40 likes | 176 Views
Note / step 2. Note / step 3. HAUL: 3:1. T1. Note / step 4. T1. Anchor. Note / step 6. T1. T1. T2. T2. T1. T3 ( T1 + T2). T3. load. Note / step 5. 3:1 “Z” System. 100% efficient pulleys. Instructions on how to perform a “T Analysis” 1) Draw out your system
E N D
Note / step 2 Note / step 3 HAUL: 3:1 T1 Note / step 4 T1 Anchor Note / step 6 T1 T1 T2 T2 T1 T3 (T1 + T2) T3 load Note / step 5 3:1 “Z” System 100% efficient pulleys Instructions on how to perform a “T Analysis” 1) Draw out your system 2) Start by applying T=1 where you would haul/pull on the system 3) T value into a pulley is = T value out of pulley 4) T value behind the pulley is the sum of input & out put values 5) T values sum at intersections (i.e. pulley / prusik intersection of main line) 6) T value at load = mechanical advantage (MA) of system
3:1 “Z” System 100% efficient pulleys T =1 = 100% Pulley = 80% Pulley Anchor T = 1 = Prusik T = 2 T = 2 T = 1 T = 1 + 2 T = 3 load 80% efficient at moving pulley & 50% efficient pulley at COD/anchor T = 1 Anchor T = 0.8 T = 1.8 T = 1.2 T = 0.4 T = 0.4 + 1.8 T = 2.2 load 50% efficient at moving pulley & 80% at COD/anchor T =1 Anchor T = 0.5 T = 1.5 T = 0.9 T = 0.4 T = 0.4 + 1.5 T = 1.9 load = 50% Pulley
Fixed end of 8 mm cord T1 T1 T2 T2 T1 Anchor T1 T4 (T2+T2) Load T1 T1 T2 T2 T1 T1 HAUL, 4:1 MA Fixed end of 8 mm cord T1 T1 T1 T1 T2 T2 Anchor Load T5 (T2+T2+T1) T1 T1 T1 T1 T2 T2 T1 T1 HAUL, 5:1 MA Set of 4s with 5:1 MA & 4:1 MA
T1 HAUL = 5:1 5:1 Compound “Z” System = 100% Pulley T1 = Prusik T1 T1 T2 Anchor T1 T3 (T1 + T2) T2 T6 T3 load T5 (T3 + T2) T1 HAUL = 11:1 T1 T1 T1 T2 T1 T3 (T1 + T2) T2 Anchor T5 (T3 + T2) T3 T6 T10 T5 load T11 (T5 + T6) 11:1 Double Compound “Z” System