Right Triangle Trigonometry

1. Right Triangle Trigonometry Pre-Calculus Monday, April 20

2. Today’s Objective Review right triangle trigonometry from Geometry and expand it to all the trigonometric functions Begin learning some of the Trigonometric identities

3. What You Should Learn • Evaluate trigonometric functions of acute angles. • Use fundamental trigonometric identities. • Use a calculator to evaluate trigonometricfunctions. • Use trigonometric functions to model and solvereal-life problems.

4. Plan • Questions from last week? • Notes! • Guided Practice • Homework

5. Right Triangle Trigonometry Trigonometry is based upon ratios of the sides of right triangles. The ratio of sides in triangles with the same angles is consistent. The size of the triangle does not matter because the triangles are similar (same shape different size).

6. θ The six trigonometric functions of a right triangle, with an acute angle ,are defined by ratios of two sides of the triangle. θ hyp opp The sides of the right triangle are: adj  the side opposite the acute angle θ  the side adjacent to the acute angle , θ  and the hypotenuse of the right triangle.

7. Trigonometric Functions θ adj opp Sin = cos = tan = Csc = sec = cot = hyp adj hyp hyp adj opp adj opp hyp The trigonometric functions are opp adj sine, cosine, tangent, cotangent, secant, and cosecant. θ θ θ θ θ θ Note: sine and cosecant are reciprocals, cosine and secant are reciprocals, and tangent and cotangent are reciprocals.

8. Reciprocal Functions Another way to look at it… sin  = 1/csc csc = 1/sin cos = 1/sec sec = 1/cos tan = 1/cot cot = 1/tan

9. 5  12 Given 2 sides of a right triangle you should be able to find the value of all 6 trigonometric functions. Example:

10. Example: Six Trig Ratios 5 4  3 Sin = sin α = Cos = cos α = Tan = Cot = cot α = tan α = Sec = sec α = Csc = csc α = Calculate the trigonometric functions for  . Calculate the trigonometric functions for . The six trig ratios are θ θ What is the relationship of α and θ? θ θ They are complementary (α = 90 – θ) θ θ

11. Example: Using Trigonometric Identities hyp a Side a is opposite θ and also adjacent to 90○– θ . 90○– θ θ b sin  = and cos(90 ) = . So, sin  = cos (90 ). Note sin  = cos(90 ), for 0 <  < 90 Note that  and 90  are complementary angles. Note : These functions of the complements are called cofunctions.

12. Cofunctions sin  = cos (90  ) cos  = sin (90  ) sin  = cos (π/2  ) cos  = sin(π/2  ) tan  = cot (90  ) cot  = tan (90  ) tan  = cot(π/2  ) cot  = tan(π/2  ) sec  = csc (90  ) csc  = sec (90  ) sec  = csc(π/2  ) csc  = sec(π/2  )

13. Example: Using Trigonometric Identities Trigonometric Identities are trigonometric equations that hold for all values of the variables. We will learn many Trigonometric Identities and use them to simplify and solve problems.

14. hyp opp adj θ adj opp hyp adj Quotient Identities θ Sin = cos = tan = θ θ The same argument can be made for cot… since it is the reciprocal function of tan.

15. Quotient Identities

16. Pythagorean Identities Three additional identities that we will use are those related to the Pythagorean Theorem: Pythagorean Identities sin2  + cos2  = 1 tan2 + 1 = sec2  cot2  + 1 = csc2 

17. Some old geometry favorites… Let’s look at the trigonometric functions of a few familiar triangles…

18. Consider an isosceles right triangle with two sides of length 1. 45 1 45 1 The Pythagorean Theorem implies that the hypotenuse is of length . Geometry of the 45-45-90 Triangle Geometry of the 45-45-90 triangle Remember a2 + b2 = c2

19. Example: Trig Functions for  45 1 sin 45° = = = cos 45° = = = 45 1 tan 45° = = = 1 cot 45° = = = 1 adj opp hyp adj hyp hyp adj sec 45° = = = csc 45° = = = opp adj opp Calculate the trigonometric functions for a 45° angle.

