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Chapter 4 Probability Distributions. 4-1 Random Variables 4-2 Binomial Probability Distributions 4-3 Mean, Variance, Standard Deviation for the Binomial Distribution 4-4 Other Discrete Probability Distributions. Overview. This chapter will deal with the construction of
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Chapter 4Probability Distributions 4-1 Random Variables 4-2 Binomial Probability Distributions 4-3 Mean, Variance, Standard Deviation for the Binomial Distribution 4-4 Other Discrete Probability Distributions
Overview This chapter will deal with the construction of probability distributions by combining the methods of Chapter 2 with the those of Chapter 3. Probability Distributions will describe what will probably happen instead of what actually did happen.
Combining Descriptive Statistics Methods and Probabilities to Form a Theoretical Model of Behavior
4-1 Random Variables
Definitions • Random Variable a variable (typically represented by x) that has a single numerical value, determined by chance, for each outcome of a procedure • Probability Distribution a graph, table, or formula that gives the probability for each value of the random variable
Probability DistributionNumber of Girls Among Fourteen Newborn Babies x P(x) 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 0.000 0.001 0.006 0.022 0.061 0.122 0.183 0.209 0.183 0.122 0.061 0.022 0.006 0.001 0.000 • Questions: • Let X = # of girls • P(X=3) = ? • P(X ≤ 2) = ? • P(X ≥ 1) = ?
Definitions • Discrete random variable has either a finite number of values or countable number of values, where ‘countable’ refers to the fact that there might be infinitely many values, but they result from a counting process. • Continuous random variable has infinitely many values, and those values can be associated with measurements on a continuous scale with no gaps or interruptions.
Requirements for Probability Distribution P(x) = 1 where x assumes all possible values 0 P(x) 1 for every value of x See #3 on hw
Mean, Variance and Standard Deviation of a Probability Distribution Formula (Mean) µ = [x•P(x)] Formula (Variance) 2= [(x - µ)2 • P(x)] Formula (Standard Deviation) =[(x - µ)2 • P(x)]
Roundoff Rule for µ, 2, and Round results by carrying one more decimal place than the number of decimal places used for the random variable x. If the values of xare integers, round µ, 2, and to one decimal place.
TI-83 Calculator Calculate Meanand Std. Dev from a Probability Distribution • Press Stat • Press “1” Edit • Enter values of random variable (x) in L1 • Enter probability P(x) in L2 • Press Stat • Cursor over to CALC • Choose the 1-Var stats option • Enter 1-Var stats L1,L2
Using Excel See Probability Distribution Worksheet Examples: • See Introduction to probability distributions handout • Go to Excel (dice example – class assignment) • Find missing probability, mean, SD and unusual values(test question see #6 on hw)
Unusual and Unlikely Values • Unusual if greater than 2 standard deviations from the mean, that is x + 2 and x – 2s • Unlikely if probability is very small, usually less than .05. This is consistent with the 2 idea associated with the empirical rule. #6f and 7c on HW
Definition Expected Value The average value of outcomes E = [x • P(x)]
E = [x • P(x)] Example: #9 on hw Event Win Lose x $5 - $5 P(x) 244/495 251/495 x • P(x) 2.465 - 2.535 E = -$.07
4-2 Binomial Random Variables
Binomial Random Variables Facts: • Discrete (we can count the outcomes) • Have to do with random variables having 2 outcomes. Examples: heads/tails, boy/girl, yes/no, defective/not defective, etc. • A binomial distribution is the sum of several trials. Example: # of heads when a coin is tossed three times
Notation for Binomial Probability Distributions n = fixed number of trials x = specific number of successes in n trials p = probability of success in one of n trials q = probability of failure in one of n trials (q = 1 - p) P(x) = probability of getting exactly x successes among n trials
Method 1 Binomial Probability Formula n! • P(x) = • px• qn-x (n - x )! x! • P(x) = nCx• px•qn-x for calculators use nCr key, where r = x
Binomial Probability Formula n! P(x) = • px•qn-x (n - x )! x! Probability of x successes among n trials for any one particular order Number of outcomes with exactly x successes among n trials
Example: Toss a coin 3 times. • Let x = number of heads and find • P(2) = • P(at least 2) This is a binomial experiment so you need to know 4 things p, q, n and x. p=.5 q=.5 n=3 a) x = 2 b) x = 0 then 1 then 2 On the test you will have to construct the entire probability distribution for tossing a coin “n” times and observing the number of heads. Should do this before the test.
