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Question 1. 2 marks. Let the large number be x and the smaller number be y . Then:. Team Round Solutions. Therefore the ratio x : y is 48 : 40 = 6 : 5. Question 2. 2 marks. Team Round Solutions. y. 3 y. 30. Question 3. 4 marks. Team Round Solutions. Question 4. 2 marks.
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Question 1 2 marks Let the large number be x and the smaller number be y. Then: Team Round Solutions Therefore the ratio x : y is 48 : 40 = 6 : 5
Question 2 2 marks Team Round Solutions y 3y 30
Question 3 4 marks Team Round Solutions
Question 4 2 marks 2 A Team Round Solutions B E 6 C D
Question 5 4 marks Team Round Solutions The sequence is The four missing numbers are 7, 10, 20, 40 The sum of these numbers is 77
Question 6 4 marks Team Round Solutions 4 3 Ratio of smaller triangle to larger triangle is 3 : 7
Question 7 4 marks Team Round Solutions A: Pay only three quarters of the normal price! (25% discount) B: Buy two – get one free! C: Two for the price of four! (don’t shop here!) D: One fifth off all prices! (20% discount) E: 30% price cut (30% discount) Answer: B
6 marks Question 8 Team Round Solutions Ratio of shaded to unshaded area
Question 9 6 marks Team Round Solutions For third set of scales we have 11 squares are needed ?
Question 10 4 marks Team Round Solutions C 9 cm 15 cm 12 cm 9 cm A B D
Question 11 6 marks The angle Jill moves through before they meet is given by Jill Jack Team Round Solutions Therefore Jack moves through 225° before they meet. 30 s
Question 12 6 marks Splitting the regular hexagon into 6 congruent triangles as shown below Team Round Solutions A B Area of kite ABCE C F D E
or Question 13 8 marks The coordinates of the image become (-x, -y) Team Round Solutions If rotated 180° about the origin this becomes (3, 4) O (-3, -4)
Question 14 8 marks Let the fraction of the chocolate bar that Pinkie has eaten be x then Perky has eaten Team Round Solutions The remaining fractions of the chocolate bar uneaten are Pinkie Perky When Perky has two times as much as has Pinkie we have
8 marks Question 15 Adding the following lines to the diagram so that we have pairs of congruent triangles. Team Round Solutions X C x B x O y y Y A
6 marks Question 16 For the cheetah For the snail Team Round Solutions distance = speed × time 2 1
C Question 17 10 marks B r The hypotenuse of the triangle is A Team Round Solutions C Now consider triangle ABC and we can deduce the missing lengths AC and BC and apply Pythagoras theorem again. 2 B r A 2
Question 18 12 marks Team Round Solutions