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I CAN solve and write whole-number and decimal addition equations.

I CAN solve and write whole-number and decimal addition equations. Vocabulary. inverse operations. h + 14. 82. h + 14. 82. h. h. 68. ?. The equation h + 14 = 82 can be represented as a balanced scale. To find the value of h, you need h by itself on one side of the scale.

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I CAN solve and write whole-number and decimal addition equations.

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  1. I CAN solve and write whole-number and decimal addition equations.

  2. Vocabulary inverse operations

  3. h + 14 82 h + 14 82 h h 68 ? The equation h + 14 = 82 can be represented as a balanced scale. To find the value of h, you need h by itself on one side of the scale. To get h by itself, first take away 14 from the left side of the scale. Now the scale is unbalanced. To rebalance the scale, take away 14 from the other side.

  4. Taking away 14 from both sides of the scale is the same as subtracting 14 from both sides of the equation. h + 14 – 14= 82 – 14 h = 68 Inverse operations undo each other. Addition and subtraction are inverse operations. If an equation contains addition, solve it by subtracting from both sides to “undo” the addition.

  5. ? 3. 65+ 87 = 152 ? 4. 152= 152 Example 1: Solving Addition Equations Solve the equation. Check your answer. A. x + 87 = 152 87 is added to x. Subtract 87 from both sides to undo the addition. 1. x + 87 – 87 = 152 – 87 2. x= 65 Check: Substitute 65 for x in the equation. 65 is the solution. 

  6. 3. 1.8 + 5.4= 7.2 ? ? 4. 7.2 = 7.2 Solve the equation. Check your answer. B. 1.8 + y = 7.2 1.8 is added to y. Subtract 1.8 from both sides to undo the addition. 7.2 –1.8 1. 1.8 –1.8 + y = 2. y= 5.4 Check: Substitute 5.4 for y in the equation.  5.4 is the solution.

  7. ? 3. 35+ 43 = 78 ? 4. 78= 78 You Try! Example 1 A. Solve the equation. Check your answer. u + 43 = 78 = 78 – 43 1. u + 43 – 43 2. u = 35 Check: 

  8. ? 3. 0.24 + 5.06 = 5.3 ? 4. 5.3= 5.3 You Try! Example 1 B. Solve the equation. Check your answer. 0.24 + g = 5.3 = 5.3 – 0.24 1. 0.24 – 0.24 + g 2. g = 5.06 Check: 

  9. Example 2: Social Studies Application Johnstown, Cooperstown, and Springfield are located in that order in a straight line along a highway. It is 12 miles from Johnstown to Cooperstown and 95 miles from Johnstown to Springfield. Find the distance d between Cooperstown and Springfield. distance between Johnstown and Springfield distance between Cooperstown and Springfield distance between Johnstown and Cooperstown = + 12 + d = 95 12 is added to d. 12 + d = 95 Subtract 12 from both sides to undo the addition. 12 – 12 d = 95 – 12 d = 83 It is 83 miles from Cooperstown to Springfield.

  10. You Try! Example 2 Patterson, Jacobsville, and East Valley are located in that order in a straight line along a highway. It is 1.7 miles from Patterson to Jacobsville and 3.5 miles from Patterson to East Valley. Find the distance d between Jacobsville and East Valley. distance between Patterson and Jacobsville distance between Jacobsville and East Valley distance between Patterson and East Valley + = 1.7 + d = 3.5 1.7 + d = 3.5 1.7 is added to d. Subtract 1.7 from both sides to undo the addition. 1.7 – 1.7 + d = 3.5 – 1.7 d = 1.8 It is 1.8 miles from Jacobsville to East Valley.

  11. Reflection CAN YOU solve and write whole-number and division addition equations?

  12. Lesson Quiz Solve each equation. Show all steps and check your answers. 1.x + 15 = 72 2.2.4 + x = 8.1 3.x + 22 = 67 4.0.14 + x = 0.93 x = 57 x = 5.7 x = 45 x = 0.79 5. Kaitlin is 2 inches shorter than Reba. Reba is 54 inches tall. How tall is Kaitlin? Write and solve an equation. 56 inches

  13. HOMEWORK WORKSHEET 2-5

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