Example: Find the probability of getting exactly 2 correct responses among 5 different requests from directory assistance. Assume in general, they are correct 80% of the time. This is a binomial experiment where: n = 5 x = 2 p = 0.80 q = 0.20 Using the binomial probability formula to solve: P(2) = 5C2• 0.8 • 0.2 = 0.0512 3 2
Method 2 Binomial Table Two tables are available on website
Example: Using Table for n = 5 and p = 0.80, find the following: a) The probability of exactly 2 successesb) The probability of at most 2 successesc) The probability of at least 1 success a) P(2) = 0.0512 b) P(at most 2) = P(0) or P(1) or P(2) = 0.0003 + 0.0064 + 0.0512 = 0.0579 c) P(at least 1) = 1 – P(0) = 1 – .0003 = .9997 Test Question
Method 3 Using Technology • Calculator function (TI-83) • See binomial distribution worksheet • See also coin example worksheet
TI-83 Calculator Finding Binomial Probabilities (complete distribution) • Press 2nd Distr • Choose binopdf • Enter binopdf(n,p) • Press STO L2 (stores probabilities in column L2) • Press Stat • Choose Edit (to view probabilities) • Optional: enter the values of the random variable in L1
TI-83 Calculator Finding Binomial Probabilities (individual value) • Press 2nd Distr • Choose binopdf • Enter binopdf(n,p,x)
TI-83 Calculator Finding Binomial Probabilities (cummulative) • Press 2nd Distr • Choose binocdf • Enter binocdf(n,p,x) This yields the sum of the probabilities from 0 to x. Example: Let n=6 and p=0.2 P(X<3) = binocdf(6,.2,3)
4.3 Mean, variance and standard deviation of a Binomial Probability Distribution
For Any Discrete Probability Distribution the general formulas are: • µ = [x • P(x)] • 2= [(x - µ) 2• P(x) ] = [(x - µ) 2 • P(x)]
For Binomial Distributions: • µ = n • p • 2 = n • p • q = n • p • q
Example: Find the mean and standard deviation for students that guess answers on a multiple choice test with 5 answers and 20 questions. • We previously discovered that this scenario could be considered a binomial experiment where: • n = 20 • p = 0.2 • q = 0.8 • Using the binomial distribution formulas: µ = (20)(0.2) = 4 correct answers = (20)(0.2)(0.8) = 1.8 answers (rounded) Test question
Reminder • Maximum usual values = µ + 2 • Minimum usual values = µ - 2
Example: Determine whether guessing 7 correct answers is unusual. For this binomial distribution, • µ = 4 answers • = 1.8 answers • µ + 2 = 4 + 2(1.8) = 7.6 • µ - 2 = 4 - 2(1.8) = .4 The usual number of correct answers would be from .4 to 7.6, so guessing 7 correct answers would not be an unusual result. Test question
4.4 Other Discrete Probability Distributions • Poisson • Geometric • Hypergeometric • Negative Binomial • And more
Poisson Distribution Definition a discrete probability distribution that applies to occurrences of some event over a specific interval. Will be a question on the test for you to differentiate between a binomial and a poisson distribution
µ x• e-µ P(x) = wheree 2.71828 x! Definition Poisson Distribution a discrete probability distribution that applies to occurrences of some event over a specific interval. Probability Formula
Example: Look at #1 • Why is this a poisson distribution? • µ = 5 • We need to find various probabilities using • Let’s find P(7) • Look at the Poisson function in Excel µ x• e-µ P(x) = x!
Geometric Distribution Definition a discrete probability distribution of the number of trials needed to get one success. Will be a question on the test for you to differentiate between a binomial, poisson and a geometric distribution
Geometric Distribution Example: Roll a die 5 times. What is the probability of getting your first 2 on the 5th roll.
Negative Binomial Distribution Definition a discrete probability distribution of the number of trials needed to get a get a specified number of successes.
Negative Binomial Distribution Example a basketball player has a 70% chance of making a free throw, what is the probability of making his 3rd free throw on his 5th shot.
Hypergeometric Distribution Hypergeometric Experiment • A sample of size n is randomly selected without replacement from a population of N items. . In the population, k items can be classified as successes, and N - k items can be classified as failures.
Hypergeometric Distribution Notation • N: The number of items in the population. • k: The number of items in the population that are classified as successes. • n: The number of items in the sample. • x: The number of items in the sample that are classified as successes. • kCx: The number of combinations of k things, taken x at a time.
Hypergeometric Distribution Example Suppose we randomly select 5 cards without replacement from an ordinary deck of playing cards. What is the probability of getting exactly 2 red cards (i.e., hearts or diamonds)? P = [ kCx ] [ N-kCn-x ] / [ NCn ] = [ 26C2 ] [ 26C3 ] / [ 52C5 ] = [ 325 ] [ 2600 ] / [ 2,598,960 ] = 0.32513