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MOMENTUM

MOMENTUM. Action and Reaction Forces  Newton’s Third Law. Newton's Third Law of Motion (Law of Action & Reaction) [Law of Forces acting in Pairs]. Newton's 3 rd Law of Motion says: for every action, there is an equal and opposite reaction.

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MOMENTUM

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  1. MOMENTUM Action and Reaction Forces Newton’s Third Law

  2. Newton's Third Law of Motion (Law of Action & Reaction) [Law of Forces acting in Pairs]

  3. Newton's 3rd Law of Motionsays: for every action, there is an equal and opposite reaction. Forces act in pairs. One force is called the action force and the other is called the reaction force.

  4. MOMENTUM • Momentumis a property a moving objecthasbecause of its mass and velocity.

  5. MOMENTUM • Which would hurt more??

  6. MOMENTUM Momentum is a property a moving object has because of its mass and velocity.Momentum can be calculated by : p = mv P = momentum (kgm/s) m = mass (kg) v = velocity (m/s)

  7. MOMENTUM • What is the momentum of a 5 kg ball that has a velocity of 15m/s? G U E S S

  8. Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15m/s?G U E S S P= ? P = M V M= 5kg V= 15m/s

  9. Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15m/s?G U E S S P= P P = M V P = 5 x 15 M= 5kg V= 15m/s

  10. Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15m/s?G UE S S P= P P = M V P = 5 x 15 M= 5kg V= 15m/s 75 kg • m/s

  11. MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S

  12. MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S P= 10 kg •m/sP = M VM= M V= 5m/s

  13. MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S P= 10 kg •m/sP = M VM= M V= 5m/s 10 = M x 5

  14. MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S P= 10 kg •m/sP = M VM= M V= 5m/s 10 = M x 5 10 = M x 5 5 5

  15. MOMENTUM • What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5m/s? G U E S S P= 10 kg •m/sP = M VM= M V= 5m/s 10 = M x 5 2 kg 10 = M x 5 5 5

  16. MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S

  17. MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S P= 50 kg •m/sP = M V M= 20kg V= V

  18. MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S P= 50 kg •m/sP = M V M= 20kg V= V 50 = 20 x V

  19. MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S P= 50 kg •m/sP = M V M= 20kg V= V 50 = 20 x V 20 20

  20. MOMENTUM • What is the velocity of a child that has a mass of 20kg and a momentum of 50 kg •m/s ? G U E S S 5/2 or 2.5 m/s P= 50 kg •m/sP = M V M= 20kg V= V 50 = 20 x V 20 20

  21. Copy this question and the steps to solve! This question is on the assignment, quiz, review and test! If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic?Given/ Miata: Miata P = M V Our first job is to find the momentum of the Miata…………

  22. If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Given/Miata: Miata: formula P= ? P = M V M=900 kg V= 30 m/s Our first job is to find the momentum of the Miata…………

  23. If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Given/Miata: Miata: formula SUB P= ?P = M VP = 900 x 30 M=900 kg V= 30 m/s Our first job is to find the momentum of the Miata…………

  24. If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Given/Miata: Miata: formula SUB ANS/UNITS P= ?P = M VP = 900 x 30 P=27000 Kg * m/s M=900 kg V= 30 m/s Since theydid NOT move after the collision,their “momentums”must have beenEQUAL!

  25. If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Given/Miata: Miata: formula SUB ANS/UNITS P= PP = M VP = 900 x 30 P=27000 Kg * m/s M=900 kg V= 30 m/s Since theydid NOT move after the collision,their “momentums”must have beenEQUAL! Given/Civic: P = 27,000 kg •m/s

  26. If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Since theydid NOT move after the collision,their “momentums”must have beenEQUAL! Given/Civic: P = 27,000 kg •m/s Given/Civic: P = 27,000 kg • m/s M = 1200kg V = ?

  27. If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Since theydid NOT move after the collision,their “momentums”must have beenEQUAL! Given/Civic: P = 27,000 kg •m/s Given/Civic: P = 27,000 kg • m/s M = 1200kg V = ? P=mv 27,000 = 1200 x V

  28. If a Miata(900kg)at 30 m/sruns head-on into a Civic (1200kg) and neither car moves after the collision, what is the velocity of the Civic? Since theydid NOT move after the collision,their “momentums”must have beenEQUAL! Given/Civic: P = 27,000 kg •m/s Given/Civic: P = 27,000 kg • m/s M = 1200kg V = V P=mv 27,000 = 1200 x V V = 22.5 m/s That was the Velocity of the Civic! 1200 1200

  29. The Law of Conservation of Momentum- the total amount of momentum of a group of objects does not change unless outside forces act on the objects. (Ex – momentum of cue ball = momentum of balls struck + remaining momentum in cue ball) What outside force acts against the balls now?

  30. If a larger truck were to run, head to head, into a smaller truck moving at the same speed, what would happen to the momentum of each truck?

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