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Chapter 7 Algebra II. Review. JEOPARDY. Jeopardy Review. Logarithms. Exponential Growth and Decay. Exponential Functions. Solving Logarithmic Equations. Solving Exponential Equations. 200. 200. 200. 200. 200. 400. 400. 400. 400. 400. 600. 600. 600. 600. 600. 800.
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Chapter 7 Algebra II Review JEOPARDY Jeopardy Review
Logarithms Exponential Growth and Decay Exponential Functions Solving Logarithmic Equations Solving Exponential Equations 200 200 200 200 200 400 400 400 400 400 600 600 600 600 600 800 800 800 800 800 1000 1000 1000 1000 1000
Logarithms200 log3 (1/9) = A: -2 Jeopardy Review
Logarithms400 log .001 A: -3 Jeopardy Review
Logarithms600 Use the change of base formula to evaluate: log6 21 A: 1.699 Jeopardy Review
Daily Double Jeopardy Review
Logarithms800 Using the properties of logarithms, expand log (x2y/z) A: 2 log x + log y – log z Jeopardy Review
Logarithms1000 Write as a single logarithm: y = 4 log m + 2 log n – 3 log k A: log (m4n2/k3) S2C13 Jeopardy Review
Exponential Growth & Decay200 Identify the percent of decay in the equation: y = 6000 (.48)x A: 52% S2C13 Jeopardy Review
Exponential Growth & Decay400 Write the equation that models exponential growth of 6% per year with a starting population of 22,000. A: y = 22,000 (1.06)x S2C13 Jeopardy Review
Exponential Growth & Decay600 Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04)x where x represents the years after 1990. A: 2.62 million S2C13 Jeopardy Review
Exponential Growth & Decay800 A city’s population is modeled by the equation y = 14,000 (.98)x, where x represents the number of years after the year 2000. Predict during which year the population will decrease to 8,900. A: 2022 S2C13 Jeopardy Review
Exponential Growth & Decay1000 • In the equation: y = 13 (2.58)x, Identify • Growth or decay • Growth or decay factor • Percent of growth or decay A: a) growth b) 2.58 c) 158% S2C13 Jeopardy Review
Exponential Functions200 Evaluate y = 2x for x = -1, 0, and 2. A: y = ½, 1, and 4 S2C13 Jeopardy Review
Exponential Functions400 Write the equation to describe the exponential function with a base of 2, passing through the point (4,7). A: y = (7/16)(2)x S2C13 Jeopardy Review
Exponential Functions600 Find the amount of money you have if you invest $20,000 for 5 years at 6% compounded continuously. A: 20,000 e^(.06*5) = $26,977.18 S2C13 Jeopardy Review
Exponential Functions800 Find the amount of money you have if you invest $3000 for 3 years at 5% compounded continuously. A: 3000 e (.05)(3) = $3485.50 S2C13 Jeopardy Review
Exponential Functions1000 You invest $2000 in an account earning 3% interest compounded continuously. How long will it be until you have $2500? A: 2500 = 2000 e (.03t) t = 7.44 years S2C13 Jeopardy Review
Solving Logarithmic Equations200 2 log24 – log22 = A: log28 = 3 S2C13 Jeopardy Review
Solving Logarithmic Equations400 log9 √81 A: 1 S2C13 Jeopardy Review
Solving Logarithmic Equations600 Solve for x. log 5x = 2 A: 102 = 5x x = 20 S2C13 Jeopardy Review
Solving Logarithmic Equations800 Solve for x. ln 3 + ln x – ln 2 = 6 A: ln (3x/2) = 6 x = 268.953 S2C13 Jeopardy Review
Solving Logarithmic Equations1000 ln x + ln (x + 3) = 2 A: ln (x2 + 3x) = 2 x = 1.6, using quadratic formula S2C13 Jeopardy Review
Solving Exponential Equations200 x2 = 49 A: 7 or -7 S2C13 Jeopardy Review
Solving Exponential Equations400 4x⅔ = 20 A: x = 11.18 S2C13 Jeopardy Review
Solving Exponential Equations600 3x – 4 = 6 A: x = 2.096 S2C13 Jeopardy Review
Solving Exponential Equations800 4√m3 + 2 = 10 A: m = 16 S2C13 Jeopardy Review
Solving Exponential Equations1000 e4x = 10 A: 4x = ln 10 x = .576 S2C13 Jeopardy Review