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Final Exam. May 10, 5 – 7:30 pm, ESS 081. Energy Transformation. 1 Caloria of heat = energy necessary to raise the temperature of one gram of pure water from 14.5 – 15.5 o C Latent Heat of vaporization Hv = 597.3 – 0.564T (Cal./g) Latent Heat of condensation.
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Final Exam • May 10, 5 – 7:30 pm, ESS 081
Energy Transformation • 1 Caloria of heat = energy necessary to raise the temperature of one gram of pure water from 14.5 – 15.5oC • Latent Heat of vaporization Hv = 597.3 – 0.564T (Cal./g) • Latent Heat of condensation
Energy Transformation, Cont. • Latent heat of fusion – Hf – 1 g of ice at 0oC => ~80 cal of heat must be added to melt ice. Resulting water has same temperature. • Sublimation – Water passes directly from a solid state to a vapor state. Energy = Hf + Hv => 677 cal/g at 0oC. • Hv > 6Hf > 5 x amt. to warm water from 0oC -> 100oC
Hydrologic Equation • Inflow = outflow +/- Changes in storage • Equation is simple statement of mass conservation
Condensation • Condensation occurs when air mass can no longer hold all of its humidity. • Temperature drops => saturation humidity drops. • If absolute humidity remains constant => relative humidity rises. • Relative humidity reaches 100% => condensation => Dew point temperature.
Limited soil-moisture storage Cool, moist Cool, moist Warm, dry
All infiltrate some water always on the surface All infiltrate Puddles and overland flow
Determining ground water recharge from baseflow (1) • Meyboom method (Seasonal recession method): utilizes stream hydrographs from two or more consecutive years. • Assumptions: the catchment area has no dams or other method of streamflow regulation; snowmelt contributes little to the runoff.
Determining ground water recharge from baseflow (2) • Rorabaugh method (Recession curve displacement method): utilizes stream hydrograph during one season.
Aquifer • Properties: Porosity, specific yield, specific retention. • Potential: Transmissivity, storativity. • Types: confined, unconfined. • Hydraulic conductivity, Physical Laws controlling water transport.
d60 d10 d60 d10
Sediment Classification • Sediments are classified on basis of size of individual grains • Grain size distribution curve • Uniformity coefficient Cu = d60/d10 • d60 = grain size that is 60% finer by weight. • d10 = grain size that is 10% finer by weight. • Cu = 4 => well sorted; Cu > 6 => poorly sorted.
Specific Yield and Retention • Specific yield – Sy: ratio of volume of water that drains from a saturated rock owing to the attraction of gravity to the total volume of the rock. • Specific retention – Sr: ratio of the volume of water in a rock can retain against gravity drainage to the total volume of the rock. • n = Sy + Sr. • Sr increases with decreasing grain size.
Darcy’s Law • Q = -KA(dh/dl). • dh/dl = Hydraulic gradient. • dh = change in head between two points separated by small distance dl.
Darcy’s Law: Yes Laminar flow (Small R < 10) Flow lines Darcy’s Law: No Flow lines Turbulent flow (Large R)
Hydraulic conductivity • K = hydraulic conductivity (L/T). • K is also referred to as the coefficient of permeability. • K = -Q[A(dh/dl)] [ L3/T/[L2(L/L)] = L/T] • V = Q/A = -K(dh/dl) = specific discharge or Darcian velocity.
Intrinsic Permeability • Intrinsic permeability Ki = Cd2 (L2). • K = Ki(γ/μ) or K = Ki(ρg/ μ) • Petroleum industry 1 Darcy = unit of intrinsic permeability Ki • 1 darcy = 1 cP x 1 cm3/s / (1 atm/ 1 cm). cP – centipoise - 0.01 dyn s/cm2 atm – atmospheric pressure – 1.0132 x 1016 dyn/cm2 • 1 darcy = 9.87 x 10-9 cm2 ~ 10-8 cm2
Aquifer • Aquifer – geologic unit that can store and transmit water at rates fast enough to supply amounts to wells. Usually, intrinsic permeability > 10-2 Darcy. • Confining layer – unit with little or no permeability … < 10-2 Darcy. aquifuge – absolutely impermeable unit. aquitard - a unit can store and transmit water slowly. Also called leaky confining layer. Raritan formation on Long Island. -- all these definitions are in a relative sense.
