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Dive into the world of algebra with this comprehensive lesson plan covering verbal to algebraic expressions, solving equations, and identifying properties of equality. Practice with examples and standardized test questions included.
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Five-Minute Check (over Lesson 1–2) Then/Now New Vocabulary Example 1: Verbal to Algebraic Expression Example 2: Algebraic to Verbal Sentence Key Concept: Properties of Equality Example 3: Identify Properties of Equality Key Concept: Addition and Subtraction / Multiplication and Division Properties of Equality Example 4: Solve One-Step Equations Example 5: Solve a Multi-Step Equation Example 6: Solve for a Variable Example 7: Standardized Test Example Lesson Menu
A B C D A. naturals (N), wholes (W), integers (Z) B. wholes (W), integers (Z), reals (R) C. naturals (N), wholes (W), rationals (Q), reals (R) D. naturals (N), wholes (W), integers (Z), rationals (Q), reals (R) 5-Minute Check 1
A B C D A. naturals (N), wholes (W) B. reals (R) C. rationals (Q), reals (R) D. integers (Z), reals (R) 5-Minute Check 2
A B C D Name the property illustrated by a + (7 + c) = (a + 7) + c. A. Associative Property of Addition B. Distributive Property C. Substitution Property D. Commutative Property of Addition 5-Minute Check 3
A B C D Name the property illustrated by3(4 + 0.2) = 3(4) + 3(.02). A. Associative Property of Addition B. Identity Property C. Distributive Property D. Substitution Property 5-Minute Check 4
A B C D Simplify (2c)(3d) + c + 5cd + 3c2. A. 3c2 + 5cd + c B. 3c2 + 11cd + c C. 3c2 + 10cd D. 3c2 + c 5-Minute Check 5
A B C D A.5 + 0 = 5 B.5(1) = 5 C.5 + (–5) = 0 D. Which equation illustrates the Additive Identity Property? 5-Minute Check 6
You used properties of real numbers to evaluate expressions. • Translate verbal expressions into algebraic expressions and equations, and vice versa. • Solve equations using the properties of equality. Then/Now
open sentence • equation • solution Vocabulary
Verbal to Algebraic Expression A. Write an algebraic expression to represent the verbal expression 7 less than a number. Answer:n – 7 Example 1
Verbal to Algebraic Expression B. Write an algebraic expression to represent the verbal expression the square of a number decreased by the product of 5 and the number. Answer:x2 – 5x Example 1
A B C D A. Write an algebraic expression to represent the verbal expression 6 more than a number. A. 6x B.x + 6 C.x6 D.x – 6 Example 1a
A B C D B. Write an algebraic expression to represent the verbal expression 2 less than the cube of a number. A.x3 – 2 B. 2x3 C.x2 – 2 D. 2 + x3 Example 1b
Algebraic to Verbal Sentence A. Write a verbal sentence to represent 6 = –5 + x. Answer: Six is equal to –5 plus a number. Example 2
Algebraic to Verbal Sentence B. Write a verbal sentence to represent 7y – 2 = 19. Answer: Seven times a number minus 2 is 19. Example 2
A B C D A. What is a verbal sentence that represents the equation n – 3 = 7? A. The difference of a number and 3 is 7. B. The sum of a number and 3 is 7. C. The difference of 3 and a number is 7. D. The difference of a number and 7 is 3. Example 2a
A B C D B. What is a verbal sentence that represents the equation 5 = 2 + x? A. Five is equal to the difference of 2 and a number. B. Five is equal to twice a number. C. Five is equal to the quotient of 2 and a number. D. Five is equal to the sum of 2 and a number. Example 2b
Identify Properties of Equality A. Name the property illustrated by the statement. a – 2.03 = a – 2.03. Answer: Reflexive Property of Equality Example 3
Identify Properties of Equality B. Name the property illustrated by the statement. If 9 = x, then x = 9. Answer: Symmetric Property of Equality Example 3
A B C D A. What property is illustrated by the statement? If x + 4 = 3, then 3 = x + 4. A. Reflexive Property of Equality B. Symmetric Property of Equality C. Transitive Property of Equality D. Substitution Property of Equality Example 3a
A B C D B. What property is illustrated by the statement? If 3 = x and x = y, then 3 = y. A. Reflexive Property of Equality B. Symmetric Property of Equality C. Transitive Property of Equality D. Substitution Property of Equality Example 3b
? 5.5 – 5.48 = 0.02 Substitute 5.5 for m. Solve One-Step Equations A.Solve m – 5.48 = 0.02. Check your solution. m – 5.48 = 0.02 Original equation m – 5.48 + 5.48 = 0.02 + 5.48 Add 5.48 to each side. m = 5.5 Simplify. Check m – 5.48 = 0.02 Original equation 0.02 = 0.02 Simplify. Answer: The solution is 5.5. Example 4
Solve One-Step Equations Original equation Simplify. Example 4
Check Original equation ? Solve One-Step Equations Substitute 36 for t. Simplify. Answer: The solution is 36. Example 4
A B C D A. What is the solution to the equation x + 5 = 3? A. –8 B. –2 C. 2 D. 8 Example 4a
A B C D B. What is the solution to the equation A.5 B. C.15 D.30 Example 4b
Solve a Multi-Step Equation Solve 53 = 3(y – 2) – 2(3y – 1). 53 = 3(y – 2) – 2(3y – 1) Original equation 53 = 3y – 6 – 6y + 2 Apply the Distributive Property. 53 = –3y – 4 Simplify the right side. 57 = –3y Add 4 to each side. –19 = y Divide each side by –3. Answer: The solution is –19. Example 5
A B C D A.–6 B. C. D.6 What is the solution to 25 = 3(2x + 2) – 5(2x + 1)? Example 5
Solve for a Variable Area formula Subtract πr2 from each side. Simplify. Example 6
Solve for a Variable Divide each side by πr. Simplify. Example 6
A B C D GEOMETRY The formula for the perimeter of a rectangle is where P is the perimeter, and w is the width of the rectangle. What is this formula solved for w? A. B. C. D. Example 6a
AB CD Read the Test Item You are asked to find the value of the expression 4g – 2. Your first thought might be to find the value of g and then evaluate the expression using this value. Notice that you are not required to find the value of g. Instead, you can use the Subtraction Property of Equality. Example 7
Solve the Test Item Original equation Subtract 7 from each side. Simplify. Answer: C Example 7
A B C D If 2x + 6 = –3, what is the value of 2x – 3? A. 12 B. 6 C. –6 D. –12 Example 7