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Review of Diprotic Acid Titration

Review of Diprotic Acid Titration. Analysis of 0.181g Carbonate / Bicarbonate Sample. # mol HCO 3 - = (0.02630 - 0.00740 L) x (0.1000 M) x (1 mol HCO 3 - / 1 mol HCl) = 0.001890 mol HCO 3 - # mole CO 3 2- = (0.00740 - 0.00060 L) x (0.1000 M) x (1 mol CO 3 2- / 1 mol HCl)

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Review of Diprotic Acid Titration

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  1. Review of Diprotic Acid Titration

  2. Analysis of 0.181g Carbonate / Bicarbonate Sample # mol HCO3- = (0.02630 - 0.00740 L) x (0.1000 M) x (1 mol HCO3- / 1 mol HCl) = 0.001890 mol HCO3- # mole CO32- = (0.00740 - 0.00060 L) x (0.1000 M) x (1 mol CO32- / 1 mol HCl) = 0.000680 mol CO32- # mole HCO3- in original mixture = # mol HCO3- - # mol HCO3- produced in titration to Phen. End Pt. = # mol HCO3- - # mol CO32- = 0.001890 mol - 0.000680 mol = 0.001210 mol HCO3- #g NaHCO3 = (0.001210 mol) x (84.007 g/mol) = 0.102 g #g Na2CO3 = (0.000680 mol) x (105.9885 g/mol) = 0.072 g wt% NaHCO3 = (0.102g / 0.181g) x 100 = 56.3 % wt % Na2CO3 = (0.072g / 0.181g) x 100 = 39.8 %

  3. Complexometric Titration

  4. Typical Complexing Agents

  5. EDTA

  6. Ca-EDTA Titration

  7. 0.00 mLTitrant Added Titration Reaction EDTA Ca2+ CaEDTA2+ end = 0 M = 0.00500 M = 0 M Equilibrium Reaction EDTA Ca2+ CaEDTA2+ Initial 0 0.0500 0 [Ca2+] = 0.00500 M Concentration pCa = - log(0.00500) = 2.30

  8. 25.00 mLTitrant Added (Equivalence Point) Titration Reaction EDTA Ca2+ CaEDTA2+ start (0.0100M)(0.02500L) (0.0050M)(0.05000L) = 0.000250 mol = 0.000250 mol = 0 mol end 0 mol 0 mol 0.000250 mol (0.000250mol)/(0.07500L) = 0 M = 0 M = 0.00333M Equilibrium Reaction EDTA Ca2+ CaEDAT2+ Initial 0 0 0.00333 Change + x + x - x Equilibrium x x ~0.00333 1.75 x 1010 = (0.00333) / x2 x = [Ca+] = 4.36 x 10-7 M Concentration pCa = - log(4.36 x 10-7) = 6.36

  9. 50.00 mLTitrant Added Titration Reaction EDTA Ca2+ CaEDTA2+ start (0.0100M)(0.05000L) (0.0050M)(0.05000L) = 0.000500 mol = 0.000250 mol = 0 mol end 0.000250 mol 0 mol 0.000250 mol (0.000250mol)/(0.1000L) (0.000250mol)/(0.1000L) = 0.00250 M = 0 M = 0.00250M Equilibrium Reaction EDTA Ca2+ CaEDAT2+ Initial 0.00250 0 0.00250 Change + x + x - x Equilibrium ~0.00250 x ~0.00250 1.75 x 1010 = (0.00250) / (0.00250) x x = [Ca+] = 5.71 x 10-11 M Concentration pCa = - log(5.71 x 10-11) = 10.24

  10. Indicators

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