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MOMENTUM. Action and Reaction Forces Newton’s Third Law. Newton's Third Law of Motion (Law of Action & Reaction) [Law of Forces acting in Pairs]. Newton's 3 rd Law of Motion says: for every action, there is an equal and opposite reaction.
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MOMENTUM Action and Reaction Forces Newton’s Third Law
Newton's Third Law of Motion (Law of Action & Reaction) [Law of Forces acting in Pairs]
Newton's 3rd Law of Motionsays: for every action, there is an equal and opposite reaction. Forces act in pairs. One force is called the action force and the other is called the reaction force.
MOMENTUM • Momentumis a property a moving objecthasbecause of its mass and velocity.
MOMENTUM • Which would hurt more??
MOMENTUM Momentum is a property a moving object has because of its mass and velocity.Momentum can be calculated by : p = mv P = momentum (kgm/s) m = mass (kg) v = velocity (m/s)
MOMENTUM • What is the momentum of a 5 kg ball that has a velocity of 15m/s? G U E S S
Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15m/s?G U E S S P= ? P = M V M= 5kg V= 15m/s
Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15m/s?G U E S S P= P P = M V P = 5 x 15 M= 5kg V= 15m/s
Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15m/s?G UE S S P= P P = M V P = 5 x 15 M= 5kg V= 15m/s 75 kg • m/s
MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S
MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S P= 10 kg •m/sP = M VM= M V= 5m/s
MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S P= 10 kg •m/sP = M VM= M V= 5m/s 10 = M x 5
MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S P= 10 kg •m/sP = M VM= M V= 5m/s 10 = M x 5 10 = M x 5 5 5
MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S P= 10 kg •m/sP = M VM= M V= 5m/s 10 = M x 5 2 kg 10 = M x 5 5 5
MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S
MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S P= 50 kg •m/sP = M V M= 20kg V= V
MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S P= 50 kg •m/sP = M V M= 20kg V= V 50 = 20 x V
MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S P= 50 kg •m/sP = M V M= 20kg V= V 50 = 20 x V 20 20
MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S 5/2 or 2.5 m/s P= 50 kg •m/sP = M V M= 20kg V= V 50 = 20 x V 20 20
Copy this question and the steps to solve! This question is on the assignment, quiz, review and test! If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic?Given/ Miata: Miata P = M V Our first job is to find the momentum of the Miata…………
If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Given/Miata: Miata: formula P= ? P = M V M=900 kg V= 30 m/s Our first job is to find the momentum of the Miata…………
If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Given/Miata: Miata: formula SUB P= ?P = M VP = 900 x 30 M=900 kg V= 30 m/s Our first job is to find the momentum of the Miata…………
If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Given/Miata: Miata: formula SUB ANS/UNITS P= ?P = M VP = 900 x 30 P=27000 Kg * m/s M=900 kg V= 30 m/s Since theydid NOT move after the collision,their “momentums”must have beenEQUAL!
If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Given/Miata: Miata: formula SUB ANS/UNITS P= PP = M VP = 900 x 30 P=27000 Kg * m/s M=900 kg V= 30 m/s Since theydid NOT move after the collision,their “momentums”must have beenEQUAL! Given/Civic: P = 27,000 kg •m/s
If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Since theydid NOT move after the collision,their “momentums”must have beenEQUAL! Given/Civic: P = 27,000 kg •m/s Given/Civic: P = 27,000 kg • m/s M = 1200kg V = ?
If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Since theydid NOT move after the collision,their “momentums”must have beenEQUAL! Given/Civic: P = 27,000 kg •m/s Given/Civic: P = 27,000 kg • m/s M = 1200kg V = ? P=mv 27,000 = 1200 x V
If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Since theydid NOT move after the collision,their “momentums”must have beenEQUAL! Given/Civic: P = 27,000 kg •m/s Given/Civic: P = 27,000 kg • m/s M = 1200kg V = V P=mv 27,000 = 1200 x V V = 22.5 m/s That was the Velocity of the Civic! 1200 1200
The Law of Conservation of Momentum- the total amount of momentum of a group of objects does not change unless outside forces act on the objects. (Ex – momentum of cue ball = momentum of balls struck + remaining momentum in cue ball) What outside force acts against the balls now?
If a larger truck were to run, head to head, into a smaller truck moving at the same speed, what would happen to the momentum of each truck?