Transmissivity • The amount of water that can be transmitted horizontally through a unit width by the full saturated thickness of the aquifer under a hydraulic gradient of 1. • T = bK • T = transmissivity. • b = saturated thickness. • K = hydraulic conductivity. • Multilayer => T1 + T2 + … + Tn
Specific Storage • Specific storage Ss = amount of water per unit volume stored or expelled owing to compressibility of mineral skeleton and pore water per unit change in head (1/L). • Ss = ρwg(α+nβ) • α = compressibiliy of aquifer skeleton. • n = porosity. • β = compressibility of water.
Storativity of confined Unit S = b Ss • Ss = specific storage. • b = aquifer thickness. • All water released in confined, saturated aquifer comes from compressibility of mineral skeleton and pore water.
Storativity in Unconfined Unit • Changes in saturation associated with changes in storage. • Storage or release depends on specific yield Sy and specific storage Ss. • S = Sy + b Ss
Volume of water drained from aquifer • Vw = SAdh • Vw = volume of water drained. • S = storativity (dimensionless). • A = area overlying drained aquifer. • dh = average decline in head.
Hydraulic head, h • Hydraulic head is energy per unit weight. • h = v2/2g + z + P/gρ. [L]. • Unit: (L; ft or m). • v ~ 10-6 m/s or 30 m/y for ground water flows. • v2/2g ~ 10-12 m2/s2 / (2 x 9.8 m/s2) ~ 10-13 m. • h = z + P/gρ. [L].
Flow lines and flow nets • A flow line is an imaginary line that traces the path that a particle of ground water would flow as it flows through an aquifer. • A flow net is a network of equipotential lines and associated flow lines.
Boundary conditions • No-flow boundary – flow line – parallel to the boundary. Equipotential line - intersect at right angle. • Constant-head boundary – flow line – intersect at right angle. Equipotential line - parallel to the boundary. • Water-table boundary – flow line – depends. Equipotential line - depends.
Estimate the quantity of water from flow net • q’ = Kph/f. • q’ – total volume discharge per unit width of aquifer (L3/T; ft3/d or m3/d). • K – hydraulic conductivity (L/T; ft/d or m/d). • p – number of flowtubes bounded by adjacent pairs of flow lines. • h – total head loss over the length of flow lines (L; ft or m). • f - number of squares bounded by any two adjacent flow lines and covering the entire length of flow.
Water table • Water table = undulating surface at which pressure in fluid in pores = atmospheric pressure. Water table
Our purpose of well studies • Compute the decline in the water level, or drawdown, around a pumping well whose hydraulic properties are known. • Determine the hydraulic properties of an aquifer by performing an aquifer test in which a well is pumped at a constant rate and either the stabilized drawdown or the change in drawdown over time is measured.
Drawdown • T = Q/ 4(h0-h)G(u) • G(u) = W(u) - completely confined. W(u,r/B) – leaky, confined, no storage. H(u,) – leaky, confined, with storage. W(uA,uB,) - unconfined.
Aquifer test • Steady-state conditions. Cone of depression stabilizes. • Nonequilibrium flow conditions. Cone of depression changes. Needs a pumping well and at least one observational well.
Aquifer tests • T = Q/ 4(h0-h)G(u) • G(u) = W(u) - completely confined. W(u,r/B) – leaky, confined, no storage. H(u,) – leaky, confined, with storage. W(uA,uB,) - unconfined.
Slug test • Overdamped – water level recovers to the initial static level in a smooth manner that is approximately exponential. • Underdamped – water level oscillates about the static water level with the magnitude of oscillation decreasing with time until the oscillations cease.
Cooper-Bredehoeft-Papadopulos Method (confined aquifer) • H/H0 = F(,) • H – head at time t. • H0 – head at time t = 0. • = T t/rc2 • = rs2S/rc2
Underdamped Response Slug Test • Van der Kamp Method – confined aquifer and well fully penetrating. • H(t) = H0 e-t cos t H(t) - hydraulic head (L) at time t (T) H0 - the instantaneous change in head (L) - damping constant (T-1) - an angular frequency (T-1)
= 2/(t2-t1) • = ln[H(t1)/H(t2)]/ (t2 – t1)
Underdamped Response Slug Test (cont.) • T = c + a ln T c = -a ln[0.79 rs2S(g/L)1/2] a = [rc2(g/L)1/2] / (8d) d = /(g/L)1/2 L = g / (2 + 2)