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Electric Fields, Voltage, Electric Current, and Ohm’s Law. ISAT 241 Fall 2003 David J. Lawrence. Properties of Electric Charges. Two kinds of charges. Unlike charges attract, while like charges repel each other. The force between charges varies as the inverse square of their separation:
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Electric Fields, Voltage, Electric Current, and Ohm’s Law ISAT 241 Fall 2003 David J. Lawrence
Properties of Electric Charges • Twokinds of charges. Unlike charges attract, while like charges repel each other. • The force between charges varies as the inversesquare of their separation: F µ 1/r2. • Charge is conserved. It is neither created nor destroyed, but is transferred. • Charge is quantized. It exists in discrete “packets”: q = +/- N e, where N is some integer.
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.2
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.2
Properties of Electric Charges • “Electric charge is conserved” means that objects become “charged” when charges (usually electrons) move from one neutral object to another. • This movement results in • a Net Positivecharge on one object, and • a Net Negativecharge on the other object.
Properties of Electric Charges • Neutral, uncharged matter contains as many positive charges as negative charges. • Net charge is caused by an excess (or shortage) of charged particles of one sign. • These particles are protons and electrons.
Properties of Electric Charges • Charge of an electron = -e = -1.6 ´ 10-19 C • Charge of a proton = +e = +1.6 ´ 10-19 C • “C” is the Coulomb. • Charge is Quantized! • Total Charge = N ´ e = N´ 1.6 ´ 10-19 C where N is the number of positive charges minus the number of negative charges. • But, for large enough N, quantization is not evident.
Electrical Properties of Materials • Conductors: materials in which electric charges move freely, e.g., metals. • Insulators: materials that do not readily transport charge, e.g., most plastics, glasses, and ceramics.
Electrical Properties of Materials • Semiconductors: have properties somewhere between those of insulators and conductors, e.g., silicon, germanium, gallium arsenide, zinc oxide. • Superconductors: “perfect” conductors in which there is no “resistance” to the movement of charge, e.g., some metals and ceramics at low temperatures: tin, indium, YBa2Cu3O7
Coulomb’s Law • The electric force between two charges is given by: (newtons, N) • Attractive if q1 and q2 have opposite sign. • Repulsive if q1 and q2 have same sign. • r = separation between the two charged particles. • ke = 9.0 x 109 Nm2/C2 = Coulomb Constant.
Coulomb’s Law • Force is avector quantity. =electric force exerted by q1 on q2 • r12 = unit vector directed from q1 to q2 Ù
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.9
y mo g Gravitational Field • Consider the uniform gravitational field near the surface of the earth • If we have a = small “test mass” mo , the force on that mass is Fg = mo g • We define the gravitational field to be Recallthat g = | g | = 9.8 m/s2
q FE q >> qo qo The Electric Field • The electric field vector E at a point in space is defined as the electric force FE acting on a positive “Test Charge” placed at that point, divided by the magnitude of the test charge qo.
q FE q >> qo qo The Electric Field • Units: • ~newtons/coulomb, N/C
Serway & Jewett, Principles of Physics, 3rd ed. See Figure 19.11
E - + FE FE The Electric Field • In general, the electric force on a charge qo in an electric field E is given by
The Electric Field • E is the electric field produced by q, not the field produced by qo. • Direction of E = direction of FE (qo > 0). • qo << |q| • We say that an electric field exists at some point if a test charge placed there experiences an electric force.
q q qo E E qo |q| >> qo q >> qo The Electric Field • For this situation, Coulomb’s law gives: FE = |FE| = ke (|q||qo|/r2) • Therefore, the electric field at the position of qo due to the charge q is given by: E = |E| = |FE|/qo = ke (|q|/r2)
y mo g Gravitational Field Lines • Consider the uniform gravitational field near the surface of the earth = g • If we have a small “test mass” mo , the force on that mass is Fg = mo g • We can use gravitational field lines as an aid for visualizing gravitational field patterns. Recallthat g = | g | = 9.8 m/s2
Electric Field Lines • An aid for visualizing electric field patterns. • Point in the same direction as the electric field vector, E, at any point. • E is large when the field lines are close together, E is small when the lines are far apart.
Electric Field Lines • The lines begin on positive charges and terminate on negative charges, or at infinity in the case of excess charge. • The number of lines leaving a positive charge or approaching a negative charge is proportional to the magnitude of the charge. • No two field lines can cross. • E is in the direction that a positive test charge will tend to go.
+ Electric Field Lines • The lines begin on positive charges and terminate on negative charges, or at infinity in the case of excess charge.
- Electric Field Lines • The lines terminate on negative charges.
Electric Field Lines • More examples Field lines cannot cross!
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.17
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.18
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.19
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.20 See the discussion about this figure on page 683 in your book.
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.21 See Example 19.6 on page 684 in your book.
Serway & Jewett, Principles of Physics, 3rd ed. Figure 19.22 See Example 19.7 on page 685 in your book.
Work Done by a Constant Force (Review) • Fluffy exerts a constant force of 12N to drag her dinner a distance of 3m across the kitchen floor. • How much work does Fluffy do?
q Work Done by a Constant Force (Review) • Ingeborg exerts a constant force of 12N to drag her dinner a distance of 3 m across the kitchen floor. • q = 30o • How much work does Ingeborg do?
Similar to Serway & Jewett, Principles of Physics, 3rd ed. Figure 6.1 See page 179 in your book.
Work Done by a Force (Review) • Is there a general expression that will give us the work done, whether the force is constant or not? • Yes! • Assume that the object that is being moved is displaced along the x-axis from xi to xf. • Refer to Figure 6.7 and Equation 6.11 on p. 184. • = area under graph of Fx from xi to xf
y a ya mo d g mo yb b Gravitational Field • Consider the uniform gravitational field near the surface of the earth = g • Recall that g = | g | = 9.8 m/s2 Suppose we allow a “test mass” mo to fall from a to b, a distance d.
y a ya mo Suppose we allow a “test mass” mo to fall from a to b, a distance d . d g mo yb b Gravitational Field • How much work is done by the gravitational field when the test mass falls?
E Electric Field • A uniform electric field can be produced in the space between two parallel metal plates. • The plates are connected to a battery.
Serway & Jewett, Principles of Physics, 3rd ed. Figure 20.3
E qo qo a b d Electric Field • How much work is done by the electric field in moving a positive test charge (qo) from a to b?
E qo qo a b d Electric Field • Recall that FE = qo E • Magnitude of displacement = d
Potential Difference = Voltage • Definition • The Potential Difference or Voltage between points a and b is always given by • =(work done by E to move test chg. from a to b) • (test charge) • This definition is true whether E is uniform or not.
Potential Difference = Voltage • For the special case of parallel metal plates connected to a battery -- • The Potential Difference between points a and b is given by • This is also called the Voltage between points a and b. • Remember, E is assumed to be uniform.
Potential Difference = Voltage • We need units! • Potential Difference between points a & b ºVoltage between points a & b
Potential Difference = Voltage • More units! • Recall that for a uniform electric field so In your book’s notation: Where d is positive when the displacement is in the same direction as the field lines are pointing.
Potential Difference = Voltage • In the general case • = a “path integral” or “line integral” • Therefore
Potential Difference = Voltage • If E, FE, and the displacement are all along the x-axis, this doesn’t look quite so imposing! • So