'L g m cfg' presentation slideshows

Module 34

Module 34. CFG --> PDA construction Shows that for any CFL L, there exists a PDA M such that L(M) = L The reverse is true as well, but we do not prove that here. CFL subset LPDA. Let L be an arbitrary CFL Let G be the CFG such that L(G) = L G exists by definition of L is CF

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