20. Geometry of the 30-60-90 Triangle 2 2 60○ 60○ 2 Use the Pythagorean Theorem to find the length of the altitude, . Geometry of the 30-60-90 triangle Consider an equilateral triangle with each side of length 2. 30○ 30○ The three sides are equal, so the angles are equal; each is 60°. The perpendicular bisector of the base bisects the opposite angle. 1 1

21. Example: Trig Functions for  30 2 1 30 sin 30° = = cos 30° = = tan 30° = = = cot 30° = = = adj opp hyp adj csc 30° = = = 2 sec 30° = = = hyp hyp adj opp adj opp Calculate the trigonometric functions for a 30 angle.

22. Example: Trig Functions for  60 2 60○ 1 sin 60 = = cos 60 = = cot 60 = = = tan 60 = = = adj opp hyp adj sec 60 = = = 2 csc 60 = = = hyp hyp adj opp adj opp Calculate the trigonometric functions for a 60 angle.

23. Some basic trig values

24. IDENTITIES WE HAVE REVIEWED SO FAR…

25. Fundamental Trigonometric Identities for Fundamental Trigonometric Identities Reciprocal Identities sin  = 1/csc cos = 1/sec tan = 1/cotcot = 1/tan sec = 1/cos csc = 1/sin Co function Identities sin  = cos(90  ) cos  = sin(90  ) sin  = cos (π/2  ) cos  = sin(π/2  ) tan  = cot(90  ) cot  = tan(90  ) tan  = cot(π/2  ) cot  = tan(π/2  ) sec  = csc(90  ) csc  = sec(90  ) sec  = csc(π/2  ) csc  = sec(π/2  ) Quotient Identities tan  = sin  /cos  cot  = cos  /sin  Pythagorean Identities sin2  + cos2  = 1 tan2 + 1 = sec2 cot2  + 1 = csc2 

26. Draw a right triangle with an angle  suchthat 4 = sec  = = . 4 hyp θ adj 1 sin  = csc  = = cos  = sec  = = 4 tan  = = cot  = Example: Given 1 Trig Function, Find Other Functions Example: Given sec  = 4, find the values of the other five trigonometric functions of  . Use the Pythagorean Theorem to solve for the third side of the triangle.

27. Using the calculator Function Keys Reciprocal Key Inverse Keys

28. Using Trigonometry to Solve a Right Triangle A surveyor is standing 115 feet from the base of the Washington Monument. The surveyor measures the angle of elevation to the top of the monument as 78.3. How tall is the Washington Monument? Figure 4.33

29. Applications Involving Right Triangles The angle you are given is the angle of elevation, which represents the angle from the horizontal upward to an object. For objects that lie below the horizontal, it is common to use the term angle of depression.

30. Solution where x = 115 and y is the height of the monument. So, the height of the Washington Monument is y = x tan 78.3  115(4.82882)  555 feet.

31. Homework4-2 Practice 1 • 1-17 ODD

32. Tuesday, April 21, 2015 BENCHMARK TOMORROW

33. Kahoot all day long! • Here’s the deal… • You need a PENCIL and PAPER • You will be GRADED for participating so make sure your Kahoot name is your real name • If you get kicked out, you must log back in • If you do not have an ipad/smart phone, you may work in teams of TWO or do your work on a piece of paper and turn that in • THIS IS REQUIRED.

34. Review Exponents and Log • Converting Logs and Exponents • https://play.kahoot.it/#/k/68a4661b-b90b-4987-820e-956c7e5af6bd • Log and Inverses • https://play.kahoot.it/#/k/45a02d91-aa36-485f-ba52-436768d981f7

35. Review Intro to Trig •  Right Triangle Trig and Angle Measures • https://play.kahoot.it/#/k/8858d7ed-b092-46c6-bc5d-b16c044665c0 • Radians, Degrees, Arc Length • https://play.kahoot.it/#/k/63ac7b20-59ce-4fd4-9266-954797b1b39a

36. Wednesday BENCHMARK!

37. Thursday, April 23

38. Do Now – How was the benchmark? What can you improve?

39. Benchmark Data

40. Benchmark Data 1st Period

41. Analysis By Question

42. Analysis By Question

43. Analysis By Question

44. Analysis By Question

45. Analysis By Question

46. Benchmark Data 2nd Period

47. Analysis By Question

48. Analysis By Question

49. Analysis By Question

50. Analysis By Question