Chapter 5 Test Review

1. Section 1 Section 2 Section 3 Section 4 Section 5 Section 6 100 100 100 100 100 100 200 200 200 200 200 200 300 300 300 300 300 300 Chapter 5 Test Review 400 400 400 400 400 400 500 500 500 500 500 500

2. Section 1 ~ 100 Points Is BD an altitude of ∆ ABC? B 45o 30o 45o 60o C A D

3. Section 1 ~ 100 Points YES Answer B 45o 30o 45o 60o C A D Back

4. Section 1 ~ 200 Points If BD is the median what do we know? B C A D

5. Section 1 ~ 200 Points CD = AD Answer B C A D Back

6. Section 1 ~ 300 Points If CD is an angle bisector what do we know? B D C A

7. Section 1 ~ 300 Points Answer B < BCD = < ACD D C A Back

8. Section 1 ~ 400 Points In the figure to the left BF is the median, EA is a perpendicular bisector, and DC is an angle bisector. If m<DCA = 25o, CF = 14, and m<CEA = 90o , what is m<AEB, m<DCB, and FA? B E D C A F

9. Section 1 ~ 400 Points m<AEB = 90o m<DCB = 25o FA = 14 Answer B E D C A F Back

10. Section 1 ~ 500 Points ∆ ABC has vertices A(-3 , -9), B(5, 11), and C(9,-1). AT is a median of ∆ ABC with T on BC. What are the coordinates of T?

11. Section 1 ~ 500 Points ∆ ABC has vertices A(-3 , -9), B(5, 11), and C(9,-1). AT is a median of ∆ ABC with T on BC. What are the coordinates of T? Answer B (5, 11) T (7, 5) T C (9, -1) A (-3, -9) Back

12. Section 2 ~ 100 Points A What is the theorem that we can use to prove ∆ ABC = ∆ XYZ? Y Z C B X

13. Section 2 ~ 100 Points A Answer LL THEOREM Y Z C B Back X

14. Section 2 ~ 200 Points If AD is an angle bisector and an altitude for the triangle ∆ ABC, what theorem can I use to prove that ∆ ADC = ∆ ADB ? A C B D

15. Section 2 ~ 200 Points LA Theorem Answer A C B D Back

16. Section 2 ~ 300 Points Find the value of X and Y so that the two triangles are congruent by the HA Theorem. 70 - Y 5 X - 8 2 X + 10 100 – 2 Y

17. Section 2 ~ 300 Points Answer 70 - Y X = 6 Y = 30 5 X - 8 2 X + 10 100 – 2 Y Back

18. Section 2 ~ 400 Points Find the value of X and Y so that the two triangles are congruent by the HL Theorem. 6 X - 9 30 + 2 Y 7 Y + 20 2 X + 3

19. Section 2 ~ 400 Points X = 3 Y = 2 Answer 6 X - 9 30 + 2 Y 7 Y + 20 2 X + 3 Back

20. Section 2 ~ 500 Points Name the 5 Theorems that we have had that deal with right triangles.

21. Section 2 ~ 500 Points HA, HL, LL, LA, and the Pythagorean Theorem Answer Back

22. Section 3 ~ 100 Points Name the property of inequality that justifies the following statement. If 7 X < 28, then x < 4.

23. Section 3 ~ 100 Points The Division Property of Inequality Answer If 7 X < 28, then x < 4. Back

24. Section 3 ~ 200 Points Name the property of inequality that justifies the following statement. If X < Y and Y < Z, then X < Z.

25. Section 3 ~ 200 Points Transitive Property of Inequality Answer If X < Y and Y < Z, then X < Z. Back

26. Section 3 ~ 300 Points Which is the greatest angle in the following figure? And what theorem from section 3 can we use to come to find the greatest angle? 1 2 3

27. Section 3 ~ 300 Points Answer < 1 and the Exterior Angle Inequality Theorem 1 2 3 Back

28. Section 3 ~ 400 Points What angle(s) are less that < 1? 1 2 7 4 3 5 6

29. Section 3 ~ 400 Points < 2, < 4, < 5, <3, and <6 Answer 1 2 7 4 3 5 6 Back

30. Section 3 ~ 500 Points What is the assume statement that you would write for the following statement if you were going to do an indirect proof? An altitude of an isosceles triangle is also a median.

31. Section 3 ~ 500 Points An altitude of an isosceles triangle is not also a median. Answer Back

32. Section 4 ~ 100 Points True OR False? The perpendicular segment from a point to a line is the shortest segment from the point to the line.

33. Section 4 ~ 100 Points Answer True OR False? The perpendicular segment from a point to a line is the shortest segment from the point to the line. Back

34. Section 4 ~ 200 Points True OR False? The parallel segment from a point to a plane is the shortest segment from the point to the plane.

35. Section 4 ~ 200 Points True OR False? The parallel segment from a point to a plane is the shortest segment from the point to the plane. Answer Back

36. Section 4 ~ 300 Points List the sides in order from least to greatest. A 65o 35o 80o C B

37. Section 4 ~ 300 Points Answer A AB < BC < AC 65o 35o 80o C B Back

38. Section 4 ~ 400 Points Given that the perimeter of the triangle is 25, list the angles in order from least to greatest. A 3 X - 2 6 X + 1 C B 2 X + 4

39. Section 4 ~ 400 Points X = 2 AC = 13 AB = 4 BC = 8 m<C , m<A, m<B Answer A 3 X - 2 6 X + 1 C B 2 X + 4 Back

40. Section 4 ~ 500 Points Find the value of X and list the sides in order from least to greatest given that m<A = 9X + 29 m<B = 93 – 5X m<C = 10X +2

41. Section 4 ~ 500 Points X = 4 m<A = 65 m<B = 73 m<C = 42 So AB < BC < AC Answer Back

42. Section 5 ~ 100 Points Is it possible to draw a triangle with sides of the given measures; 4, 6, 18 ?

43. Section 5 ~ 100 Points NO 4 + 6 = 10 > 18 Answer Back

44. Section 5 ~ 200 Points Is it possible to draw a triangle with sides of the given measures; 9, 40, 47?

45. Section 5 ~ 200 Points YES 9 + 40 = 49 > 47 40 + 47 = 87 > 9 47 + 9 = 56 >40 Answer Back

46. Section 5 ~ 300 Points If two sides of a triangle are 33 and 68, between what two numbers must the third side fall?

47. Section 5 ~ 300 Points Answer 35 and 101 Back

48. Section 5 ~ 400 Points If two sides of a triangle are 5 and 63, between what two numbers must the third side fall?

49. Section 5 ~ 400 Points 58 And 68 Answer Back

50. Section 5 ~ 500 Points Is it possible to have a triangle with the given vertices A(1, 4), B(5, -1), and C(1, -4)?