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241-213 Computer Engineering Mathematics. 21. Chapter 21 Complex Functions. OUTLINE. Limits Continuity Derivatives. Complex Functions. A complex function is a function that is defined for complex numbers in some set S and takes on complex values.
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OUTLINE • Limits • Continuity • Derivatives
Complex Functions • A complex function is a function that is defined for complex numbers in some set S and takes on complex values. • If C denotes the set of complex number, and • fis such a function, • then we write • This means, f(z) is a complex number for each z in S. • The set S is called the domainof f.
Example • Let S consists of all z with |z| < 1 • and define f(z) = z2 in S • then and f is a complex function. • Often we define a function by some explicit expression in z, for example, • In the absence of specifying S, we agree to allow all z which the expression for f(z) is defined • This function defines for all complex z except 2i and -2i
Example 21.1 Let
Limit Theorems • Many limit theorems from real calculus hold for complex functions as well • Suppose
Limits of Real vs Complex functions • Limits of real functions approach the point from 2 sides • Limits of complex functions approach the point from any directions
Continuity • Any polynomial is continuous for all z • Any rational function (quotient of polynomians) is continuous whenever its denominator is nonzero. • If f is continuous at z0, so is |f|
Continuity • If {zn} is a sequence of complex numbers and each f(zn) is defined • then {f(zn)} is also a complex sequence • For example, if f(z)= 2z2 and zn = 1/n then f(zn) = 2/n2 • We claim that {f(zn)} converges if {zn} does, when f is continuous • “Continuity preserves convergence of sequences”
THEOREM 21.1 • Let be continuous, and let {zn} be a sequence of complex numbers in S. If {zn} converges to a number w in S, then {f(zn)} converges to f(w) • A converse of Theorem 21.1 If f(zn)->f(w)for every sequence {zn} of points ofSconverging tow, thenfis continuous atw.
Bounded Function • If f is bounded if there is a disk about the origin containing all the numbers f(z) for z in S • A continuous function need not be bounded (look at f(z) = 1/z for z != 0)
THEOREM 21.2 • Let . Suppose S is compact and f is continuous on S. Then f is bounded.
THEOREM 21.3 • Let be continuous and suppose S is compact. Then there are numbers ziand z2 in Ssuch that, for allzinS
The Derivative of a Complex Function • The reason for having S open in this definition is to be sure that there is some open disk aboutz0 throughout which f(z) is defined
Derivative Formulas • If n is a positive integer • and f(z) = zn • then f’(z) = nzn-1 • if f(z) = sin(z) then f’(z)= cos(z)
Cauchy-Riemann Equations • We will derive a set of partial differential equations that must be satisfied by the real and imaginary parts of a differentiable complex function.
THEOREM 21.5 Cauchy-Riemann Equations