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Prepared by Dwi Agrina 20110110080

KONTINUITAS. Prepared by Dwi Agrina 20110110080. SOAL Suatu pipa mengalirkan minyak dengan “Specific gravity” S = 0,86 mempunyai diameter berubah lambat laun . Pada penampang dimana diameter pipa sama dengan 20 cm, kecepatan aliran adalah

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Prepared by Dwi Agrina 20110110080

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  1. KONTINUITAS Prepared by Dwi Agrina 20110110080

  2. SOAL Suatupipamengalirkanminyakdengan “Specific gravity” S = 0,86 mempunyai diameter berubahlambat laun. Padapenampangdimana diameter pipasamadengan 20 cm, kecepatanaliranadalah u = 2m/ det . Berapabesarnyakecepatan rata-rata padasuatupenampangdimanadiameternyaadalah 5 cm? Hitung pula besarnyamasa yang mengalirtersebutdalamsatuan kilogram per detik.

  3. Persamaankontinuitas : Q = A1u1 = A2u2 Apabila diameter penampang 1 adalah 20 cm dan diameter penampang 2 adalah 5 cm, maka : U2=U1A1/A2=2m/det*1/4.3,14(0,20)2m2 1/4.3,14(0,50)2m2 U2=32M/DET M=pQ=pUA=1000kg/m3x32m/detx1/4.3,14(0,50)2m2 M=62,83 kg/det

  4. Pipauntukmenyalurkan air menempelpadasebuahdindingrumahsepertiterlihatpadagambarberikut! Perbandinganluaspenampangpipabesardanpipakeciladalah 4 : 1. Posisipipabesaradalah 5 m diatastanahdanpipakecil 1 m diatastanah. Kecepatanaliran air padapipabesaradalah 36 km/jam dengantekanan 9,1 x 105 Pa. Tentukan :a) Kecepatan air padapipakecilb) Selisihtekananpadakeduapipac) Tekananpadapipakecil(ρair = 1000 kg/m3)

  5. PembahasanData :h1 = 5 mh2 = 1 mv1 = 36 km/jam = 10 m/sP1 = 9,1 x 105 PaA1 : A2 = 4 : 1a) Kecepatan air padapipakecilPersamaanKontinuitas :A1v1 = A2v2(4)(10) = (1)(v2)v2 = 40 m/sb) SelisihtekananpadakeduapipaDari Persamaan Bernoulli :P1 + 1/2 ρv12 + ρgh1 = P2 + 1/2 ρv22 + ρgh2P1 − P2 = 1/2 ρ(v22 − v12) + ρg(h2 − h1)P1 − P2 = 1/2(1000)(402 − 102) + (1000)(10)(1 − 5) P1 − P2 = (500)(1500) − 40000 = 750000 − 40000P1 − P2 = 710000 Pa = 7,1 x 105 Pa 1

  6. SOAL Suatucorot (nozzle) dengan diameter awalnya D1 = 8 cm dan diameter akhirnya D2 = 2 cm mengalirkancairansebesar 10 ℓ / det. Turunkansuatupersamaanuntukkecepatanaliransepanjang sumbucorottersebutdenganmengambiljarak x sepanjangsumbudiukurdaripenampangawaldan panjangcorotsamadengan L.

  7. Persamaankontinuitas Q =u A u=Q A A=1/4.3,14D2=1.4.3,14(D1-(D1-D2)/L(X)2=1/4.3,14(0,08-0,06/LX)2 U=0,01/(1/4.3,14(0,08-(0,06/L.X))2=1,273/(0,08-(0,06/L.X)2

  8. Air bersihmengalirdarirumahjonimelaluipipa 1,2,3,4, diameter ppa 1=10mm, pipa 2=45mm,pipa 3=65,mm pipa 4=80mm, kecepatandialiranpipa 2= 4m/s danpipa 3=1,5m/s, dan debit dipipa 3 adalah 2X debit alirandipipa 4,hitunglah Q1, V1, Q2,D3,dan V4

  9. Q2= A2.V2 = ¼.π.0,045².4=0.006358m³/det=6,358l/det Q1=Q2=6,358 l/det A1.V1=6,358 l/det V1=6,358.10ˉ³ ÷ ¼. Π. 0,01² = 0.81 m/s Q2=Q3+Q4 =Q3+ 0,5 Q3 =1,5 Q3

  10. sekian, terimakasih

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