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q 0. §8-5 Electric potential. Electrostatic field does work for moving charge. --E-field possesses energy. 1.Work done by electrostatic force. Let test charge q 0 moves a b along arbitrary path in the E-field set up by point charge q. The work done by electrostatic force=?.
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q0 §8-5 Electric potential Electrostatic field does work for moving charge --E-field possesses energy 1.Work done by electrostatic force Let test charge q0 moves a b along arbitrary path in the E-field set up by point charge q . The work done by electrostatic force=?
q0 The work depends on only the initial position and final position of qo, and has nothing to do with the path.
When qo moves in the E-field set up by charges’ system q1, q2, qn , ---has nothing to do with path
When qo moves in the E-field set up by charged body, -- the workhas nothing to do with path Conclusion: Electrostatic force is conservative force. 2. Circular theorem of electrostatic field When q0 moves along a closed path L, E-force does work:
、 Circular theorem of electrostatic field Electrostatic field is conservative field. The work done by electrostatic force = the decrease of the electric potential energy 3. Electric potential energy q0 moves in E-field a b, --The E-potential energy when q0 at point a and b.
Z Z The work done by E-force for q0=- increment of E-potential energy. Notes (1) EPa is relative quantity.If we want to decide the magnitude of EPwhen q0 at a point , we must choose zero reference point of E-potential energy. Z--zero E-potential energy point
(3) EPdepends on E-field and ,it belongs the system. The choice of zero E-potential energy point : Choose zero point at when the charge distribution is finite. Choose zero point at the finite distance point when the charge distribution is infinite. (2) EPis scalar. It can be positive, negative or zero.
Z 4. Electric potential --Describe the character of E-field. Definition E-potential difference: Work:
The distance from q to a Take U=0,then the E-potential of a point a : 5.Calculation of E-potential (1) The E-potential of a point chargeq
U r + U r Discussion Ifq>0,U>0 for any point in the space. when r,U U() 0 Ifq<0,U<0 for any point in the space. when r,U U() 0
a ri r1 qi q1 (2)The E-potential of a system The system of point charges:q1,q2,,qn --superposition principle of E-potential
charge element a dq (3)The E-potential of charged body Divide q many ofdq For any dq: For entire charged body :
Integrating for charged body Caution !! This method can be used for the finite distribution charged body.
6. Examples of calculating E-potential [Example 1] Four point charges q1=q2=q3=q4=q is put on the vertexes of a square with edge of a respectively. Calculate (1)The E-potential at point 0. (2)If test charge q0 is moved from to 0, how much work does the E-force do?
(1) (2)
Use the definition of E-potential as the distribution of is known. – definition method Z Integrating for path Calculate the E-potential set up by a charged body Two methods Definition method
Integrating for charged body Use the superposition principle of E-potential--superposition method. superposition method
[Example 2] Calculate the E-potential on the axis of a uniform charged ring. q、 R are known. Solution Method Use the E-field distribution of the ring that was calculated before. The direction: along x axis
q dq Method -- superposition method
If the charged body is a half circle, ? 0 R (2) Discussion (1)
q + + + R r R ) ( + + + + + ) ( [Example 3] Calculate the E-potential distribution of a charged spherical surface Solution Definition method E-field distribution: Zero potential point:
) ( P r q + + + R + + + + + (1) For any point P outside the sphere (2) For any point inside the sphere surface
分段积分 + + + + + R + + q + + + + + P The sphere is equipotential.
) ( ) ( Conclusion
The distribution curve ofE-field: E 1 8 r2 O r R 1 8 r The distribution curve ofE-potential r R O
Integrating for charged body superposition method: It’s very complex!!
Conclusion When the E-field distribution is symmetry and it can be calculated by using Gauss’s Law conveniently, it is simpler to calculate potential by using definition method. When the E-field distribution is not symmetry and it can’t be calculated by using Gauss’s Law conveniently, it is simpler to calculate potential by using superposition method.
[Example 4] Calculate the E-potential distribution of an infinite line with uniform charge(the linear density isλ). Solution Use definition method
Finite distance to the charged line How to choose thezero potential point? Choose any point b as zero potential point When rp<rb, U >0. When rp>rb, U <0.
§8-6 Equipotential surface and Potential gradient 1. Equipotential surface --the potential has the same value at all points on the surface.
Real line-- -line Dash line-- equipotential surface Positive point charge Electric dipole
A parallel plate capacitor + + + + + + + + +
a q0 b The properties of equipotential surfaces No net work is done by the E-field as a charge moves between any two points on the same equipotential surface. Prove: Assume q0 moves along equipotential surface a b, then:
-lines are always normal to equipotential surfaces Assume on an equipotential surface, the field at point P is q0 moves along equipotential surface, q0 P Prove: then:
-line points on the direction of the increase of the potential. a b Assume there are two equipotential surface U a , Ub Prove: then
E2 r2 r1 E1 Uc Ua Ub the density of equipotential surfaces shows the magnitude of E-field. Prove: Assume there is a family of equipotential surfaces Ua、 U b、 Uc、 then:
-line If the distribution of U is known, How can we calculate ? 2. Potential gradient Equipotential surface
C Express that the ’s direction is the direction of U decrease. b a • Special example: uniform field unit positive chargeab, the work done by E-force: q=1
’s component at the direction of ’s component at any direction = the negative magnitude of the rate of U change with distance on that direction. q=1 moves ac , the work done by E-force :
The normal direction of equipotential surface, point on U increasing (2) Any E-field: definition: potential gradient grad U =U grad U U
conclusion a.the magnitude of at any point = themaximumof the rate of U change with distance on that point. the direction of is perpendicular to the equipotential surface at that point and along the the direction of U decreasing. b. In the space that U is constant, U= 0, E = 0 c.E is not sure = 0 in the space of U= 0. U is not sure = 0 in the space of E= 0.
P( ) [Example 1] Calculate the E-field of an electric dipole.
[example 2] calculate the E-field on the axis of the round charged plate using its potential gradient .