velocity of 100 rad/s. The rotational kinetic energy of the wheel is • 4 J (b) 70 J • (c) 400 J (d) 800 J Class Exercise - 1
Solution Hence, answer is (c).
A rod of length L is hinged from one end. It is brought to the horizontal position and released. The angular velocity of the rod when it is in vertical position is Class Exercise - 2
Solution Loss in potential energy = Gain inkineticenergy
Solution contd.. Hence, answer is (b).
The moment of inertia of a square plate about one of its diagonal is (Assumeto be the side of the square and mass M) Class Exercise - 3
MI of a square plate about an axispassing through itscentre andperpendicular to its plane is I0 = 2ID Solution Hence, answer is (b).
A uniform disc of radius R and mass M is mounted on an axle as shown in the figure. A light cord is wrapped around the rim of the wheel and a downward pull T is exerted on the cord. The angular acceleration of the wheel is Class Exercise - 4
Solution Applying torque equation,torqueof tension about O = TR Hence, answer is (a).
A particle of mass m is released from rest at A, falling parallel to y-axis. The torque acting on the particle with respect to origin and angular momentum at any time with respect to origin is • mgb and mgt (b) mgt and mg • (c) mgb and mgbt (d) mgt and mgbt Class Exercise - 5
Momentum = mgt Solution Angular momentum = Linear momentum × Perpendiculardistance from the axis Velocity after time t of falling = gt L = mgt × b L = mgbt … (ii) Hence, answer is (c).
The ratio of the radius of gyration of a circular disc and a circular ring of the same mass and radius about a tangential axis parallel to the plane is • 6 : 5 (b) 1 : 2 • (c) 5 : 6 (d) None of these Class Exercise - 6
M.I. of circular disc about tangentialaxis by theorem ofparallel axis is M.I. of ring about tangential axis by theorem of parallelaxis is Solution Hence, answer is (d).
The moment of inertia of a cylinder of radius a mass M and height h about an axis parallel to the axis of the cylinder and distant b from the centre is Class Exercise - 7
Solution According to theorem of parallel axis, Hence, answer is (d).