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Bose-Einstein Statistics. Applies to a weakly-interacting gas of indistinguishable Bosons with: Fixed N = i n i Fixed U = i E i n i No Pauli Exclusion Principle: n i 0, unlimited Each group i has: g i states, g i -1 possible subgroups, n i to be shared between them
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RWL Jones, Lancaster University Bose-Einstein Statistics Applies to a weakly-interacting gas of indistinguishable Bosons with: Fixed N = ini Fixed U = iEini No Pauli Exclusion Principle: ni0, unlimited Each group i has: gi states, gi-1 possible subgroups, ni to be shared between them Number of combination to do this is: So number of microstates in distribution {ni} states:
RWL Jones, Lancaster University Bose-Einstein Statistics Classical limit: Bose-Einstein: Large numbers: gi, ni ni factors
RWL Jones, Lancaster University Bose-Einstein Distribution We use the same technique as for Boltzmann, maximize ln t({ni}) : d ln t ({ni}) = 0 Add to this the constraints: dN = 0 idni = 0 :(ii) dU = 0 i Ei dni = 0 :(iii) Once again, add the (i)+(ii)+(iii) (Lagrange) Thermodymanics gives =-1/kT
RWL Jones, Lancaster University Open and Closed Systems given by N=igiF(Ei) for a closed system of phoney bosons (e.g. ground state He4 atom (2p2n2e, each in up-down spin combinations) = -/kT Elementary bosons (not made up of fermions) do not conserve N – examples are photons and phonons These correspond to an open system – no fixed n no no
RWL Jones, Lancaster University Black Body Radiation Spectral Energy density is the energy in a photon gas between E and E+dE = U(E) dE Energy in photon gas for photons with frequencies between and + d= u() d= h F(E) g(E) dE = h F() g() d (from week 1homework) = h F() V 82/c3 d Planck Radiation Formula
RWL Jones, Lancaster University Black Body Radiation In terms of wavelength (= c/) u() u() h./kT~3 hc./kT~5
RWL Jones, Lancaster University Black Body Radiation max hc/5kT T = Tsun 6000Kmax 480 nm (yellow light) T = Troom 300Kmax 10 m (Infra-red) T = Tuniverse 3Kmax 1 mm (microwave background) Total Energy of Photon Gas:
RWL Jones, Lancaster University Radiation Pressure For massive particles: P = (2/3) (U/V) (because E ~ k2 and and k ~ V1/3) For massless particles E ~ K P = (1/3) (U/V)
RWL Jones, Lancaster University Classical Limit In Maxwell-Boltzmann limit, F(E)<<1, so exp( (E-)/(kBT) ) >> 1 So FMB(E) = exp( -(E-)/(kBT) ) = exp( /(kBT) ) exp( -(E/(kBT) ) = (N/Z) exp( -(E/(kBT) ) So N/Z = exp( /(kBT) ) So chemical potential = kBT ln(N/Z)