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Acceleration

Acceleration. A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = V 2 = A = D = T =. Acceleration. A car starts from rest and accelerates at a rate of 6.1 m/s 2 for 7 seconds. Calculate how far it traveled. V 1 = 0 m/s.

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Acceleration

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  1. Acceleration • A car starts from rest and accelerates at a rate of 6.1 m/s2for 7 seconds. Calculate how far it traveled. • V1 = • V2 = • A = • D = • T =

  2. Acceleration • A car starts from rest and accelerates at a rate of 6.1 m/s2for 7 seconds. Calculate how far it traveled. • V1 = 0 m/s

  3. Acceleration • A car starts from rest and accelerates at a rate of 6.1 m/s2for 7 seconds. Calculate how far it traveled. • V1 = 0 m/s • V2 = no

  4. Acceleration • A car starts from rest and accelerates at a rate of 6.1 m/s2for 7 seconds. Calculate how far it traveled. • V1 = 0 m/s • V2 = no • A = 6.1 m/s2

  5. Acceleration • A car starts from rest and accelerates at a rate of 6.1 m/s2for 7 seconds. Calculate how far it traveled. • V1 = 0 m/s • V2 = no • A = 6.1 m/s2 • D = ?

  6. Acceleration • A car starts from rest and accelerates at a rate of 6.1 m/s2for 7 seconds. Calculate how far it traveled. • V1 = 0 m/s • V2 = no • A = 6.1 m/s2 • D = ? • T = 7 sec.

  7. Solution #1 • D = V1t + at2 2

  8. Solution #1 • D = ½ at2 • D = (6.1 m/s2)(7 sec)2 2

  9. Solution #1 • D = ½ at2 • D = (6.1 m/s2)(7 sec)2 2 • D = 150 m

  10. Acceleration #2 • What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s2 and comes to rest in 484 m? • V1= • V2= • A = • D = • T =

  11. Acceleration #2 • What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s2 and comes to rest in 484 m? • V1 = ?

  12. Acceleration #2 • What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s2 and comes to rest in 484 m? • V1 = ? • V2 = 0 m/s

  13. Acceleration #2 • What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s2 and comes to rest in 484 m? • V1 = ? • V2 = 0 m/s • A = -8.0 m/s2

  14. Acceleration #2 • What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s2 and comes to rest in 484 m? • V1 = ? • V2 = 0 m/s • A = -8.0 m/s2 • D = 484 m

  15. Acceleration #2 • What was the initial velocity of a car that accelerates at a rate of – 8.0 m/s2 and comes to rest in 484 m? • V1 = ? • V2 = 0 m/s • A = -8.0 m/s2 • D = 484 m • T = no

  16. Solution #2 • Use equation # 7 • V22 = V12 + 2ad

  17. Solution #2 • Use equation # 7 • V22 = V12 + 2ad • 0 m/s = V12+ 2(-8.0m/s)( 484 m)

  18. Solution #2 • Use equation # 7 • V22 = V12 + 2ad • 0 m/s = V12+ 2(-8.0m/s2)( 484 m) • 7744 m2/s2 = V12

  19. Solution #2 • Use equation # 7 • V22 = V12 + 2ad • 0 m/s = V12+ 2(-8.0m/s2)( 484 m) • 7744 m2/s2 = V12 • V1= 88 m/s

  20. Acceleration #3 • What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? • V1= • V2= • A= • D= • T=

  21. Acceleration #3 • What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? • V1 = 25.6 m/s

  22. Acceleration #3 • What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? • V1 = 25.6 m/s • V2 = 8.5 m/s

  23. Acceleration #3 • What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec.? • V1 = 25.6 m/s • V2 = 8.5 m/s • A = ?

  24. Acceleration #3 • What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec. • V1 = 25.6 m/s • V2 = 8.5 m/s • A = ? • D = no

  25. Acceleration #3 • What is the acceleration of a car that was going at 25.6 m/s and slows to 8.5 m/s in 4.6 sec. • V1 = 25.6 m/s • V2 = 8.5 m/s • A = ? • D = no • T = 4.6 sec

  26. Solution #3 • Use Equation #2 • A = V2- V1 t

  27. Solution #3 • A = V2- V1 t A = 8.5 m/s – 25.6 m/s 4.6 sec

  28. Solution #3 • A = V2- V1 t A = 8.5 m/s – 25.6 m/s 4.6 sec A = -3.7 m/s2

  29. Acceleration #4 • A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid? • V1 = • V2= • A = • D = • T =

  30. Acceleration #4 • A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? • V 1 = 14 m/s

  31. Acceleration #4 • A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? • V 1 = 14 m/s • V2 = 0 m/s

  32. Acceleration #4 • A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? • V 1 = 14 m/s • V2 = 0 m/s • A = no

  33. Acceleration #4 • A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? • V 1 = 14 m/s • V2 = 0 m/s • A = no • D = ?

  34. Acceleration #4 • A car traveling at 14m/s encounters a patch of ice and takes 5.0 sec to stop. How far did it skid ? • V 1 = 14 m/s • V2 = 0 m/s • A = no • D = ? • T = 5.0 sec

  35. Solution #4 • Use equation # 4 • D = (V2+V1) t 2

  36. Solution #4 • Use equation # 4 • D = (V2+V1) t 2 D = (14m/s + 0 m/s)5 sec 2

  37. Solution #4 • Use equation # 4 • D = (V2+V1) t 2 D = (14m/s + 0 m/s)5 sec 2 D = 35 m

  38. Acceleration #5 • An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s2over 50 meters. What is it’s final velocity? • V1= • V2= • a= • d= • t=

  39. Acceleration #5 • An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s2over 50 meters. What is it’s final velocity? • V1= 16 m/s

  40. Acceleration #5 • An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s2over 50 meters. What is it’s final velocity? • V1= 16 m/s • V2 = ?

  41. Acceleration #5 • An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s2over 50 meters. What is it’s final velocity? • V1= 16 m/s • V2 = ? • A = 4.0 m/s2

  42. Acceleration #5 • An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s2over 50 meters. What is it’s final velocity? • V1= 16 m/s • V2 = ? • A = 4.0 m/s2 • D = 50 m

  43. Acceleration #5 • An object traveling at 16 m/s accelerates at a constant rate of 4.0 m/s2over 50 meters. What is it’s final velocity? • V1= 16 m/s • V2 = ? • A = 4.0 m/s2 • D = 50 m • T = no

  44. Solution #5 • Use equation #7 • V22= V12 + 2ad

  45. Solution #5 • Use equation #7 • V22= V12 + 2ad • V22 = 16 m/s + 2(4.0m/s2)(50m)

  46. Solution #5 • Use equation #7 • V22= V12 + 2ad • V22 = 16 m/s + 2(40.0m/s2)(50m) • V2 = 26 m/s

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