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PRECALCULUS 2/20/14

PRECALCULUS 2/20/14 OBJECTIVE: Find areas of oblique triangles and use the Law of Sines to model and solve real-world problems. HW: A nswer Practice Test. Due tomorrow. Answer 6.1 odds 35-47. Due Monday. Test 3 is on Monday. ACTIVITIES: Do Now: Copy in your math notebook.

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PRECALCULUS 2/20/14

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  1. PRECALCULUS 2/20/14 OBJECTIVE: Find areas of oblique triangles and use the Law of Sines to model and solve real-world problems. HW: Answer Practice Test. Due tomorrow. Answer 6.1 odds 35-47. Due Monday. Test 3 is on Monday. ACTIVITIES: Do Now: Copy in your math notebook. Recall: Area = ½ (base)(height) or or C A b a b c h h A C B B c a

  2. Find the area of the triangle having the given measurements. Round to the nearest square unit. C = 1150 , a = 5 yards, b = 7 yards 7 square yards C) 32 square yards 16 square yards D) 63 square yards Solution: Area = ½ a b sin C = ½ (5)(7) sin 1150 = 15.86  16 yards

  3. A guy wire to a tower makes a 670 angle with level ground. At a point 33 feet farther from the tower than the wire but on the same side as the base of the wire, the angle of elevation to the top of the tower is 380 . Find the length of the wire to the nearest foot. A) 42 feet B) 47 feet C) 84 feet D) 89 feet Solution: 290 x 670 380 1130 Answer: The length of the wire is 42 feet. 33

  4. Two tracking stations are on the equator 158 miles apart. A weather balloon is located on a bearing of N340E from the western station and on a bearing of N220W from the eastern station. How far is the balloon from the western station? Round to the nearest mile. A) 158 miles B) 149 miles C) 177 miles D) 186 miles Solution: balloon 560 x Answer: The balloon is 177 miles from the western station. 220 340 680 560 western station 158 mi eastern station

  5. A surveyor standing 54 meters from the base of a building measures the angle to the top of the building and finds it to be 370. The surveyor then measures the angle to the top of the radio tower on the building and finds that it is 490. How tall is the tower? A) 8.26 meters B) 7.7 meters C) 11.48 meters D) 21.43 meters

  6. To find the distance AB across a river, a distance BC of 531 m is laid off on one side of the river. It is found that B = 105.90 and C = 12.80. Find AB. Round to the nearest meter. A) 115 meters B) 118 meters C) 137 meters D) 134 meters

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