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#32 A compound is formed when 9.03 grams Mg combines with 3.48 grams N. What is the percent composition of this compound?. The total weight is: 9.03 + 3.48 = 12.51. The percentage of Mg is: 9.03 x 100 = 72.2 % 12.51.
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#32 A compound is formed when 9.03 grams Mg combines with 3.48 grams N. What is the percent composition of this compound? The total weight is: 9.03 + 3.48 = 12.51 The percentage of Mg is:9.03 x 100 = 72.2 % 12.51 The percentage of N is:3.48 x 100 = 27.8 % 12.51
#33 When a 14.2 g sample of mercury (II) oxide is decomposed into its elements by heating, 13.2 g Hg is obtained. What is the percent composition of the compound? The total weight is: 14.2 grams The percentage of Hg is:13.2 x 100 = 93.0 % 14.2 The percentage of O is:1.0 x 100 = 7.0 % 14.2 The difference between the beginning and end weight is the oxygen
#34 Calculate the percent composition of these compounds. a. ethane (C2H6) The total molar mass of ethane is: (12.0 x 2) + (1.0 x 6) 30.0 g/mole The percentage of C is:24.0 x 100 = 80.0% 30.0 The percentage of H is:6.0 x 100 = 20.0 % 30.0
#34 Calculate the percent composition of these compounds. b. sodium bisulfate (NaHSO4) The total molar mass of (NaHSO4 is: 23.0 + 1.0+ 32.1 +(16.0 x 4)= 120.1 g/mole The percentage of Na is:23.0 x 100 = 19.2% 120.1 The percentage of H is:1.0 x 100 = .83% 120.1 The percentage of S is:32.1 x 100 = 26.7 % 120.1 The percentage of O is:64.0 x 100 = 53.3 % 120.1
#35 Calculate the percent nitrogen in these fertilizers. a. NH3 The total molar mass of (NH3 is: 14.0 + (1.0 x 3)= 17.0 g/mole The percentage of N is:14.0 x 100 = 82.4% 17.0 b. NH4NO3 The total molar mass of NH4NO3 is: 14.0+(1.0 x 4)+14+(16 x 3)= 80.0 g/mole The percentage of N is:28.0 x 100 = 35.0 % 80.0 Two nitrogens