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PHY 126 Final Exam

Problem 1 (6+6+6+6+6 points). PHY 126 Final Exam. (a) (6 points). image of arrow by mirror. final image 2. F. F. 20.0 cm. 20.0 cm. 85.0 cm. A. B. 40.0 cm. 40.0 cm. 170.0 cm. (3 points for the mirror image, 3 points for the final image). (c) Real (3 point) and inverted (3 point).

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PHY 126 Final Exam

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  1. Problem 1 (6+6+6+6+6 points) PHY 126 Final Exam (a) (6 points) image of arrow by mirror final image 2 F F 20.0 cm 20.0 cm 85.0 cm A B 40.0 cm 40.0 cm 170.0 cm (3 points for the mirror image, 3 points for the final image)

  2. (c) Real (3 point) and inverted (3 point). (d) (6 points) (e) (6 points)

  3. Since the density of concrete is larger than that of water, the object • is completely submerged in the water. Therefore the apparent mass • of the object is: (5 points) As the net torque around the pivot is zero: (5 points) (5 points) A: B: Problem 2 (15+15 points) (b) Since the density of ice is smaller than that of water, the object floats. Therefore there is no weight contribution from the ice object. (5 points) As the net torque around the pivot is zero: (5 points) (5 points) A: B:

  4. ab: For isothermal process DT=0 and DU=0. W=nRTCln(Vb/Va)=-nRTCln(r) and • Q=W=-nRTCln(r). (1 point for each quantity) (b) bc: For isochoric process, DV=0 and W=0; Q=DU=nCV(TH-TC). (1 point for each) • (c) cd: For isothermal process DT=0 and DU=0. W=nRTHln(Va/Vb)=nRTHln(r) and • Q=W=nRTHln(r). (1 point for each) (d) da: For isochoric process, DV=0 and W=0; Q=DU=nCV(TC-TH). (1 point for each) (e) The net work for one cycle is Wnet=nR(TH-TC)ln(r). (4 points) Problem 3 (3+3+3+3+4+4+10 points) (f) The net heat added for one cycle Qadded is the same as Qcd=nRTHln(r). (4 points). (e) The efficiency is Wnet/Qadded=1-(TC/TH) (5 points). This is the same as the efficiency of a Carnot cycle engine operating between the two temperatures (5 points).

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