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5 .2 Solving Systems Using Substitution

Learn how to solve systems of linear equations by using substitution. Isolate one variable and substitute its expression into the other equation for quick solving. Practice with examples.

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5 .2 Solving Systems Using Substitution

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  1. 5.2 Solving Systems Using Substitution I can solve systems of linear equations by using substitution.

  2. Solve one of the equations for one of the variables. • Isolate one of the variables in one of the equations. • Choose whichever seems easiest. • Substitute the expression for the variable in the other equation. • Use substitution when a system has at least one equation that can be solved quickly for one of the variables. How to Use Substitution

  3. Solve the following system: • 3y + 4x = 14 • -2x + y = -3 • The second equation looks easiest to solve for y • So y = 2x – 3 • Substitute 2x – 3 for y in the other equation • 3(2x – 3) + 4x = 14 • Solve for x • x = 2.3 • Now substitute 2.3 for x in either equation • y = 1.6 • The solution is (2.3, 1.6) Practice

  4. Solve the following system by substituting: • y = 3x and x + y = -32 • (-8, -24) Try This

  5. Solve the system using substitution • 6y + 5x = 10 • x + 3y = -7 • (8, -5) You Try

  6. A large snack pack costs $5 and a small costs $3. If 60 snack packs are sold, for a total of $220, How many were large and how many were small? • Let x = large and y = small • Money: 5x + 3y = 220 • Amount sold: x + y = 60 • Solve: (20, 40) • 20 large and 40 small Using Systems

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