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6.9 Addition of Sulfuric Acid to Alkenes. CH 3 CHCH 3. CH 3 CH. CH 2. OSO 2 OH. Addition of H 2 SO 4. HOSO 2 OH. follows Markovnikov's rule: yields an alkyl hydrogen sulfate. Isopropyl hydrogen sulfate. CH 3 CH. CH 2. +. CH 3 CH. CH 3. CH 3 CHCH 3. OSO 2 OH. Mechanism. .
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CH3CHCH3 CH3CH CH2 OSO2OH Addition of H2SO4 HOSO2OH follows Markovnikov's rule: yields an alkyl hydrogen sulfate Isopropylhydrogen sulfate
CH3CH CH2 + CH3CH CH3 CH3CHCH3 OSO2OH Mechanism .. SO2OH + O H .. slow – .. : + SO2OH O .. fast : ..
CH3CHCH3 SO2OH O heat CH3CHCH3 O H Alkyl hydrogen sulfates undergo hydrolysis in hot water + H—OH + HO—SO2OH
OH Application: Coversion of alkenes to alcohols 1. H2SO4 2. H2O, heat (75%)
But... not all alkenes yield alkyl hydrogen sulfateson reaction with sulfuric acid these do: H2C=CH2, RCH=CH2, and RCH=CHR' these don't: R2C=CH2, R2C=CHR, and R2C=CR2 (These form polymers, sec 6.21)
C C C H C OH Acid-Catalyzed Hydration of Alkenes + H—OH reaction is acid catalyzed; typical hydration medium is 50% H2SO4-50% H2O
CH3 H3C H 50% H2SO4 CH2CH3 CH3 C C C 50% H2O H3C CH3 OH Follows Markovnikov's Rule (90%)
CH3 50% H2SO4 CH2 50% H2O OH Follows Markovnikov's Rule (80%)
CH3 H3C CH3 CH3 C C CH2 H3C OH Mechanism involves a carbocation intermediate is the reverse of acid-catalyzed dehydrationof alcohols to alkenes H+ + H2O
H H3C + : H C O CH2 H3C H H : : O Mechanism Step (1) Protonation of double bond + slow H3C + C + CH3 H3C H
H H3C + : : C + O CH3 H3C H fast CH3 H + : C CH3 O H CH3 Mechanism Step (2) Capture of carbocation by water
CH3 H H : C CH3 O : : O H H CH3 fast CH3 H .. + : : C H CH3 O O H H CH3 Mechanism Step (3) Deprotonation of oxonium ion + + +
Relative Rates Acid-catalyzed hydration ethylene CH2=CH2 1.0 propene CH3CH=CH2 1.6 x 106 2-methylpropene (CH3)2C=CH2 2.5 x 1011 The more stable the carbocation, the fasterit is formed, and the faster the reaction rate.
CH3 H3C CH3 CH3 C C CH2 H3C OH Principle of microscopic reversibility In an equilibrium process, the same intermediates and transition states are encountered in the forward direction and the reverse, but in the opposite order. H+ + H2O
Hydration-Dehydration Equilibrium How do we control the position of the equilibrium and maximize the product?
Le Chatelier’s Principle A system at equilibrium adjusts so to minimize any stress applies to it. For the hydration-dehydration equilibria, the key stress is water. Adding water pushes the equilibrium toward more product (alcohol). Removing water pushes the equilibrium toward more reactant (alkene).
Le Chatelier’s Principle At constant temperature and pressure a reaction proceeds in a direction which is spontaneous or decreases free energy (G). The sign of G is always positive, but DG can be positive or negative. DG = Gproducts – Greactants Spontaneous when DG < 0
c d = + R T l n [ C ] [ D ] a b [ A ] [ B ] Le Chatelier’s Principle For a reversible reaction: aA + bB cC + dD The relationship between DG and DGo is: DGo DG R = 8.314 J/(mol.K) and T is the temperature in K
Le Chatelier’s Principle At equilibrium G = 0 and the following becomes true: Substituting Keq into the previous equation gives: Go = - RT lnKeq Reactions for Go positive are endergonic and for Go negative are exergonic.
Synthesis Suppose you wanted to prepare 1-decanol from 1-decene? OH
Synthesis Suppose you wanted to prepare 1-decanol from 1-decene? Needed: a method for hydration of alkenes with a regioselectivity opposite to Markovnikov's rule. OH
1. hydroboration 2. oxidation Synthesis Two-step reaction sequence called hydroboration-oxidation converts alkenes to alcohols with a regiochemistry opposite to Markovnikov's rule. OH
H BH2 C C C C Hydroboration step + H—BH2 Hydroboration can be viewed as the addition ofborane (BH3) to the double bond. But BH3 is not the reagent actually used.
H BH2 C C C C Hydroboration step + H—BH2 Hydroboration reagents: H Diborane (B2H6)normally used in an ether- like solventcalled "diglyme" BH2 H2B H
H BH2 C C C C Hydroboration step + H—BH2 Hydroboration reagents: Borane-tetrahydrofurancomplex (H3B-THF) .. + O – BH3
H BH2 H OH C C C C Oxidation step H2O2, HO– Organoborane formed in the hydroborationstep is oxidized with hydrogen peroxide.
1. B2H6, diglyme 2. H2O2, HO– Example OH (93%)
H OH 1. H3B-THF CH3 CH3 C C C C 2. H2O2, HO– CH3 H Example H3C CH3 H3C H (98%)
Example OH 1. B2H6, diglyme 2. H2O2, HO– (no rearrangement) (82%)
Features of Hydroboration-Oxidation • hydration of alkenes • regioselectivity opposite to Markovnikov's rule • no rearrangement • stereospecific syn addition
H CH3 CH3 HO H H syn-Addition • H and OH become attached to same face of double bond 1. B2H6 2. H2O2, NaOH only product is trans-2-methylcyclopentanol(86%) yield
Hydroboration-oxidation electrons from alkene flow into 2P orbital of boron
Hydroboration-oxidation H atom with 2 electrons migrates to C with greatest (+) charge (most highly substituted). Syn add.
Hydroboration-oxidation Anion of hydrogen peroxide attacks boron
Hydroboration-oxidation Carbon with pair of electrons migrates to oxygen, displacing hydroxide. Oxygen on same side as boron
Hydroboration-oxidation Hydrolysis cleaves boron-oxygen bond resulting in anti-Markovnikov addition
1-Methylcyclopentene + BH3 • syn addition of Hand B to double bond • B adds to less substituted carbon
Add hydrogen peroxide • OH replaces B on same side
C C C C + X2 electrophilic addition to double bond forms a vicinal dihalide X X
Example Br2 CH3CHCHCH(CH3)2 CH3CH CHCH(CH3)2 CHCl3 0°C Br Br (100%)
Scope Limited to Cl2 and Br2 F2 addition proceeds with explosive violence I2 addition is endothermic: vicinal diiodides dissociate to an alkene and I2