1 / 8

Stats

Stats. Section 5.6 Notes. Review of Binomial Probability Distribution. Introduced in section 4.3: 1. The procedure must have a fixed number of trials 2. The trials must be independent 3. Each trial must have all outcomes classified into two categories.

sorcha
Download Presentation

Stats

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Stats Section 5.6 Notes

  2. Review of Binomial Probability Distribution • Introduced in section 4.3: • 1. The procedure must have a fixed number of trials • 2. The trials must be independent • 3. Each trial must have all outcomes classified into two categories. • 4. The probabilities must remain constant for each trial. • Our example was of a multiple choice test.

  3. Normal Distribution as Approximation to Binomial Distribution • If , then the binomial random variable has a probability distribution that can be approximated by a normal distribution with the mean and standard deviation given as:

  4. Continuity Correction • When we use the normal distribution (which is a continuous probability distribution) as an approximation to the binomial distribution (which is discrete), a continuity correction is made to a discrete whole number x in the binomial distribution by representing the single value x by the interval from • x - 0.5 to x + 0.5

  5. Example • Recently, American Airlines had 72.3% of its flights arriving on time. In a check of 40 randomly selected American Airlines flights, 19 arrived on time. Estimate the probability of getting 19 or fewer on-time flights among 40, assuming that the 72.3% rate is correct. Is it unusual to get 19 or fewer on-time flights among 40 randomly selected American Airlines flights?

  6. Let x = the number that arrive on time • n = 40 and p = .723 therefore q = .277 • np = 28.92 which is • nq = 11.08 which is • So we can use the normal distribution as an approximation to binomial. Therefore:

  7. Therfore: • Yes it would be an unusual even to get 19 or fewer on-time flights because .0004 < .05

  8. Question! • How would things change if the problem asked about 19 or more flights?

More Related