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pH of Common Substances

pH of Common Substances. Timberlake, Chemistry 7 th Edition, page 335. Calculating pH. pH = -log [H + ] So if [H + ] = 1x10 -5 pH = - log ( 1x10 -5 ) = 5 Calculate the pH if [H + ] = 1 x 10 -2 M pH = [H + ] = 3.0 x 10 -6 M pH = [H + ] = 8.2 x 10 -6 M pH =.

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pH of Common Substances

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  1. pH of Common Substances Timberlake, Chemistry 7th Edition, page 335

  2. Calculating pH • pH = -log [H+] • So if [H+] = 1x10-5 pH = - log (1x10-5 ) = 5 • Calculate the pH if [H+] = 1 x 10-2 M pH = [H+] = 3.0 x 10-6 M pH = [H+] = 8.2 x 10-6 M pH =

  3. Convert pH to [H+] • 10-pH = [H+] • If pH = 5, 10-pH = 10-5 = 0.000 01 = 1 x 10-5 M • Calculate the [H+] if pH = 2.37 [H+] = pH = 11.05 [H+] = pH = 6.50 [H+] =

  4. pH of Common Substance pH [H1+] [OH1-] pOH 14 1 x 10-14 1 x 10-0 0 13 1 x 10-13 1 x 10-1 1 12 1 x 10-12 1 x 10-2 2 11 1 x 10-11 1 x 10-3 3 10 1 x 10-10 1 x 10-4 4 9 1 x 10-9 1 x 10-5 5 8 1 x 10-8 1 x 10-6 6 6 1 x 10-6 1 x 10-8 8 5 1 x 10-5 1 x 10-9 9 4 1 x 10-4 1 x 10-10 10 3 1 x 10-3 1 x 10-11 11 2 1 x 10-2 1 x 10-12 12 1 1 x 10-1 1 x 10-13 13 0 1 x 100 1 x 10-14 14 NaOH, 0.1 M Household bleach Household ammonia Lime water Milk of magnesia Borax Baking soda Egg white, seawater Human blood, tears Milk Saliva Rain Black coffee Banana Tomatoes Wine Cola, vinegar Lemon juice Gastric juice More basic 7 1 x 10-7 1 x 10-7 7 More acidic

  5. pOH • pOH= -log [OH-] • 10-pOH = [OH-] • So if [OH-] = 4 x 10-3 M pOH = -log (4 x 10-3) = 2.397 = 2.40 • pH + pOH = 14

  6. Complete this for homework…

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