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Chapter 7 Algebra II

Chapter 7 Algebra II. Review. JEOPARDY. Jeopardy Review. Logarithms. Exponential Growth and Decay. Exponential Functions. Solving Logarithmic Equations. Solving Exponential Equations. 200. 200. 200. 200. 200. 400. 400. 400. 400. 400. 600. 600. 600. 600. 600. 800.

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Chapter 7 Algebra II

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  1. Chapter 7 Algebra II Review JEOPARDY Jeopardy Review

  2. Logarithms Exponential Growth and Decay Exponential Functions Solving Logarithmic Equations Solving Exponential Equations 200 200 200 200 200 400 400 400 400 400 600 600 600 600 600 800 800 800 800 800 1000 1000 1000 1000 1000

  3. Logarithms200 log3 (1/9) = A: -2 Jeopardy Review

  4. Logarithms400 log .001 A: -3 Jeopardy Review

  5. Logarithms600 Use the change of base formula to evaluate: log6 21 A: 1.699 Jeopardy Review

  6. Daily Double Jeopardy Review

  7. Logarithms800 Using the properties of logarithms, expand log (x2y/z) A: 2 log x + log y – log z Jeopardy Review

  8. Logarithms1000 Write as a single logarithm: y = 4 log m + 2 log n – 3 log k A: log (m4n2/k3) S2C13 Jeopardy Review

  9. Exponential Growth & Decay200 Identify the percent of decay in the equation: y = 6000 (.48)x A: 52% S2C13 Jeopardy Review

  10. Exponential Growth & Decay400 Write the equation that models exponential growth of 6% per year with a starting population of 22,000. A: y = 22,000 (1.06)x S2C13 Jeopardy Review

  11. Exponential Growth & Decay600 Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04)x where x represents the years after 1990. A: 2.62 million S2C13 Jeopardy Review

  12. Exponential Growth & Decay800 A city’s population is modeled by the equation y = 14,000 (.98)x, where x represents the number of years after the year 2000. Predict during which year the population will decrease to 8,900. A: 2022 S2C13 Jeopardy Review

  13. Exponential Growth & Decay1000 • In the equation: y = 13 (2.58)x, Identify • Growth or decay • Growth or decay factor • Percent of growth or decay A: a) growth b) 2.58 c) 158% S2C13 Jeopardy Review

  14. Exponential Functions200 Evaluate y = 2x for x = -1, 0, and 2. A: y = ½, 1, and 4 S2C13 Jeopardy Review

  15. Exponential Functions400 Write the equation to describe the exponential function with a base of 2, passing through the point (4,7). A: y = (7/16)(2)x S2C13 Jeopardy Review

  16. Exponential Functions600 Find the amount of money you have if you invest $20,000 for 5 years at 6% compounded continuously. A: 20,000 e^(.06*5) = $26,977.18 S2C13 Jeopardy Review

  17. Exponential Functions800 Find the amount of money you have if you invest $3000 for 3 years at 5% compounded continuously. A: 3000 e (.05)(3) = $3485.50 S2C13 Jeopardy Review

  18. Exponential Functions1000 You invest $2000 in an account earning 3% interest compounded continuously. How long will it be until you have $2500? A: 2500 = 2000 e (.03t) t = 7.44 years S2C13 Jeopardy Review

  19. Solving Logarithmic Equations200 2 log24 – log22 = A: log28 = 3 S2C13 Jeopardy Review

  20. Solving Logarithmic Equations400 log9 √81 A: 1 S2C13 Jeopardy Review

  21. Solving Logarithmic Equations600 Solve for x. log 5x = 2 A: 102 = 5x x = 20 S2C13 Jeopardy Review

  22. Solving Logarithmic Equations800 Solve for x. ln 3 + ln x – ln 2 = 6 A: ln (3x/2) = 6 x = 268.953 S2C13 Jeopardy Review

  23. Solving Logarithmic Equations1000 ln x + ln (x + 3) = 2 A: ln (x2 + 3x) = 2 x = 1.6, using quadratic formula S2C13 Jeopardy Review

  24. Solving Exponential Equations200 x2 = 49 A: 7 or -7 S2C13 Jeopardy Review

  25. Solving Exponential Equations400 4x⅔ = 20 A: x = 11.18 S2C13 Jeopardy Review

  26. Solving Exponential Equations600 3x – 4 = 6 A: x = 2.096 S2C13 Jeopardy Review

  27. Daily Double

  28. Solving Exponential Equations800 4√m3 + 2 = 10 A: m = 16 S2C13 Jeopardy Review

  29. Solving Exponential Equations1000 e4x = 10 A: 4x = ln 10 x = .576 S2C13 Jeopardy Review

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