1 / 8

Review 5.1 to 5.3

Review 5.1 to 5.3. Practice for Quiz. Lesson Quiz: Part I Variation. 1. The volume V of a pyramid varies jointly as the area of the base B and the height h , and V = 24 ft 3 when B = 12 ft 2 and h = 6 ft. Find B when V = 54 ft 3 and h = 9 ft. 18 ft 2.

spike
Download Presentation

Review 5.1 to 5.3

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Review 5.1 to 5.3 Practice for Quiz

  2. Lesson Quiz: Part I Variation 1. The volume V of a pyramid varies jointly as the area of the base B and the height h, and V = 24 ft3 when B = 12 ft2 and h = 6 ft. Find B when V = 54 ft3 and h = 9 ft. 18 ft2 2. The cost per person c of chartering a tour bus varies inversely as the number of passengers n. If it costs $22.50 per person to charter a bus for 20 passengers, how much will it cost per person to charter a bus for 36 passengers? $12.50

  3. 40 k k 10 x x Example 3 Given: y varies inversely as x, and y = 4 when x = 10. Write and graph the inverse variation function. y = y varies inversely as x. Substitute 4 for y and 10 for x. 4= k =40 Solve for k. Write the variation formula. y=

  4. Example 3Continued To graph, make a table of values for both positive and negative values of x. Plot the points, and connect them with two smooth curves. Because division by 0 is undefined, the function is undefined when x = 0.

  5. (2x + 1)(3x + 2) 6x2 + 7x + 2 (2x + 1) (3x + 2)(2x – 3) 6x2 – 5x – 5 (2x – 3) 5.2 Simplifying Rational Expressions Example 1 Simplify. Identify any x-values for which the expression is undefined. Factor; then divide out common factors. = The expression is undefined at ????

  6.    1 10x3y4 3x5y3 x – 3 3x5y3 x – 3 10x3y4 x + 5 x + 5 5x3 4(x + 3) (x – 3)(x + 3) 4x+ 20 4(x+ 5) x2 – 9 9x2y5 2x3y7 2x3y7 9x2y5 3y5 Example 2: Multiplying Rational Expressions Multiply. Assume that all expressions are defined. A. B. 3 5 3

  7. ÷   4(x – 4) 4(2x – 1)(x – 3) 4(2x2 – 7x + 3) (2x + 1)(x – 4) (2x+ 1)(x – 4) 8x2 – 28x +12 2x2– 7x – 4 2x2– 7x – 4 4x2– 1 (x +3) (2x + 1)(2x – 1) (2x + 1)(2x – 1) 8x2 – 28x +12 (x + 3)(x – 3) (x + 3)(x – 3) x2 – 9 x2 – 9 4x2– 1  Dividing: Example Divide. Assume that all expressions are defined.

  8. x2 – 3x – 10 = 7 x –2 = 7 (x+ 5)(x – 2) (x – 2) Example 5: Solving Simple Rational Equations Solve. Check your solution. Note that x ≠ 2. x + 5 = 7 x = 2 Because the left side of the original equation is undefined when x = 2, there is no solution.

More Related