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B-field points into page

a. g. B-field points into page. b. 1900-01 Studying the deflection of these rays in magnetic fields, Becquerel and the Curies establish    rays to be charged particles. p i = 0 = p f = p rifle + p bullet. p rifle = – p bullet.  - decay.  - decay.

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B-field points into page

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  1. a g B-field points into page b 1900-01 Studying the deflection of these rays in magnetic fields, Becquerel and the Curies establish  rays to be charged particles

  2. pi = 0 = pf = prifle + pbullet prifle = – pbullet

  3. -decay -decay

  4. Some Alpha Decay Energies and Half-lives Isotope KEa(MeV) t1/2l(sec-1) 232Th 4.01 1.41010 y 1.610-18 238U 4.19 4.5109 y 4.910-18 230Th 4.69 8.0104y 2.810-13 238Pu 5.50 88years 2.510-10 230U 5.89 20.8 days 3.910-7 220Rn 6.29 56 seconds 1.210-2 222Ac 7.01 5 seconds 0.14 216Rn 8.05 45.0msec 1.5104 212Po 8.78 0.30msec 2.3106 216Rn 8.78 0.10msec 6.9106

  5. 1930 Series of studiesofnuclear beta decay, e.g., Potassiumgoestocalcium19K40 20Ca40 Coppergoestozinc29Cu64 30Zn64 Borongoestocarbon5B12  6C12 Tritiumgoes tohelium1H3  2He3 Potassium nucleus Before decay: After decay: A B A) B) C) both the same Which fragment has a greater momentum? energy?

  6. 1932 Once the neutron was discovered, included the more fundamental n  p + e For simple 2-bodydecay, conservation of energy and momentum demand both the recoil of the nucleus and energy of the emitted electron be fixed (by the energy released through the loss of mass) to a single precise value. Ee = (mA2 - mB2 + me2)c2/2mA but this only seems to match the maximum value observed on a spectrum of beta ray energies!

  7. No. of counts per unit energy range 0 5 10 15 20 Electron kinetic energy in KeV The beta decay spectrum of tritium ( H  He). Source: G.M.Lewis, Neutrinos (London: Wykeham, 1970), p.30)

  8. -decay spectrum for neutrons Electron kinetic energy in MeV

  9. 1932n  p + e- + charge0 +1 -1 ? mass939.56563 938.27231 0.51099906 MeVMeVMeV neutrino ??? 0 ? the Fermi-Kurie plot. The Fermi-Kurie plot looks for any gap between the observed spectrum and the calculated Tmax neutrino mass < 5.1 eV < me /100000  0

  10. Niels Bohr hypothesized the existence of quantum mechanical restrictions on the principle of energy conservation, but Pauli couldn’t buy that: Wolfgang Pauli 1900-1958

  11. Dear Radioactive Ladies and Gentlemen, as the bearer of these lines, to whom I graciously ask you to listen, will explain to you in more detail, how because of the "wrong" statistics of the N and Li6 nuclei and the continuous beta spectrum, I have hit upon a desperate remedy to save the "exchange theorem" of statistics and the law of conservation of energy. Namely, the possibility that there could exist in the nuclei electrically neutral particles, that I wish to call neutrons, which have spin 1/2 and obey the exclusion principle and which further differ from light quanta in that they do not travel with the velocity of light. The mass of the neutrons should be of the same order of magnitude as the electron mass and in any event not larger than 0.01 proton masses. The continuous beta spectrum would then become understandable by the assumption that in beta decay a neutron is emitted in addition to the electron such that the sum of the energies of the neutron and the electron is constant... I agree that my remedy could seem incredible because one should have seen those neutrons much earlier if they really exist. But only the one who dare can win and the difficult situation, due to the continuous structure of the beta spectrum, is lighted by a remark of my honoured predecessor, Mr Debye, who told me recently in Bruxelles: "Oh, It's well better not to think to this at all, like new taxes". From now on, every solution to the issue must be discussed. Thus, dear radioactive people, look and judge. Unfortunately, I cannot appear in Tubingen personally since I am indispensable here in Zurich because of a ball on the night of 6/7 December. With my best regards to you, and also to Mr Back. Your humble servant . W. Pauli, December 1930

  12. "I have done a terrible thing. I have postulated a particle that cannot be detected."

