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Net Ionic Equations

Net Ionic Equations. Section 4 Writing Net Ionic Equations. Chapter 8. Ionic Equations. Ionic compounds dissolve in water KI( aq ) = K + ( aq ) + I – ( aq ) Pb(NO 3 ) 2 ( aq ) = Pb 2+ ( aq ) + ( aq ). Reaction between KI and Pb(NO 3 ) 2

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Net Ionic Equations

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  1. Net Ionic Equations

  2. Section4 Writing Net Ionic Equations Chapter 8 Ionic Equations • Ionic compounds dissolve in water • KI(aq) = K+(aq) + I–(aq) • Pb(NO3)2(aq) = Pb2+(aq) + (aq) • Reaction between KI and Pb(NO3)2 • 2KI(aq) + Pb(NO3)2(aq)  PbI2(s) + 2KNO3(aq) • Total Ionic Equation • 2K+(aq) + 2I–(aq) + Pb2+(aq) + (aq) •  PbI2(s) + 2K+(aq) + (aq)

  3. Section4 Writing Net Ionic Equations Chapter 8 Ionic Equations, continued • Spectator ions remain unchanged in the solution as aqueous ions. They do not react. • 2K+(aq) + 2I–(aq) + Pb2+(aq) + (aq) •  PbI2(s) + 2K+(aq) + (aq) • The net ionic equationis the chemical equation that shows only the net change. • 2I–(aq) + Pb2+(aq)  PbI2(s)

  4. Section4 Writing Net Ionic Equations Chapter 8 Ionic Equations, continued • Net Ionic equations can be used for displacement reactions. • Zn(s) + Cu2+(aq) + (aq)  Cu(s) + Zn2+(aq) + (aq) • net ionic equation • Zn(s) + Cu2+(aq)  Cu(s) + Zn2+(aq)

  5. Section4 Writing Net Ionic Equations Chapter 8 Ionic Equations, continued • Check atoms and charge to balance net ionic equations. • (aq) + Ba2+(aq)  BaSO4(s) • Charge: (2–) + (2+) = 0 0 • Zn(s) + Cu2+(aq)  Cu(s) + Zn2+(aq) • Charge: 2+ 2+

  6. Chapter 8 Writing a Net Ionic Equation

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