1 / 14

Graphing Quadratic Inequalities

Graphing Quadratic Inequalities. Steps for Graphing (quickly). Shading. Graph: y ≤ x 2 + 6x – 4. * Vertex: (-3,-13). Slope 1, 3, 5. * Solid Line. * Less than means shade BELOW. Graph: y > -x 2 + 4x – 3. * Vertex: (2, 1). Slope -1, -3, -5. * Dashed Line.

sandrahenry
Download Presentation

Graphing Quadratic Inequalities

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Graphing Quadratic Inequalities

  2. Steps for Graphing (quickly)

  3. Shading

  4. Graph: y ≤ x2 + 6x – 4 * Vertex: (-3,-13) Slope 1, 3, 5 * Solid Line * Less than means shade BELOW

  5. Graph: y > -x2 + 4x – 3 * Vertex: (2, 1) Slope -1, -3, -5 * Dashed Line * Greater than means shade ABOVE

  6. Graph: y ≥ x2 – 8x + 12 * Vertex: (4, -4) Slope 1, 3, 5 * Solid Line * Greater than means shade ABOVE

  7. Graph: y > -x2 + 4x + 5 * Vertex: (2, 9) Slope -1, -3, -5 * Dashed Line * Greater than means shade ABOVE

  8. Solving a Quadratic Inequality

  9. Steps for solving • Write the original inequality as an equation • Set equal to 0, factor, and solve. • > ≥  GREAT OR – or must be in the answer • Write the answer

  10. Solve: x2 – 5x≤ – 4 x2 – 5x = -4 x2 – 5x + 4 = 0 (x – 4) (x – 1) = 0 x = 1, 4 Answer: 1 ≤ x ≤ 4

  11. Solve: -x2 + 7x< 12 -x2 + 7x = 12 -x2 + 7x – 12 = 0 x2 – 7x + 12 = 0 (x – 4) (x – 3) = 0 x = 3, 4 Answer: x < 3 or x > 4

  12. What if it can’t factor?Graph it!

  13. Solve: -(x – 1)2 – 3 < 0 -(x – 1)2 – 3 < y y > -(x – 1)2 – 3 Answer: all real numbers

  14. Solve: x2 + 4 ≤ 0 x2 + 4 ≤ y y ≥ x2 + 4 Answer: no solution

More Related