  13. Primary proton 1936 Millikan’s group shows at earth’s surface cosmic ray showers are dominated by electrons, gammas, and X-particles capable of penetrating deep underground (to lake bottom and deep tunnel experiments) and yielding isolated single cloud chamber tracks

  14. 1937 Street and Stevenson • 1938 Andersonand Neddermeyer • determine X-particles • are charged • have 206× the electron’s mass • decay to electrons with • a mean lifetime of 2msec 0.000002 sec

  15. 1947 Lattes, Muirhead, Occhialini and Powell observe pion decay Cecil Powell (1947) Bristol University 

  16. C.F.Powell, P.H. Fowler, D.H.Perkins Nature 159, 694 (1947) Nature 163, 82 (1949)

  17. Consistently ~600 microns (0.6 mm) 

  18. Under the influence of a magnetic field m+ p+ m+ energy always predictably fixed by Ep simple 2-body decay! p+m+ + neutrino? charge +1 +1 ? spin 0½? 0 ½

  19. n p + e- + neutrino? p+m+ + neutrino? Then m-e- + neutrino? p ??? m e As in the case of decaying radioactive isotopes, the electrons’s energy varied, with a maximum cutoff (whose value was the 2-body prediction) 3bodydecay! e m 2 neutrinos

  20. 1953, 1956, 1959 Savannah River (1000-MWatt) Nuclear Reactor in South Carolina looked for the inverse of the process n p + e- + neutrino p + neutrino n + e+ ? with estimate flux of 51013 neutrinos/cm2-sec Cowan & Reines observed 2-3 p + neutrino events/hour also looked for n + neutrino p + e- but never observed!

  21. Homestake Mine Experiment • 1967 • built at Brookhaven labs • 615 tons of tetrachloroethylene • Neutrino interaction 37Cl37Ar • (radioactive isotope, ½ = 35 days) • Chemically extracting the 37Ar, • its radioactivity gives the number • of neutrino interactions in the vat • (thus the solar neutrino flux). • Results: Collected data 1969-1993 • (24 years!!) • gives a mean of 2.5±0.2 SNU • while theory predicts 8 SNU • (1 SNU = 1 neutrino interaction • per second for 10E+36 target atoms). • This is a neutrino deficit of 69%.

  22. UndergroundNeutrinoObservatory The proposed next-generation underground water Čerenkov detector to probe physics beyond the sensitivity of the highly successful Super-Kamiokande detector in Japan

  23. The SuperK detector is a water Čerenkov detector 40 m tall 40 m diameter stainless steel cylinder containing 50,000 metric tons of ultra pure water The detector is located 1 kilometer below Mt. Ikenoyama inside the Kamioka zinc mine.

  24. The main sensitive region is 36 m high, 34 m in dia viewed by 11,146 inward facing Hamamatsu photomultiplier tubes surrounding 32.5 ktons of water

  25. UndergroundNeutrinoObservatory • 650 kilotons • active volume: • 440 kilotons • 20 times larger • than • Super-Kamiokande $500M The optimal detector depth to perform the full proposed scientific program of UNO  4000 meters-water-equivalent or deeper major components: photomultiplier tubes, excavation, water purification system.

  26. 1953 Konopinski & Mahmoud introduce LEPTON NUMBER to account for which decays/reactions are possible,which not e,  ( )  assignedL = +1 e+, + ( +)  assignedL = -1 n p +e- + neutrino _ _  _ p + neutrino n + e+  n + e+ n +  p + e- ?? ??

  27. 1962Lederman,Schwartz,Steinberger Brookhaven National Laboratory using aas a source ofantineutrinos and a 44-footthick stack of steel (from a dismantled warship hull) to shield everything but the ’s found 29 instances of  + p  + + n but none of  + p  e+ + n

  28. So not just ONE KIND of neutrino, the leptons are associated into “families” e e      p e- e- e e  n

  29. Helicity“handedness” For a moving particle state, its lab frame velocity defines an obvious direction for quantization ms s fraction of spin “aligned” in this direction For spin-½ S =  ·p=H   1 2 though  ^ mS s(s+1) |Sz| |S| mSħ s(s+1)ħ = = Notice individual spin-½ particles have HELICITY +1(ms = +½)RIGHT-HANDED HELICITY +1(ms = -½)LEFT-HANDED spin spin v v s s

  30. However: not “aligned” just mostly so HELICITY +1(ms = +½)RIGHT-HANDED HELICITY +1(ms = -½)LEFT-HANDED But helicity (say of an electron) is not some LORENTZ-INVARIANT quantity! Its value depends upon the frame of reference: Imagine a right-handed electron traveling to the right when observed in a frame itself moving right with a speed > v. spin It will be left-handed! v s

  31. So HELICITY must NOT appear in the Lagrangian for any QED or QCD process (well, it hasn’t yet, anyway!). HELICITY is NOT like some QUANTUM NUMBER. It is NOT unambiguously defined. But what about a massless particle (like the  or…the neutrino?) m < 5.1 eV << me = 0.511003 MeV e m < 160 keV  m < 24 MeV  Recall for a massless particle: v = c Which means it is impossible (by any change of reference frame) to reverse the handedness of a massless particle. HELICITY is an INVARIANT a fundamental, FIXED property of a neutrino or photon.

  32. Experimentally what is generally measured is a ratio comparing the number of a particles in a beam, or from a source, that are parallel or anti-parallel to the beams direction. Helicity = Longitudinal polarization turns out to be hard to measure; Transverse polarization is much easier to detect. There are several schemes for rotating the polarization of massive particles.

