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Learn about the different elements of circles, including interior and exterior angles, chords, tangents, and their relationships. Explore calculations and examples to deepen your understanding.
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Vocabulary • Interior • Exterior • Radius • Diameter • Chord • Secant • Tangent
chords VT and WR secant: VT tangent: s diam.: WR radii: QW and QR Lesson Quiz: Part I 1. Identify each line or segment that intersects Q.
Circles • Congruent • Concentric • Tangent • Internally tangent • Externally tangent
Tangents • Tangent • Perpendicular to radius • Example: Visible distance to horizon from Mt Everest • Mt Everest is 29,000 ft above sea level • Find: EH • 2 tangents from external point • Same measure
12-2 Arcs & Chords • Types of Arcs • Minor Arc • < 180o • Major Arc • >180o • Semi-Circle • = 180o • Central Angle: a angle whose vertex is at the center of a circle
b. mAHB a. mFMC mFMC = 0.30(360) = 108 Central is 30% of the . = 360° – mAMB = 0.10(360) c. mEMD mAHB =360° –0.25(360) = 36 = 270 Central is 10% of the .
Solving for Arcs: • Adjacent Arcs: • Arc Addition Postulate:
mJKL mKL = 115° mJKL = mJK + mKL Find each measure. mLJN mKPL = 180° – (40 + 25)° Arc Add. Post. = 25° + 115° Substitute. = 140° Simplify.
Congruent Arcs – 2 Arcs with the same measure • Central Angles • Chords
Congruent Arcs • Examples • Find RT • Find mCD
Radii & Chords • If radius is perpendicular to chord • Bisects Chord & Arc • A perpendicular bisector of chord is a radius
Step 1 Draw radius RN. RM NP , so RM bisects NP. Using Radii and Chords Find NP. RN = 17 Radii of a are . Step 2 Use the Pythagorean Theorem. SN2 + RS2 = RN2 SN2 + 82 = 172 Substitute 8 for RS and 17 for RN. SN2 = 225 Subtract 82 from both sides. SN= 15 Take the square root of both sides. Step 3 Find NP. NP= 2(15) = 30
Step 1 Draw radius PQ. PS QR , so PS bisects QR. Find QR to the nearest tenth. PQ = 20 Radii of a are . Step 2 Use the Pythagorean Theorem. TQ2 + PT2 = PQ2 TQ2 + 102 = 202 Substitute 10 for PT and 20 for PQ. TQ2 = 300 Subtract 102from both sides. TQ 17.3 Take the square root of both sides. Step 3 Find QR. QR= 2(17.3) = 34.6
Inscribed Angles • Inscribed angle • Vertex on circle • Sides contain chords • Measure of inscribed angle = ½ measure of arc • m<E = ½(mDF)
Inscribed Angles • If inscribed angle arcs are congruent • Intercept same arc or congruent arcs • THEN: Inscribed angles are congruent
Example • Find mBC • Find m<ECD • Find m<DEC
Example 2: Hobby Application An art student turns in an abstract design for his art project. Find mDFA. mDFA= mDCF + mCDF = 115°
Inscribed Angle • Inscribed angle subtends a semicircle if and only if the angle is a right angle • Example:
Quadrilaterals • Opposite Angles Add to 180
Example: Finding Angle Measures in Inscribed Quadrilaterals Find the angle measures of GHJK. Step 1 Find the value of b.
Angle Relationships • Tangent and a secant/chord • Measure of angle is ½ intercepted arc measure • Measure of the arc is twice the measure of angle • Example: • Find m<BCD • Find measure of arc AB
Interior Angle • Intersect inside circle • Measure of vertical angles is ½ sum of arcs • Example: • Find m<PQT
Examples • Find x 1. 2. 3.
4. Find mCE. 12°
Sectors & Arc LengthGeometry 12.3 • Sector of a circle – 2 radii & arc • The pie shaped slice of the circle • Area of sector is percent area of circle based on arc or central angle: • A= Area, r= radius, m= measure of arc/angle
Segments of Circles • Segment of circle • Area of arc bounded by chord • Finding Area of Segment
Segment Examples Segment: • segment RST - segment DEF Area sector-Area of Triangle
Arc Length • Distance along the arc (circumference) • Measured in linear units • L= length, r= radius, m= measure of arc/angle • Example: • Measure of GH
J Segment RelationshipsGeometry 12.6 J Example:
Example: Art Application The art department is contracted to construct a wooden moon for a play. One of the artists creates a sketch of what it needs to look like by drawing a chord and its perpendicular bisector. Find the diameter of the circle used to draw the outer edge of the moon.
Example 2 Continued 8(d – 8) = 9 9 8d – 64 = 81 8d = 145
External Secant Relationships Example:
External Tan/Sec Relationship Example:
Lesson Review: Part I 1. Find the value of d and the length of each chord. d = 9 ZV = 17 WY = 18 2. Find the diameter of the plate.
Lesson Review: Part II 3. Find the value of x and the length of each secant segment. x = 10 QP = 8 QR = 12 4. Find the value of a. 8
Equation for CircleGeometry 12.7 & Algebra 2 12.2 • (x– h)2 + (y – k)2 = r2 • h is the x coordinate of the center point • k is the y coordinate of the center point • r is the radius • To determine if point is inside/on/outside • Plug x and y of point into circle equation • h & k are the CENTER POINT coordinates • Compare result to r2 • If < pt is inside : if > pt is outside : if = pt is on
Distance Example: Consumer Application Use the map and information given in Example 3 on page 730. Which homes are within 4 miles of a restaurant located at (–1, 1)? The circle has a center (–1, 1) and radius 4. The points insides the circle will satisfy the inequality (x + 1)2 + (y – 1)2 < 42. Points B, C, D and E are within a 4-mile radius . Check Point F(–2, –3) is near the boundary. (–2 + 1)2 + (–3 – 1)2 < 42 (–1)2 + (–4)2 < 42 x Point F (–2, –3) is not inside the circle. 1 + 16 < 16
Finding center & radius • Given 2 endpoints • Find center point • X coordinate is (x1+x2)/2 • Y coordinate is (y1+y2)/2 • Use center point coordinate and one end point with the distance formula to find the radius • Plug center point and radius into equation for circle
Slope of Tangent • Slope of radius = Rise over Run (ΔY ÷ ΔX) • Find negative reciprocal • Change sign, flip fraction • Insert negative reciprocal into slope formula • Y = mx + b • Substitute y & x coords from tangent point to find b • Rewrite equation with y & x and the b value
From the equation x2 + y2 = 29, the circle has center of (0, 0) and radius r = . Example: Writing the Equation of a Tangent Write the equation of the line tangent to the circle x2 + y2 = 29 at the point (2, 5). Step 1 Identify the center and radius of the circle.
2 – 5 5 2 The slope of the radius is . Because the slopes of perpendicular lines are negative reciprocals, the slope of the tangent is . Tangent Example Continued Step 2 Find the slope of the radius at the point of tangency and the slope of the tangent. Use the slope formula. Substitute (2, 5) for (x2 , y2 ) and (0, 0) for (x1 , y1 ).
Step 3 Find the slope-intercept equation of the tangent by using the point (2, 5) and the slope m = . 2 – 5 Substitute (2, 5) (x1 , y1 ) and – for m. 2 5 Tangent Example Continued Use the point-slope formula. Rewrite in slope-intercept form.
The equation of the line that is tangent to x2 + y2 = 29 at (2, 5) is Tangent Example Continued Check Graph the circle and the line.