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Homework Corrections for Holt 8-4 and 8-3

This is a list of homework corrections for Holt 8-4 and Holt 8-3, including problems 36, 39, 42, 45, 48, 51, 54, and various others.

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Homework Corrections for Holt 8-4 and 8-3

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  1. Homework Corrections(Page 1 of 3) A # 14 / Holt 8-4 #36, 39, 42, 45, 48, 51, 54, 67, 68, 70, 77 – 82; Holt 8-3 #33 – 36, 38 – 43 Holt 8-4 36. (3x + 2)(x + 3) 39. (3x – 4)(x – 5) 42. (5x + 3)(2x + 5) 45. (2x – 1)(2x + 3) 48. (n + 1)(3n – 4) 51. -(3x – 2)(x + 1) 54. 5x2 + 31x – 28; (x + 7)(5x – 4) 67. 4x(x + 2) + 1(x + 2) (4x + 1)(x + 2) 68. width increased by 2 yd, length increased by 3 yd 70. The student forgot to find factors of both 12 and 2 77. B

  2. Homework Corrections(Page 2 of 3) A # 14 / Holt 8-4 #36, 39, 42, 45, 48, 51, 54, 67, 68, 70, 77 – 82; Holt 8-3 #33 – 36, 38 – 43 Holt 8-4 cont. 78. H 79. A 80. G 81. (2x + 1)(2x + 1) 82. (7x – 1)(7x – 1) Holt 8-3 33. C 34. A 35. D 36. B 38. (x + 5)(x – 4) 39. (x – 2)(x – 9)

  3. Homework Corrections(Page 3 of 3) A # 14 / Holt 8-4 #36, 39, 42, 45, 48, 51, 54, 67, 68, 70, 77 – 82; Holt 8-3 #33 – 36, 38 – 43 Holt 8-3 cont. 40. (x + 3)(x – 7) 41. (x + 1)(x + 9) 42. (x – 4)(x – 8) 43. (x + 6)(x + 7)

  4. Lesson Objective:I will be able to … • Factor perfect square trinomials and difference • of two squares • Language Objective: I will be able to … • Read, write, and listen about vocabulary, key • concepts, and examples

  5. Page 20

  6. • 3x3x • • 2(3x2) 22 A trinomial is a perfect square if: • The first and last terms are perfect squares. •The middle term is two times one factor from the first term and one factor from the last term. 9x2 + 12x + 4 Example: Page 20

  7. 9x9x 2(9x5) 55 3x3x ● ● 2(3x8) 88 ●    2(9x 5) = 90x 2(3x 8) = 48x ≠ 15x   9x2 – 15x + 64 is not a perfect-square trinomial because 15x ≠ 2(3x  8). 81x2 + 90x + 25 is a perfect-square trinomial because 90x = 2(9x  5). Example 1: Recognizing and Factoring Perfect-Square Trinomials Page 20 Determine whether each trinomial is a perfect square. If so, factor. If not explain. A. 9x2 – 15x + 64 B. 81x2 + 90x + 25 81x2 + 90x + 25 =(9x + 5)2

  8. x x 2(x7) 7 7    2(x 7) = 14x  Your Turn 1 Page 21 Determine whether each trinomial is a perfect square. If so, factor. If not explain. x2 – 14x + 49 x2 – 14x + 49 is a perfect-square trinomial because 14x = 2(x  7). x2 – 14x + 49 =(x – 7)2

  9. 4x2 – 9 2x 2x3 3   A polynomial is a difference of two squares if: • There are two terms, one subtracted from the other. • Both terms are perfect squares. Example: Page 20

  10. x4 – 25y6 is a difference of two squares because and . x2 x2 10x 10x 5y3 5y3 2y 2y     100x2 – 4y2 is a difference of two squares because and . Example 2: Recognizing and Factoring the Difference of Two Squares Page 21 Determine whether each binomial is a difference of two squares. If so, factor. If not, explain. A. 100x2 – 4y2 B. x4 – 25y6 x4 – 25y6 = (x2 + 5y3)(x2 – 5y3) 100x2 – 4y2 = (10x + 2y)(10x – 2y)

  11. 4x 4x 2y? 2y? Your Turn 2 Page 21 Determine whether each binomial is a difference of two squares. If so, factor. If not, explain. 16x2 – 4y5 16x2 – 4y5 is not the difference of two squares because 4y5 is not a perfect square.

  12. Classwork Assignment #15 • Holt 8-5 #1 – 13

  13. Homework Assignment #15 • Holt 8-5 #14 – 19, 21 – 32 • KIN 8-6

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