'Uniform charge' presentation slideshows

Ley de Gauss

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Physics 014

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Physics 2102

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IV. Fields

IV. Fields. 2. Example : Electric Field at a point a distance x from a line with uniform charge density l total charge Q, and a length 2a as shown. Step 1: Define dQ: dQ = l dy = (Q/2a)dy. Step 2: Differential form (continuous distribution of charge) |d E | = k(dQ)/r 2

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Electric Charge

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Problem #34 (a)

Example 23.8. Problem #34 (a).

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HRW7 23.CQ.01. [406131] A surface has the area vector A = (6 i +3 j ) m 2 .

Warm Up 3. Question. HRW7 23.CQ.01. [406131] A surface has the area vector A = (6 i +3 j ) m 2 . (a) What is the flux of an electric field through it if the field is E = 4 N/C i ? (b) What is the flux of an electric field through it if the field is E = 4 N/C k?. Answer: (a).

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HRW7 23.CQ.01. [406131] A surface has the area vector A = (6 i +3 j ) m 2 .

Warm Up 3. Question. HRW7 23.CQ.01. [406131] A surface has the area vector A = (6 i +3 j ) m 2 . (a) What is the flux of an electric field through it if the field is E = 4 N/C i ? (b) What is the flux of an electric field through it if the field is E = 4 N/C k?. Answer: (a).

282 views • 2 slides