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Lesson 3-4

Lesson 3-4. Derivatives of Trigonometric Functions. Objectives. Find the derivatives of trigonometric functions. Vocabulary. none new. Trig Differentiation Rules. d ---- (sin x) = cos x Sin dx d ---- ( cos x) = -sin x Cos dx

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Lesson 3-4

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  1. Lesson 3-4 Derivatives of Trigonometric Functions

  2. Objectives • Find the derivatives of trigonometric functions

  3. Vocabulary • none new

  4. Trig Differentiation Rules d ---- (sin x) = cos x Sin dx d ---- ( cos x) = -sin x Cos dx Rest of them can be done from these two and the Quotient rule!

  5. Rest of Trig Differentiation Rules d ---- [tan x] = sec² x dx d ---- (cot x) = -csc² x dx d ---- [sec x] = (sec x) • (tan x) dx d ---- (csc x) = -(csc x) • (cot x) dx

  6. Example 1 Find the derivatives of the following: y = sin x – cos x f(x) = (tan x) / (x + 1) y’(x) = cos x – (-sin x) = cos x + sin x (x + 1) (sec² x) – (1) (tan x) y’(x) = --------------------------------------- (x + 1)²

  7. Example 2 Find the derivatives of the following: y = sin (π/4) y = x³ sin x y’(x) = 0 y’(x) = 3x² (sin x) + x³ (cos x)

  8. Example 3 Find the derivatives of the following: • y = x² + 2x cos x • y = x / (sec x + 1) y’(x) = 2x + 2x (-sin x) + (2) (cos x) (sec x + 1) (1) – (sec x tan x) (x) y’(x) = ---------------------------------------------- (sec x + 1)²

  9. Example 4 Find the derivatives of the following: • y = x / (cot x) • y = (csc x) / ex (cot x) (1) – (-csc² x) (x) y’(x) = --------------------------------------- (cot x)² (ex) (-csc x cot x) – (ex) (csc x) y’(x) = --------------------------------------------- (ex)²

  10. Example 5 Find the derivatives of the following: sin x = (1/7) lim ----------- = (1/7) (1) = 1/7 x • sin x • lim ----------- 7x sin 5x • lim ----------- 5x x→0 x→0 sin u = lim ----------- = 1 u letting u = 5x x→0 u→0

  11. Example 6 A particle moves along a line so that at any time t>0 its position is given by x(t) = 2πt + cos(2πt). Find the velocity at time t. Find the speed (|v|) at t = ½. What are the values of t for which the particle is at rest? v(t) = x’(t) = 2π – 2π (sin 2πt) Speed = |v(1/2)| = |x’(t)| = |2π – 2π (sin π)| = 2π When v(t) = 0 = 2π – 2π (sin 2πt) 2π (sin 2πt) = 2π sin 2πt = 1  t = ¼, 5/4, 9/4, 13/4, etc

  12. Summary & Homework • Summary: • Use trig rules for finding derivatives • d(sin x) = cos x • d(cos x) = -sin x • Homework: • pg 216 – 217: 1-3, 6, 9-11, 18, 29, 41

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