1 / 4

Stoichiometry

Stoichiometry. 10 steps to stoich. Write word equation Write formula equation Balance Write given info under it in equation Write what you solving for under it in equation Convert given info into moles Use the mole ratio Convert moles into g, parts, … Calculate answer

thais
Download Presentation

Stoichiometry

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Stoichiometry

  2. 10 steps to stoich • Write word equation • Write formula equation • Balance • Write given info under it in equation • Write what you solving for under it in equation • Convert given info into moles • Use the mole ratio • Convert moles into g, parts, … • Calculate answer • Write answer with correct sig figs and units

  3. If 21.0 g of silver nitrate (169.9) was added to excess calcium chloride (110.98), how many grams of solid silver chloride (143.35) should have formed? What is the other product? Silver nitrate + calcium chloride  silver chloride + calcium nitrate AgNO3 (aq) + CaCl2 (aq)  AgCl (s) + Ca(NO3)2 (aq) 2 2 21.0 g ? g 7 8 6 = 17.7 g AgCl Always 1 mol in step 6 and 8 Numbers come from balanced equation

  4. 2 2 ? g 21.0 g 17.7 g 6.86 g CaCl2 Different do to rounding off only 6.85 g CaCl2 AgNO3 (aq) + CaCl2 (aq)  AgCl (s) + Ca(NO3)2 (aq) North side convert 21.0 g AgNO3 ? g CaCl2 South side convert 17.7 g AgCl  ? g CaCl2

More Related