270 likes | 398 Views
Dynamical Systems 2 Topological classification. Ing. Jaroslav J í ra , CSc. More Basic Terms. Basin of attraction is the region in state space of all initial conditions that tend to a particular solution such as a limit cycle, fixed point, or other attractor.
E N D
Dynamical Systems 2Topological classification Ing. Jaroslav Jíra, CSc.
More Basic Terms Basin of attraction is the region in state space of all initial conditions that tend to a particular solution such as a limit cycle, fixed point, or other attractor. Trajectory is a solution of equation of motion, it is a curve in phase space parametrized by the time variable. The Flow of a dynamical system is the expression of its trajectory or beam of its trajectories in the phase space, i.e. the movement of the variable(s) in time Nullclines are the lines where the time derivative of one component of the state variable is zero. Separatrix is a boundary separating two modes of behavior of the dynamical system. In 2D cases it is a curve separating two neighboring basins of attraction.
A simple pendulum Differential equation After transformation into two first order equations
An output of the Mathematica program Phase portratit for the simple pendulum Used equations
A simple pendulum with various initial conditions Stable fixed point φ0=0° φ0=45° φ0=90° φ0=135° Unstable fixed point φ0=180° φ0=170° φ0=190° φ0=220°
A damped pendulum Differential equation After transformation into two first order equations Equation in Mathematica: NDSolve[{x'[t] == y[t], y'[t] == -.2 y[t] - .26 Sin[x[t]], … and phase portraits
A damped pendulumcommented phase portrait Nullcline determination: At the crossing points of the null clines we can find fixed points.
Classification of Dynamical SystemsOne-dimensional linear or linearized systems
Verification from the bacteria example Bacteria equation Derivative 1st fixed point - unstable 2nd fixed point - stable
Classification of Dynamical SystemsTwo-dimensional linear or linearized systems Set of equations for 2D system Jacobian matrix for 2D system Calculation of eigenvalues Formulation using trace and determinant
Types of two-dimensional linear systems1.Attracting Node (Sink) Equations Jacobian matrix Eigenvalues λ1= -1 λ2= -4 Eigenvectors Solution from Mathematica Conclusion: there is a stablefixed point, the node-sink
2.Repelling Node Equations Jacobian matrix Eigenvectors Eigenvalues λ1= 1 λ2= 4 Solution from Mathematica Conclusion: there is an unstablefixed point, the repelling node
3.Saddle Point Equations Jacobian matrix Eigenvectors Eigenvalues λ1= -1 λ2= 4 Solution from Mathematica Conclusion: there is an unstablefixed point, the saddle point
4.Spiral Source (Repelling Spiral) Equations Jacobian matrix Eigenvectors Eigenvalues λ1= 1+2i λ2= 1-2i Solution from Mathematica Conclusion: there is an unstablefixed point, the spiral source sometimes called unstable focal point
5.Spiral Sink Equations Jacobian matrix Eigenvectors Eigenvalues λ1= -1+2i λ2= -1-2i Solution from Mathematica Conclusion: there is a stablefixed point, the spiral sink sometimes called stable focal point
6.Node Center Equations Jacobian matrix Eigenvectors Eigenvalues λ1= +1.732i λ2= -1.732i Solution from Mathematica Conclusion: there is marginally stable (neutral) fixed point, the node center
Brief classification of two-dimensional dynamical systems according to eigenvalues
Special cases of identical eigenvalues A stable star (a stable proper node) Equations and matrix Eigenvalues + eigenvectors Solution An unstable star (an unstable proper node) Equations and matrix Eigenvalues + eigenvectors Solution
Special cases of identical eigenvalues A stable improper node with 1 eigenvector Equations and matrix Eigenvalues + eigenvectors Solution An unstable improper node with 1 eigenvector Equations and matrix Eigenvalues + eigenvectors Solution
Classification of dynamical systems usingtrace and determinant of the Jacobian matrix 1.Attracting node p=-5; q=4; Δ=9 2. Repelling node p=5; q=4; Δ=9 3. Saddle point p=3; q=-4; Δ=25 4. Spiral source p=2; q=5; Δ=-16 5. Spiral sink p=-2; q=5; Δ=-16 6. Node center p=0; q=5; Δ=-20 7. Stable/unstable star p=-/+ 2; q=1; Δ=0 8. Stable/unstable improper node p=-/+ 2; q=1; Δ=0
Example 2 – an improper node calculation in Matlab function [t,y] = setequationsimnode tspan=[0,5]; for k=-10:10; for l=-10:20:10; init=[k;l]; [t,y]=ode45(@f,tspan,init); plot(y(:,1),y(:,2)); hold on; end end for k=-10:10; for l=-10:20:10; init=[l;k]; [t,y]=ode45(@f,tspan,init); plot(y(:,1),y(:,2)); hold on; end end %Plot annotation xlabel('x1') ylabel('x2') title('AN IMPROPER NODE'); grid on; function yprime=f(t,y) yprime=zeros(2,1); yprime(1)=-y(1)+y(2); yprime(2)=-y(2); end clc hold off end
Classification of Dynamical SystemsLinear or linearized systems with more dimensions