  33. Electro-static bending magnetic bending precesses spin - - - - - - - - + + + + + - + to analyzer + - + + - + - + + light element (metallic) reflector aluminum e- Coulomb scattering doesn’t alter spin direction! decay source analyzer

  34. E B Crossed magnetic/electric fields: EB selects the velocity v= c but the spin precesses about the B-filed direction E E E B B B Can be built/designed to rotate the spin by a pre-calculated amount (say 90O) Following any scheme for rotating spins, beams of particles can be Spin analyzed by punching through a thin foil of some heavy element!

  35. Head-on view of approaching nuclei + + m m,soppositely aligned! s

  36. electron passing nuclei on the right  Sees B of approaching nuclei UP + + m “orbital” angular momentum of nuclei ( up!) m,soppositely aligned! s positive! The interaction makes the potential energy increase with r

  37. positive negative  The interaction makes the potential energy increase with r So gives a positive (repulsive) force which knocks electrons to the RIGHT!

  38. electron passing nuclei on the left  Sees B of approaching nuclei DOWN + + m s “orbital” angular momentum of nuclei ( down!) negative! So knocks electrons to the LEFT! gives an attractive force

  39. When positive more electrons scatter LEFT than RIGHT When negative more RIGHT than LEFT EXPERIMENTALLY The weak decay products , e v c predominantly right-handed H = + for e+, + v c predominantly left-handed H = - for e-, -

  40. Until 1960s assumed, like s neutrinos come in both helicities: +1 and -1 …created in ~equal numbers (half polarized +1, half -1) 1961 1st observed PION DECAYS at REST _ (where ,  come out back-to-back) spins  , (each spin-½) oppositely aligned! _    spin-0 Were these half +1, half -1? No! Always polarized RIGHT-HANDED! So these must be also! +  + Each ALWAYS left-handed!

  41. ALL NEUTRINOS ARE LEFT-HANDED Helicity = ms/s = -1 ALL NEUTRINOS ARE RIGHT-HANDED Helicity = ms/s = +1

  42. Dirac Equation(spin-½ particles) ( p my  0 0 sj -sj0 j  ( 0p0  •p y  my 0 s -s0 0 p •s - p •s0 p • ( ) = ( ) where p •s = px( ) + py( ) + pz( ) 0 1 1 0 0 -i i 0 1 0 0 -1 = ( ) pz px-ipy px+ipy-pz

  43. Our “Plane wave” solutions(for FREEDirac particles) y(r,t) = aexp[i/h(Et-p • r)]u(E,p) ae(i/h)xmpmu(E,p) which gave ( p mu = ( )( ) E/c-mc -p•s uA p•s -E/c-mcuB from which we note: uA= ( p • s )uB uB= ( p • s )uA c E-mc2 c E+mc2

  44. Dirac Equation(spin-½ particles) g 0 -pxg1-pyg 2-pzg 3= my E c recall g 5=ig 0g 1g 2g 3 multiply from left by (-ig 1g 2g 3) -ig 1g 2g 3g 0 = +ig 0g 1g 2g 3 = g 5 since g mg n=-g ng m -ig 1g 2g 3g 1 = -i(g 1)2g2g 3 = +ig2g 3 = +i(s2s3)( )( ) = +i(is1)( ) = s1I since (g i)2 = -I 0 1 -1 0 0 1 -1 0 -1 0 0 -1 so -px g 1 - px s 1I -ig 1g 2g 3g 2 = s2I -ig 1g 2g 3g 3 = s3I (g 5 -(p • s)I)y = -img 1g 2g 3y E c

  45. This gives an equation that looks MORE complicated! How can this form be useful? (g 5 -(p • s)I)y = -img 1g 2g 3y E c For a ~massless particle (like theor any a relativistic Dirac particle E >> moc2) E=|p|c as mo0 (or at least mo<<E) ( |p|g 5 -(p • s)I)y = 0 Which then gives: or: (g 5 -p • sI)y = 0 ^ s0 0s sI = What do you think this looks like? ^ p • sI is a HELICITY OPERATOR!

  46. In Problem Set #5 we saw that if the z-axis was chosen to be the direction of a particle’s momentum were all well-defined eigenspinors of Sz i.e. (p • sI)u(p)= u(p) ^ “helicity states” (g 5 -p • sI)y = 0 ^ So • 5 “measures” the helicity of y g 5y = (p • sI)y ^

  47. Looking specifically at g5u(p) = = uA uB uB uA For massless Dirac particles (or in the relativistic limit) (p • sI)u(p) ^ g5u(p)=

  48. We’ll find a useful definition in the “left-handed spinor” Think: “Helicity=-1” (1-5) 2 uL(p)=u(p) In general NOT an exact helicity state (if not massless!) Since 5u(p)= ±u(p) for massless or relativistic Dirac particles 0 if u(p) carries helicity +1 u(p) if u(p) carries helicity -1 if neither it still measures how close this state is to being pure left-handed separates out the “helicity-1 component” Think of it as a “projection operator” that picks out the helicity -1 component of u(p)

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