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6.6 Rings and fields

Let ? : G 1 ?G 2 be a surjection homomorphism between two groups, N be a normal subgroup of G 1 , and Ker ? ? N. Proof: G 2 / ? (N) is a group. Theorem 6.22: Let [H; ? ] be a normal subgroup of the group [G; ? ]. Then [G/H; ? ] is a group. ? (N) is a subgroup of G 2 . Normal subgroup?

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