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12-1. Inverse Variation. Warm Up. Lesson Presentation. Lesson Quiz. Holt Algebra 1. Warm Up Solve each proportion. 1. . 2. 4.2. 10. 3. 4. 2.625. 2.5.

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  1. 12-1 Inverse Variation Warm Up Lesson Presentation Lesson Quiz Holt Algebra 1

  2. Warm Up Solve each proportion. 1. 2. 4.2 10 3. 4. 2.625 2.5 5. The value of y varies directly with x, and y = –6 when x = 3. Find y when x = –4. 8 6. The value of y varies directly with x, and y = 6 when x = 30. Find y when x = 45. 9

  3. Objective Identify, write, and graph inverse operations.

  4. Vocabulary inverse variation

  5. A relationship that can be written in the form y = , where k is a nonzero constant and x ≠ 0, is an inverse variation. The constant k is the constant of variation. Inverse variation implies that one quantity will increase while the other quantity will decrease (the inverse, or opposite, of increase). Multiplying both sides of y = by x gives xy = k. So, for any inverse variation, the product of x and y is a nonzero constant.

  6. Remember! A direct variation is an equation that can be written in the form y = kx, where k is a nonzero constant.

  7. There are two methods to determine whether a relationship between data is an inverse variation. You can write a function rule in y = form, or you can check whether xy is a constant for each ordered pair.

  8. Can write in y = form. Example 1: Identifying an Inverse Variation Tell whether each relationship is an inverse variation. Explain. Method 1 Write a function rule. The relationship is an inverse variation. Method 2 Find xy for each ordered pair. 1(30) = 30, 2(15) = 30, 3(10) = 30 The product xy is constant, so the relationship is an inverse variation.

  9. Cannot write in y = form. Example 2: Identifying an Inverse Variation Tell whether each relationship is an inverse variation. Explain. Method 1 Write a function rule. y = 5x The relationship is not an inverse variation. Method 2 Find xy for each ordered pair. 1(5) = 5, 2(10) = 20, 4(20) = 80 The product xy is not constant, so the relationship is not an inverse variation.

  10. Example 3: Identifying an Inverse Variation Tell whether each relationship is an inverse variation. Explain. 2xy = 28 Find xy. Since xy is multiplied by 2, divide both sides by 2 to undo the multiplication. xy = 14 Simplify. xy equals the constant 14, so the relationship is an inverse variation.

  11. Cannot write in y = form. Example 4: Identifying an Inverse Variation Tell whether each relationship is an inverse variation. Explain. 2x + y = 10 The relationship is not an inverse variation.

  12. Helpful Hint Since k is a nonzero constant, xy ≠ 0. Therefore, neither x nor y can equal 0, and no solution points will be on the x- or y-axes.

  13. An inverse variation can also be identified by its graph. Some inverse variation graphs are shown. Notice that each graph has two parts that are not connected. Also notice that none of the graphs contain (0, 0). This is because (0, 0) can never be a solution of an inverse variation equation.

  14. Example: Graphing an Inverse Variation Write and graph the inverse variation in which y = 0.5 when x = –12. Step 1 Find k. k = xy Write the rule for constant of variation. = –12(0.5) Substitute –12 for x and 0.5 for y. = –6 Step 2 Use the value of k to write an inverse variation equation. Write the rule for inverse variation. Substitute –6 for k.

  15. x 1 2 4 –1 0 –4 –2 y 1.5 3 6 –1.5 –6 –3 undef. Example Continued Write and graph the inverse variation in which y = 0.5 when x = –12. Step 3 Use the equation to make a table of values.

  16. ● ● ● ● ● ● Example Continued Write and graph the inverse variation in which y = 0.5 when x = –12. Step 4 Plot the points and connect them with smooth curves.

  17. Example: Transportation Application The inverse variation xy = 350 relates the constant speed x in mi/h to the time y in hours that it takes to travel 350 miles. Determine a reasonable domain and range and then graph this inverse variation. Use the graph to estimate how long it will take to travel 350 miles driving 55 mi/h. Step 1 Solve the function for y so you can graph it. xy = 350 Divide both sides by x.

  18. x 20 40 60 80 y 17.5 8.75 5.83 4.38 Example Continued Step 2 Decide on a reasonable domain and range. Length is never negative and x ≠ 0 x > 0 Because x and xy are both positive, y is also positive. y > 0 Step 3 Use values of the domain to generate reasonable ordered pairs.

  19. ● ● ● ● Example Continued Step 4 Plot the points. Connect them with a smooth curve. Step 5 Find the y-value where x = 55. When the speed is 55 mi/h, the travel time is about 6 hours.

  20. Remember! Recall that sometimes domain and range are restricted in real-world situations.

  21. The fact that xy = k is the same for every ordered pair in any inverse variation can help you find missing values in the relationship.

  22. Let and Let y vary inversely as x. Find Substitute 2 for –4 for and –6 for Solve for by dividing both sides by –4. Check It Out!Example 5 Write the Product Rule for Inverse Variation. Simplify. Simplify.

  23. Substitute 400 for 125 for and 25 for Solve for by dividing both sides by 125. Example 6: Physics Application Boyle’s law states that the pressure of a quantity of gas x varies inversely as the volume of the gas y. The volume of gas inside a container is 400 in3 and the pressure is 25 psi. What is the pressure when the volume is compressed to 125 in3? Use the Product Rule for Inverse Variation. (400)(25) = (125)y2 Simplify.

  24. When the gas is compressed to 125 in3, the pressure increases to 80 psi. Example 6 Continued Boyle’s law states that the pressure of a quantity of gas x varies inversely as the volume of the gas y. The volume of gas inside a container is 400 in3 and the pressure is 25 psi. What is the pressure when the volume is compressed to 125 in3?

  25. Check It Out! Example 7 On a balanced lever, weight varies inversely as the distance from the fulcrum to the weight. The diagram shows a balanced lever. How much does the child weigh?

  26. Substitute 3.2 for , 60 for and 4.3 for Solve for by dividing both sides by 3.2. Check It Out! Example 7 Continued Use the Product Rule for Inverse Variation. Simplify. Simplify. The child weighs 80.625 lb.

  27. Lesson Quiz: Part I 1. Write and graph the inverse variation in which y = 0.25 when x = 12.

  28. Lesson Quiz: Part II 2. The inverse variation xy = 210 relates the length y in cm to the width x in cm of a rectangle with an area of 210 cm2. Determine a reasonable domain and range; then determine the length when the width is 14 cm.

  29. Lesson Quiz: Part III 3. Let x1= 12, y1 = –4, and y2 = 6, and let y vary inversely as x. Find x2. –8

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