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A comprehensive study guide on reaction rates and equilibrium in chemistry, covering topics such as activation energy, entropy, catalysts, and Keq calculations.
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ChemistryChapter 19 – Reaction Rates and EquilibriumStudy Guide - Answers
Matching. • I activated complex • A reaction rate • J Le Châtelier’s principle • C spontaneous • G elementary reaction • E chemical equilibrium • H entropy • D activation energy • F inhibitor • B free energy
11. In which the following physical states does a given substance have the highest entropy? • Solid • Gas • Liquid • All of the above
12. A reaction that requires free energy • Must be endothermic • Is nonspontaneous. • Must correspond to a decrease in entropy. • Is spontaneous.
13. The two factors that determine whether a reaction is spontaneous or nonspontaneous are: • Entropy and disorder. • Entropy and enthalpy change. • Electron configuration and energy change. • Energy and the heat of reaction.
14. In which of these systems is the entropy decreasing? • Air escaping from a tire • Snow melting • Salt dissolving in water • A gas condensing to a liquid Decreasing Entropy
15. All spontaneous processes: • Are exothermic • Are endothermic • Involve an increase in entropy • Release free energy
16. If a catalyst is used in a reaction: • The energy of activation increases. • The reaction rate does not change. • The reaction rate increases. • The equilibrium shifts.
17. Which of the following affects the rate of a chemical reaction? • The presences of a catalyst • The temperature • The concentration of reactants • All of the above.
18. What is the expression for Keq for this reaction? 2H2O(g) ⇋ 2H2(g) + O2(g) • Keq= [2H2O] [H2]x[O2] • Keq= [H2]2 x [O2] [H2O]2 • Keq= [2H2] x [O2] [2H2O] • Keq= [H2O]2 [H2]2 x [O2]
19. In an equilibrium reaction with a Keq of 1 x 108 • Reactants are favored. • Reaction is nonspontaneous. • Products are favored. • Reaction is exothermic.
20. What is the effect of adding more CO2 to the following equilibrium reaction? CO2+ H2O ⇋ H2CO3 • More H2CO3 is produced. • More H2O is produced. • The equilibrium is pushed in the direction of reactants. • No change.
21. Doing which of the following generally increases the entropy of a substance? • Freezing it • Dissolving it in water • Condensing it • All of the above
22. The Keq of a reaction is 4 x 10-7. At equilibrium: • The reactants are favored. • The products are favored. • The reactants and products are present in equal amounts. • The rate of the reverse reaction is much greater than the rate of the forward reaction.
23. Two opposing reactions (A + B ⇋ C + D) occurring simultaneously at the same rate is an example of: • Reversibility. • Chemical equilibrium. • Neither a nor b • Both a and b
24. Calculate the value of Keq for this reaction at equilibrium. 2NOCl(g) ⇋ 2NO(g) + Cl2(g)An analysis of the equilibrium mixture in a 1-L flask gives the following results: NOCl, 0.30 mol; 1.2 mol; Cl2, 0.60 mol. Keq= [NO]2 x [Cl2] = (1.2)2(0.60) = 9.6 [NOCl]2 (0.30)2 Keq= 9.6
25. Carbon monoxide and hydrogen are combined in the commercial preparation of methyl alcohol. CO(g) + 2H2(g) ⇋ CH3OH(g)At a certain set of conditions, the equilibrium mixture contains 0.020 mol/L of CO, 0.60 mol/L of H2, and the equilibrium constant is 2.2 x 102 L2/mol2. What is the concentration of CH3OH in the equilibrium mixture? 2.2 x 102 L2/mol2 = [CH3OH]. [CO] x [H2]2 2.2 x 102 L2/mol2 = [CH3OH] . (0.020 mol/L)(0.60 mol/L)2 [CH3OH] = 1.58 mol/L
26. The following reaction has an H0of 53 kJ/mol and a S0 of 0.070 kJ/(K x mol) at 25 °C. 2A + B → 2CIs this reaction spontaneous? (Calculate ΔG.) 273 °C + 25° = 298 K ΔG0 = ΔH0 – TΔS0 ΔG0 = (53 kJ/mol) – (298 K)(0.070 kJ/mol·K) ΔG0 = (53 kJ/mol) – (21 kJ/mol) ΔG0 = 32 kJ/mol This reaction is not spontaneous, because G0 is positive!
27. What is the standard change in entropy for the following reaction when all reactants are in specified states? 2H2O(l) + O2(g) → 2H2O2(l)Standard entropies S0 is J/(K x mol): H2O(l) = 69.94, H2O2(l) = 92.0, O2(g) = 205.0 ΔS0= S0(products) – S0(reactants) ΔS0 = (2 mol)(92.0 J/mol·K) – [(2 mol)(69.94 J/mol·K) + (1 mol)(205.0 J/mol·K)] 1 mole 1 mole 1 mole ΔS0 = -161 J/(mol·K)
28. Predict the changes in the equilibrium position for this reaction when the following changes are made: 2A(g) + B(g) ⇋ 4C(g) + heat • Decrease the concentration of C; • Add more heat; • Increase the concentration of A; • Increase the pressure. In each case, state whether the change causes a shift that favors the formation of reactants or of products. • Favors Products • Favors Reactants • Favors Products • Favors Reactants
29. The rate law for the following reaction is: Rate = k[A]a x [B]b.aA+ bB → cC + dDFrom the data in the following chart, find the kinetic order of the reaction with respect to A and B, as well as the overall order. Doubling A doubles the rate – first order in A. Doubling B increases the rate 8 times (23 = 8) – third order in B. First order + third order = fourth order overall.