1 / 15

F=BIL

F=BIL. Or is it…. F=qvB. Also Determine the direction of the Force! . V. B. Positive Charge is moving. Use: F=qvB Force is going:. V. B. Negative Charge is moving. Use: F=qvB Force is going: Coming out of the page!. B. I. Use: F=BiL Force is going:. F = 1.5x10 -12 N.

thyra
Download Presentation

F=BIL

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. F=BIL Or is it….. F=qvB Also Determine the direction of the Force! 

  2. V B Positive Charge is moving

  3. Use: F=qvB Force is going:

  4. V B Negative Charge is moving

  5. Use: F=qvB Force is going: Coming out of the page!

  6. B I

  7. Use: F=BiL Force is going:

  8. F = 1.5x10-12 N V = 2.0x107 m/s Electron B = ?

  9. Use: F=qvB 1.5 x 10-12= (1.6 x 10-19C) x (2.0x107 m/s) x B B= .46875 T Force is going:

  10. B = .15 T Electron V = 1.5x106 m/s F = ?

  11. You would break your hand trying this one so the charge will not feel any force

  12. What is the acceleration of the proton? Mass of a proton is = 1.67262158 × 10-27 kilograms B = .75 T Proton V = 5.8x106m/s

  13. Use: F=qvB F=ma ma=qvB (1.67262158 × 10-27 kg)x a = (1.6 x 10-19C) x (5.8x106m/s) x .75 T a = 4.167 x 1014 m/s/s Force is going:

  14. 1. What is the acceleration of the electron? B = .75 T 2. What is the radius of curvature? Hint: ac = v2/r Electron V = 4.5x107m/s

  15. Use: F=qvB F=mv2/r mv2/r=qvB (9.11 × 10-31 kg)(4.5x107m/s)2/r= (1.6 x 10-19C) x (4.5x107m/s) x .75 T r = 3.4 x 10-4 m Force is going:

More Related