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Computational Geometry The art of finding algorithms for solving geometrical problems. Literature: M. De Berg et al: Computational Geometry, Springer, 2000. H. Edelsbruner: Algorithms in Combinatorial Geometry, Springer, 1987. 1. Convex Hull. 1.1 Euclidean 2-dimensional space E 2
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Computational GeometryThe art of finding algorithms for solving geometrical problems • Literature: • M. De Berg et al: Computational Geometry, Springer, 2000. • H. Edelsbruner: Algorithms in Combinatorial Geometry, Springer, 1987.
1. Convex Hull 1.1 Euclidean 2-dimensional space E2 • Real Vector Space V2(V,+,•); • Equations of lines in E2: a1x1 + a2x2 = b (eq. 1) X=A + (1-)B (eq. 2) l B (1-l) X A
1.2 Affine / Convex Combination Affine combination of points A and B A + mB, + m= 1 Convex combination of points A and B , m 0 A + mB, + m = 1, Generalization: Euclidean n-dim space En Affine combination: 1A1 + 2A2 + … + kAk , 1 + 2 + … + k = 1 Convex combination: 1A1 + 2A2 + … + kAk , 1 + 2 + … + k = 1, 1 ,…, k 0
1.3 Affine / Convex Hull • Affine Hull of a finite set of points A1 ,…, Ak 1A1 + 2A2 + … + kAk : 1 + 2 + … + k = 1 • Convex Hull of a finite set of points A1 ,…, Ak 1A1 + 2A2 + … + kAk : 1 + 2 + … + k = 1, i 0 Affine (Convex) Hull of a set S, notation Aff (S) (Conv (S)), is the set of all affine (convex) combinations of finite subsets of S.
Examlpes • Line AB is the affine hull of A and B. • Plane ABC is the affine hull of affinely independent points A, B and C. • ... • Segment [A,B]. - is the set of points on AB which are between A and B, i.e. the set of convex combinations of A and B. • Triangle, ...
1.4 Exercises Exercise 1 Prove that if a point B belongs to the affine hull Aff (A1, A2, …, Ak ) of points A1, A2,…, Ak , then: Aff (A1, A2,…, Ak) = Aff (B,A1, A2,…, Ak).
1.4 Exercises (cont.) Exercise 2 • Prove that the affine hull Aff (A1, A2, …, Ak ) of points A1, A2,…, Ak contains the line AB with each pair of its points A,B. • Moreover, prove that Aff (A1, A2, …, Ak ) is the smallest set containing {A1, A2, …, A k } and having this property. [This property therefore may serve as a definition of affine sets. ] (Hint: proof by induction.)
1.4 Exercises (cont.) Exercise 3 Prove that Aff (A1,, A2,…, Ak ) is independentofthe transformation of coordinates. Definition: Affine transformation of coordinates: Matrix multiplication : X -> X• Mnn Matrix translation: X-> X + O’
1.4 Exercises (cont.) Reformulate exercises 1-3 by substituting: • Aff (A1, A2,…, Ak ) with Conv (A1, A2,…, Ak ) • line AB with segment [A,B]. • Definition: Convex set is a set which contains the segment [A,B] with each pair of its elements A and B. Exercise 1’-3’
1.4 Exercises (cont.) If a convex set S contains the vertices A1, A2,…, Ak of a polygon P=A1A2…Ak , it contains the polygon P. (Hint: Interior point property). Exercise 4
1.4 Exercises (cont.) Exercise 5-5’ Prove that Aff (S) (Conv ( S)) is the smallest affine (convex) set containing S, i. e. the smallest set X which contains the line AB (segment [AB]) with each pair of points A, B X. Alternatively: Definition: Convex Hull of a set of points S, notation Conv (S ) is the smallest convex set containing S.
1.4 Exercises (cont.) Prove that: Aff (A1, A2,…, Ak) = Aff (A1,, Aff (A2,…, Ak)). Conv (A1, A2,…, Ak) = Conv (A1,, Conv (A2,…, Ak)). Exercise 6-6’
1.4 Exercises (cont.) Definiton: A set S of points is said to be affinely (convex) independent if no point of S is an affine combination of the others. Affine (convex) basisBS of a set S is an affinely (convex) independent subset of S such that every point in S is an affine (convex) combination of points from BS. A set A1, A2,…, Ak is affinely independent if and only if the set of vectors A1A2,…, A1Akis linearly independent. Exercise 7
Therefore... Every set in En has an affine basis of k n+1 points. (easy to prove). It has also a convex basis (not easy to prove), which is not necessarily finite. A number of points in an affine basis of a set S is constant and said to be the dimension of S.
Theorem If S is a finite set of points, then Conv (S) is a polygon with the vertices in S. Proof: 1. There is a convex polygon PS with the vertices in S. (for example, Algorithm1) 2. PS= Conv (S).